Organic Chemistry
Organic Chemistry
2nd Edition
ISBN: 9781118452288
Author: David R. Klein
Publisher: WILEY
Question
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Chapter 23.6, Problem 14PTS

(a)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  1

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  2

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  3

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(b)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  4

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  5

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  6

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(c)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  7

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  8

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  9

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(d)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  10

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  11

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  12

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(e)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  13

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  14

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

Organic Chemistry, Chapter 23.6, Problem 14PTS , additional homework tip  15

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

Blurred answer

Chapter 23 Solutions

Organic Chemistry

Ch. 23.4 - Prob. 10CCCh. 23.4 - Prob. 11CCCh. 23.5 - Prob. 2LTSCh. 23.5 - Prob. 12PTSCh. 23.5 - Prob. 13PTSCh. 23.6 - Prob. 3LTSCh. 23.6 - Prob. 14PTSCh. 23.6 - Prob. 15ATSCh. 23.6 - Prob. 16ATSCh. 23.6 - Prob. 17ATSCh. 23.7 - Prob. 18PTSCh. 23.7 - Prob. 19PTSCh. 23.7 - Prob. 20PTSCh. 23.7 - Prob. 21ATSCh. 23.8 - Prob. 22CCCh. 23.8 - Prob. 23CCCh. 23.8 - Prob. 24CCCh. 23.9 - Prob. 5LTSCh. 23.9 - Prob. 25PTSCh. 23.9 - Prob. 26ATSCh. 23.9 - Prob. 27ATSCh. 23.9 - Prob. 28ATSCh. 23.10 - Prob. 29CCCh. 23.11 - Prob. 30CCCh. 23.11 - Prob. 6LTSCh. 23.11 - Prob. 31PTSCh. 23.11 - Prob. 32ATSCh. 23.11 - Prob. 33ATSCh. 23.12 - Prob. 34CCCh. 23.12 - Prob. 35CCCh. 23.13 - Prob. 36CCCh. 23.13 - Prob. 37CCCh. 23 - Prob. 38PPCh. 23 - Prob. 39PPCh. 23 - Prob. 40PPCh. 23 - Prob. 41PPCh. 23 - Prob. 42PPCh. 23 - Prob. 43PPCh. 23 - Prob. 44PPCh. 23 - Prob. 45PPCh. 23 - Prob. 46PPCh. 23 - Prob. 47PPCh. 23 - Prob. 48PPCh. 23 - Prob. 49PPCh. 23 - Prob. 50PPCh. 23 - Prob. 51PPCh. 23 - Prob. 52PPCh. 23 - Prob. 53PPCh. 23 - Prob. 54PPCh. 23 - Prob. 55PPCh. 23 - Prob. 56PPCh. 23 - Prob. 57PPCh. 23 - Prob. 58PPCh. 23 - Prob. 59PPCh. 23 - Prob. 60PPCh. 23 - Prob. 61PPCh. 23 - Prob. 62PPCh. 23 - Prob. 63PPCh. 23 - Prob. 64PPCh. 23 - Prob. 65PPCh. 23 - Prob. 66PPCh. 23 - Prob. 67PPCh. 23 - Prob. 68PPCh. 23 - Prob. 69PPCh. 23 - Prob. 70PPCh. 23 - Prob. 71PPCh. 23 - Prob. 72PPCh. 23 - Prob. 73PPCh. 23 - Prob. 74PPCh. 23 - Prob. 75PPCh. 23 - Prob. 76PPCh. 23 - Prob. 77IPCh. 23 - Prob. 78IPCh. 23 - Prob. 79IPCh. 23 - Prob. 80IPCh. 23 - Prob. 81IPCh. 23 - Prob. 82IPCh. 23 - Prob. 83IPCh. 23 - Prob. 84IPCh. 23 - Prob. 85IPCh. 23 - Prob. 86IPCh. 23 - Prob. 87IPCh. 23 - Prob. 88IPCh. 23 - Prob. 89IPCh. 23 - Prob. 90IPCh. 23 - Prob. 91CPCh. 23 - Prob. 92CPCh. 23 - Prob. 93CPCh. 23 - Prob. 94CPCh. 23 - Prob. 95CPCh. 23 - Prob. 96CPCh. 23 - Prob. 97CPCh. 23 - Prob. 98CP
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