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Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Question
Chapter 24, Problem 18RQ
To determine
The basic principle of a universal dividing head.
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Please can you help with ten attatched question?
An AISI 1018 steel ball with 1.100-in diameter is used as a roller between a flat plate
made from 2024 T3 aluminum and a flat table surface made from ASTM No. 30 gray
cast iron. Determine the maximum amount of weight that can be stacked on the
aluminum plate without exceeding a maximum shear stress of 19.00 kpsi in any of the
three pieces. Assume the figure given below, which is based on a typical Poisson's
ratio of 0.3, is applicable to estimate the depth at which the maximum shear stress
occurs for these materials.
1.0
0.8
Ratio of stress to Pmax
0.4
90
0.6
στ
Tmax
0.2
0.5a
a
1.5a
2a
2.5a
За
Distance from contact surface
The maximum amount of weight that can be stacked on the aluminum plate is
lbf.
A carbon steel ball with 27.00-mm diameter is pressed together with an aluminum ball
with a 36.00-mm diameter by a force of 11.00 N. Determine the maximum shear
stress and the depth at which it will occur for the aluminum ball. Assume the figure
given below, which is based on a typical Poisson's ratio of 0.3, is applicable to estimate
the depth at which the maximum shear stress occurs for these materials.
1.0
0.8
Ratio of stress to Pma
9 0.6
στ
24
0.4
Tmax
0.2
0
0.5a
a
1.5a
Z
2a
2.5a
За
Distance from contact surface
The maximum shear stress is determined to be
MPa.
The depth in the aluminum ball at which the maximum shear stress will occur is
determined to be [
mm.
Chapter 24 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 24 - Suppose that you wanted to machine cast iron with...Ch. 24 - How is the feed per tooth related to the feed rate...Ch. 24 - Why must the number of teeth on the cutter be...Ch. 24 - Why is the question of up or down milling more...Ch. 24 - For producing flat surfaces in mass-production...Ch. 24 - Milling has a higher metal removal rate than...Ch. 24 - Which type of milling (up or down) is being done...Ch. 24 - Why does down milling dull the cutter more rapidly...Ch. 24 - What parameters do you need to specify in order to...Ch. 24 - In Figure 24.2b, the tool material is carbide....
Ch. 24 - What is the advantage of a helical-tooth cutter...Ch. 24 - What would the cutting force diagram for Fc look...Ch. 24 - Could the stub arbor-mounted face mill shown in...Ch. 24 - In a typical solid arbor milling cutter shown in...Ch. 24 - Make some sketches to show how you would you set...Ch. 24 - Make some sketches to show how you would set up a...Ch. 24 - Explain how controlled movements of the work m...Ch. 24 - Prob. 18RQCh. 24 - What is the purpose of the hole-circle plate on a...Ch. 24 - You have selected a feed per tooth and a cutting...Ch. 24 - How much time will be required for a milling...Ch. 24 - If the depth of cut is 0.35 in., what is the metal...Ch. 24 - Prob. 4PCh. 24 - Calculate the spindle rpm and table feed (ipm) for...Ch. 24 - A gray cast iron surface 6 in. wide and 18 in....Ch. 24 - Prob. 7PCh. 24 - In Figure 24.12, the feed is 0.006 in. per tooth....Ch. 24 - Suppose you want to do the job described in...Ch. 24 - The Bridgeport vertical-spindle milling machine is...Ch. 24 - The KC Machine Works, which does job shop...
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