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(a)
Interpretation: For a given compound set of compounds, the given
Concept Introduction: An azide synthesis involves the reaction between
Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions.
Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.
Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.
(b)
Interpretation: For a given compound set of compounds, the given amines are to be prepared via an azide synthesis, reductive amination starting from sodium azide
Concept Introduction: An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed in the first step. Alkyl azide on reduction with hydrogen in the presence of platinum produces primary amine. In this way, primary amines are synthesized while secondary and tertiary amines are not formed as by-products.
Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.
Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.
Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.
(c)
Interpretation: For a given compound set of compounds, the given amines are to be prepared via an azide synthesis, reductive amination starting from sodium azide
Concept Introduction: An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed in the first step. Alkyl azide on reduction with hydrogen in the presence of platinum produces primary amine. In this way, primary amines are synthesized while secondary and tertiary amines are not formed as by-products.
Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.
Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.
Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.
(d)
Interpretation: For a given compound set of compounds, the given amines are to be prepared via an azide synthesis, reductive amination starting from sodium azide
Concept Introduction: An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed in the first step. Alkyl azide on reduction with hydrogen in the presence of platinum produces primary amine. In this way, primary amines are synthesized while secondary and tertiary amines are not formed as by-products.
Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.
Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.
Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.
(e)
Interpretation: For a given compound set of compounds, the given amines are to be prepared via an azide synthesis, reductive amination starting from sodium azide
Concept Introduction: An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed in the first step. Alkyl azide on reduction with hydrogen in the presence of platinum produces primary amine. In this way, primary amines are synthesized while secondary and tertiary amines are not formed as by-products.
Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.
Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.
Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.
(f)
Interpretation: For a given compound set of compounds, the given amines are to be prepared via an azide synthesis, reductive amination starting from sodium azide
Concept Introduction: An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed in the first step. Alkyl azide on reduction with hydrogen in the presence of platinum produces primary amine. In this way, primary amines are synthesized while secondary and tertiary amines are not formed as by-products.
Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.
Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.
Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.
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Chapter 23 Solutions
Organic Chemistry
- Identify the missing organic reactants in the following reaction: X + Y H+ two steps Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. Х :arrow_forwardDraw the mechanism of friedel-crafts acylation using acetyl chloride of m-Xylenearrow_forwardI need help naming these in IUPACarrow_forward
- H R Part: 1/2 :CI: is a/an electrophile Part 2 of 2 Draw the skeletal structure of the product(s) for the Lewis acid-base reaction. Include lone pairs and formal charges (if applicable) on the structures. 4-7: H ö- H Skip Part Check X :C1: $ % L Fi Click and drag to start drawing a structure. MacBook Pro & ㅁ x G 0: P Add or increase positive formal cha Save For Later Submit ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centearrow_forwardDraw the friedel-crafts acylation mechanism of m-Xylenearrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- 1. Base on this experimental results, how do you know that the product which you are turning in is methyl 3-nitrobenzoate(meta substituted product ) rather than either of the other two products? 2. What observation suggests that at least a small amount of one or both of the other two isomers are in the mother liquor?arrow_forwardExplain Huckel's rule.arrow_forwardhere is my question can u help me please!arrow_forward
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