(a)
To determine: The name of the given aldose.
Interpretation: The name of the given aldose is to be stated.
Concept introduction: The two diastereomeric sugars which differ only in the configuration at a single asymmetric carbon atom are known as epimers. Aldose is a monosaccharide which contains an
(b)
To determine: The name of the given aldose.
Interpretation: The name of the given aldose is to be stated.
Concept introduction: The two diastereomeric sugars which differ only in the configuration at a single asymmetric carbon atom are known as epimers. Aldose is a monosaccharide which contains an aldehyde carbonyl group.
(c)
To determine: The name of the given aldose.
Interpretation: The name of the given aldose is to be stated.
Concept introduction: The two diastereomeric sugars which differ only in the configuration at a single asymmetric carbon atom are known as epimers. Aldose is a monosaccharide which contains an aldehyde carbonyl group.
(d)
To determine: The name of the given aldose.
Interpretation: The name of the given aldose is to be stated.
Concept introduction: The two diastereomeric sugars which differ only in the configuration at a single asymmetric carbon atom are known as epimers. Aldose is a monosaccharide which contains an aldehyde carbonyl group.
(e)
To determine: The name of the given aldose.
Interpretation: The name of the given aldose is to be stated.
Concept introduction: The two diastereomeric sugars which differ only in the configuration at a single asymmetric carbon atom are known as epimers. Aldose is a monosaccharide which contains an aldehyde carbonyl group.
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Chapter 23 Solutions
ORGANIC CHEMISTRY
- The decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forwardDon't used hand raitingarrow_forwardCS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?arrow_forward
- CS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.arrow_forwardThe following is a first order reaction where the rate constant, k, is 6.29 x 10-3 min-*** What is the half-life? C2H4 C2H2 + H2arrow_forwardControl Chart Drawing Assignment The table below provides the number of alignment errors observed during the final inspection of a certain model of airplane. Calculate the central, upper, and lower control limits for the c-chart and draw the chart precisely on the graph sheet provided (based on 3-sigma limits). Your chart should include a line for each of the control limits (UCL, CL, and LCL) and the points for each observation. Number the x-axis 1 through 25 and evenly space the numbering for the y-axis. Connect the points by drawing a line as well. Label each line drawn. Airplane Number Number of alignment errors 201 7 202 6 203 6 204 7 205 4 206 7 207 8 208 12 209 9 210 9 211 8 212 5 213 5 214 9 215 8 216 15 217 6 218 4 219 13 220 7 221 8 222 15 223 6 224 6 225 10arrow_forward
- Collagen is used to date artifacts. It has a rate constant = 1.20 x 10-4 /years. What is the half life of collagen?arrow_forwardיווי 10 20 30 40 50 60 70 3.5 3 2.5 2 1.5 1 [ppm] 3.5 3 2.5 2 1.5 1 6 [ppm] 1 1.5 -2.5 3.5arrow_forward2H2S(g)+3O2(g)→2SO2(g)+2H2O(g) A 1.2mol sample of H2S(g) is combined with excess O2(g), and the reaction goes to completion. Question Which of the following predicts the theoretical yield of SO2(g) from the reaction? Responses 1.2 g Answer A: 1.2 grams A 41 g Answer B: 41 grams B 77 g Answer C: 77 grams C 154 g Answer D: 154 grams Darrow_forward
- Part VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 f1 (ppm) Predicted 13C NMR Spectrum 100 f1 (ppm) 30 220 210 200 190 180 170 160 150 140 130 120 110 90 80 70 -26 60 50 40 46 30 20 115 10 1.0 0.9 0.8 0 -10arrow_forwardQ: Arrange BCC and Fec metals, in sequence from the Fable (Dr. R's slides) and Calculate Volume and Density. Aa BCC V 52 5 SFCCarrow_forwardNonearrow_forward
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