Study Guide with Student Solutions Manual for McMurry's Organic Chemistry, 9th
9th Edition
ISBN: 9781305082144
Author: John E. McMurry
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 23.7, Problem 11P
Show the products you would expect to obtain by Claisen condensation following esters:
(a) [CH3]2CHCt2CC2Et
(b) Ethyl phenylacetate
(c) Ethyl cyclohexylacetate
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 23 Solutions
Study Guide with Student Solutions Manual for McMurry's Organic Chemistry, 9th
Ch. 23.1 - Prob. 1PCh. 23.1 - Prob. 2PCh. 23.3 - Prob. 3PCh. 23.3 - Prob. 4PCh. 23.4 - Prob. 5PCh. 23.4 - 1-Butanol is prepared commercially by a route that...Ch. 23.4 - Prob. 7PCh. 23.5 - Prob. 8PCh. 23.6 - Prob. 9PCh. 23.6 - What product would you Expect to obtain from base...
Ch. 23.7 - Show the products you would expect to obtain by...Ch. 23.7 - Prob. 12PCh. 23.8 - What product would you expect from the following...Ch. 23.9 - What product would you expect From the following...Ch. 23.9 - Prob. 15PCh. 23.10 - Prob. 16PCh. 23.10 - Prob. 17PCh. 23.10 - Prob. 18PCh. 23.11 - Prob. 19PCh. 23.11 - Show how you might use an enamine reaction to...Ch. 23.12 - Prob. 21PCh. 23.12 - How would you prepare the following compound using...Ch. 23.SE - Prob. 23VCCh. 23.SE - Prob. 24VCCh. 23.SE - Prob. 25VCCh. 23.SE - The following molecule was formed by a Robinson...Ch. 23.SE - Prob. 27MPCh. 23.SE - Prob. 28MPCh. 23.SE - Predict the product(s) and provide the mechanism...Ch. 23.SE - Predict the product(s) and provide the mechanism...Ch. 23.SE - Predict the product(s) and provide the mechanism...Ch. 23.SE - Knoevenagel condensation is a reaction involving...Ch. 23.SE - Azlactones are important starting materials used...Ch. 23.SE - Prob. 34MPCh. 23.SE - Isoleucine, another of the twenty amino acids...Ch. 23.SE - The first step in the citric acid cycle of food...Ch. 23.SE - Prob. 37MPCh. 23.SE - The Knoevenagel reaction is a carbonyl...Ch. 23.SE - The Darzens reaction invoIves a two-step,...Ch. 23.SE - The following reaction involves a hydrolysis...Ch. 23.SE - Prob. 41MPCh. 23.SE - Prob. 42MPCh. 23.SE - Prob. 43MPCh. 23.SE - Propose a mechanism for the following...Ch. 23.SE - Prob. 45MPCh. 23.SE - Prob. 46MPCh. 23.SE - Prob. 47MPCh. 23.SE - Prob. 48APCh. 23.SE - Prob. 49APCh. 23.SE - Prob. 50APCh. 23.SE - Prob. 51APCh. 23.SE - Prob. 52APCh. 23.SE - Prob. 53APCh. 23.SE - Prob. 54APCh. 23.SE - Prob. 55APCh. 23.SE - Prob. 56APCh. 23.SE - Prob. 57APCh. 23.SE - Prob. 58APCh. 23.SE - In the mixed Claisen reaction of cyclopentanone...Ch. 23.SE - Ethyl dimethylacetoacetate reacts instantly at...Ch. 23.SE - Prob. 61APCh. 23.SE - Prob. 62APCh. 23.SE - The so-called Wieland-Miescher ketone is a...Ch. 23.SE - Prob. 64APCh. 23.SE - Prob. 65APCh. 23.SE - Prob. 66APCh. 23.SE - What condensation products would you expect to...Ch. 23.SE - The following reactions are unlikely to provide...Ch. 23.SE - Fill in the missing reagents a-h in the following...Ch. 23.SE - Prob. 70APCh. 23.SE - Prob. 71APCh. 23.SE - Prob. 72APCh. 23.SE - Prob. 73AP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Please correct answer and don't used hand raitingarrow_forwardneed help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardCan you tell me if my answers are correctarrow_forwardBunsenite (NiO) crystallizes like common salt (NaCl), with a lattice parameter a = 4.177 Å. A sample of this mineral that has Schottky defects that are not supposed to decrease the volume of the material has a density of 6.67 g/cm3. What percentage of NiO molecules is missing? (Data: atomic weight of Ni: 58.7; atomic weight of O: 16).arrow_forward
- A sample of aluminum (face-centered cubic - FCC) has a density of 2.695 mg/m3 and a lattice parameter of 4.04958 Å. Calculate the fraction of vacancies in the structure. (Atomic weight of aluminum: 26.981).arrow_forwardPlease correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardWhich of the following species is a valid resonance structure of A? Use curved arrows to show how A is converted to any valid resonance structure. When a compound is not a valid resonance structurc of A, explain why not. Provide steps and tips on what to look for to understand how to solve and apply to other problems.arrow_forwardN IZ Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 HN Molecule 3 Х HN www. Molecule 4 Molecule 5 Molecule 6 none of the above NH NH Garrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Coenzymes and cofactors; Author: CH15 SWAYAM Prabha IIT Madras;https://www.youtube.com/watch?v=bubY2Nm7hVM;License: Standard YouTube License, CC-BY
Aromaticity and Huckel's Rule; Author: Professor Dave Explains;https://www.youtube.com/watch?v=7-BguH4_WBQ;License: Standard Youtube License