Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
9th Edition
ISBN: 9781319090241
Author: Daniel C. Harris, Sapling Learning
Publisher: W. H. Freeman
Question
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Chapter 24, Problem 24.AE

a)

Interpretation Introduction

Interpretation:

The name of two straight chain hydrocarbons that is responsible for the elution of 2-pentanone has to be identified.

Concept Introduction:

Kovats retention index:

Retention index, I for linear alkane equals 100 times the number of Carbon atoms.

For a molecule of Octane, I=800

For a molecule of Nonane, I=900

The elution of compound between Octane and Nonane will have retention index between 800 and 900 is calculated using the formula,

I=100[n+(N-n)logtr'(unknown)-logtr'(n)logtr'(N)-logtr'(n)]

Where, n = number of Carbon atoms in smaller alkane

N = number of Carbon atoms in larger alkane

tr'(n) = adjusted retention time of smaller alkane

tr'(N) = adjusted retention time of larger alkane

To give the name of two straight chain hydrocarbons that is responsible for the elution of 2-pentanone

a)

Expert Solution
Check Mark

Answer to Problem 24.AE

The elution of 2-pentanone takes place between Nonane and Decane, but very close elution takes places through Decane.

Explanation of Solution

The retention index of the compounds is based on the overall polarity phases and the selectivity that depends on the types of polar interaction offered by each column. For poly (ethylene glycol) column, the elution of 2-pentanone takes place between Nonane and Decane, but very close elution takes places through Decane.

b)

Interpretation Introduction

Interpretation:

The retention time of the compound has to be calculated.

Concept Introduction:

Kovats retention index:

Retention index, I for linear alkane equals 100 times the number of Carbon atoms.

For a molecule of Octane, I=800

For a molecule of Nonane, I=900

The elution of compound between Octane and Nonane will have retention index between 800 and 900 is calculated using the formula,

I=100[n+(N-n)logtr'(unknown)-logtr'(n)logtr'(N)-logtr'(n)]

Where, n = number of Carbon atoms in smaller alkane

N = number of Carbon atoms in larger alkane

tr'(n) = adjusted retention time of smaller alkane

tr'(N) = adjusted retention time of larger alkane

To calculate the retention time of the unknown compound

b)

Expert Solution
Check Mark

Answer to Problem 24.AE

The retention time of the compound is 16.40min .

Explanation of Solution

Given,

tr'ofC10=13.83tr'ofC11=15.42tm=1.80min

The adjusted retention time of tr'(unknown) is calculated as,

1050=100[10+(11-10)logtr'(unknown)-log13.83log15.42-log13.83]tr'(unknown)=14.60min

The adjusted retention time of unknown along with tm gives the retention time of the compound.

tr=tr'ofunknown+tmtr=14.60+1.80tr=16.40min

The retention time of the compound= 16.40min

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