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(a)
Interpretation:
The structure of complex pentamminenitrito-N-cobalt(III)ion needs to be drawn.
Concept introduction:
The structure of chelate complex is formed in such a way that the ligands are linked through covalent bonds wherein the metal ion is at the centre with ligands on either side of the metal ion.
The structures gets arranged to give a square planar, octahedral or tetrahedral sturcutre. Structures gets arranged to form a stable or symmetrical geometry.
(b)
Interpretation:
The structure of chelate complex ethylenediaminedithiocyanato-S-copper(II) needs to be drawn.
Concept introduction:
Structure of chelates are formed in such a way that multidentate ligands uses more that one atom to bind to a metal ion wherein the ligands are attached to the central atom. It is mostly in the form of rings or have square planar and tetrahedral structures. The geometry needs to be stable and hence, the molecules undergo rearrangement.
(c)
Interpretation:
The structure of hexaaquanickel(II) ion needs to be drawn.
Concept introduction:
Chelate indicates those structure which are cyclic in nature and metal ions unite with organic or inorganic molecules. The presence of mulitdentate ligands uses more atoms to bind to metal ion where ligands get attached to the central atom. The structure is mostly in the form of rings. The structure is
either square planar or tetrahedral. The geometry needs to be stable for which the molecules undergo rearrangement.
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Chapter 24 Solutions
EBK GENERAL CHEMISTRY
- 93 = Volume 93 = 5.32× 10 3 -23 ст a √ 1073 5.32× 10 3 cm³arrow_forwardASP.....arrow_forwardQuestion 7 (10 points) Identify the carboxylic acid present in each of the following items and draw their structures: Food Vinegar Oranges Yogurt Sour Milk Pickles Acid Structure Paragraph ✓ BI UAE 0118 + v Task: 1. Identify the carboxylic acid 2. Provide Name 3. Draw structure 4. Take a picture of your table and insert Add a File Record Audio Record Video 11.arrow_forward
- Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 IZ IN Molecule 4 Molecule 5 ZI none of the above ☐ Molecule 3 Х IN www Molecule 6 NH Garrow_forwardHighlight each chiral center in the following molecule. If there are none, then check the box under the drawing area. There are no chiral centers. Cl Cl Highlightarrow_forwardA student proposes the following two-step synthesis of an ether from an alcohol A: 1. strong base A 2. R Is the student's proposed synthesis likely to work? If you said the proposed synthesis would work, enter the chemical formula or common abbreviation for an appropriate strong base to use in Step 1: If you said the synthesis would work, draw the structure of an alcohol A, and the structure of the additional reagent R needed in Step 2, in the drawing area below. If there's more than one reasonable choice for a good reaction yield, you can draw any of them. ☐ Click and drag to start drawing a structure. Yes No ロ→ロ 0|0 G Х D : ☐ பarrow_forward
- टे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.arrow_forwardShown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1arrow_forwardPredict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.arrow_forward
- NG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardShow work...don't give Ai generated solutionarrow_forward
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