
Concept explainers
(a)
Interpretation:
The structure of given monosaccharide using chair conformations is to be drawn.
Concept introduction:
The sugars that do not undergo hydrolysis to form simpler compounds are known as monosaccharides.
Pyranose are those saccharides that consist of a six membered ring in which five carbon atoms and one oxygen atom is present.
(b)
Interpretation:
The structure of given monosaccharide using chair conformations is to be drawn.
Concept introduction:
The sugars that do not undergo hydrolysis to form simpler compounds are known as monosaccharides.
Pyranose are those saccharides that consist of a six membered ring in which five carbon atoms and one oxygen atom is present.
(c)
Interpretation:
The structure of given monosaccharide using chair conformations is to be drawn.
Concept introduction:
The sugars that do not undergo hydrolysis to form simpler compounds are known as monosaccharides.
Pyranose are those saccharides that consist of a six membered ring in which five carbon atoms and one oxygen atom is present.
(d)
Interpretation:
The structure of given monosaccharide using Haworth projections is to be drawn.
Concept introduction:
The sugars that do not undergo hydrolysis to form simpler compounds are known as monosaccharides.
Furanose is those saccharides that consist of a five membered ring in which four carbon atoms and one oxygen atom is present.
(e)
Interpretation:
The structure of given monosaccharide using Haworth projections is to be drawn.
Concept introduction:
The sugars that do not undergo hydrolysis to form simpler compounds are known as monosaccharides.
Furanose is those saccharides that consist of a five membered ring in which four carbon atoms and one oxygen atom is present.

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Chapter 23 Solutions
ORGANIC CHEMISTRY
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- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
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