a. Answer Explanation Given information: The numbers of confirmed cases of Lyme disease in Maine from 2003 to 2010 are shown in the table, where t represents the year, with t = 3 corresponding to 2003 . Use a graphing utility to create a scatter plot of the data Calculation: Consider the given table, Using a graphing utility to create a scatter plot. Hence, the solution is plot. b. To determine Find a quadratic model for the data. Answer f ( x ) = − 7.51190 t 2 + 184.65476 t − 387.94048 Explanation Given information: The numbers of confirmed cases of Lyme disease in Maine from 2003 to 2010 are shown in the table, where t represents the year, with t = 3 corresponding to 2003 . Use the regression feature of the graphing utility to find a quadratic model for the data. Graph the model in the same viewing window as the scatter plot. Calculation: Use the regression feature of the graphing utility to find a quadratic model for the data f ( x ) = − 7.51190 t 2 + 184.65476 t − 387.94048 Using a graphing utility to create a scatter plot. Hence, the solution is plot and f ( x ) = − 7.51190 t 2 + 184.65476 t − 387.94048 c. To determine Compare the model with the original data. Answer There is lot of variance between the model and original data. Explanation Given information: The numbers of confirmed cases of Lyme disease in Maine from 2003 to 2010 are shown in the table, where t represents the year, with t = 3 corresponding to 2003 . Use the model to create a table of estimated values of N Compare the model with the original data. Calculation: The model to create a table of estimated values of N . y e a r t 3 4 5 6 7 8 9 10 n u m b e r N 98 230 348 450 537 609 665 707 From the table it is clear that there is lot of variance between the model and original data. Hence, the solution is shown in table. d. To determine Use synthetic division to confirm algebraically your estimated value for the year 2010 . Answer 662 Explanation Given information: The numbers of confirmed cases of Lyme disease in Maine from 2003 to 2010 are shown in the table, where t represents the year, with t = 3 corresponding to 2003 . Use synthetic division to confirm algebraically your estimated value for the year 2010 . Calculation: Use synthetic division , t = 10 10 − 8 185 − 388 − 80 1050 − 8 105 662 662 is very close to the estimated value 707 . Hence, the solution is 662 .

3rd Edition

ISBN: 9781285607160

Author: Larson

Publisher: CENGAGE CO

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Question

Chapter 2.3, Problem 86E

To determine

Use a graphing utility to create a scatter plot of the data.

Expert Solution

Answer to Problem 86E

EBK PRECALCULUS W/LIMITS, Chapter 2.3, Problem 86E , additional homework tip 1

Explanation of Solution

Given information:

The numbers of confirmed cases of Lyme disease in Maine from 2003 to 2010 are shown in the table, where t represents the year, with t=3 corresponding to 2003 .

EBK PRECALCULUS W/LIMITS, Chapter 2.3, Problem 86E , additional homework tip 2

Use a graphing utility to create a scatter plot of the data

Calculation:

Consider the given table,

Using a graphing utility to create a scatter plot.

EBK PRECALCULUS W/LIMITS, Chapter 2.3, Problem 86E , additional homework tip 4

Hence, the solution is plot.

To determine

Find a quadratic model for the data.

Expert Solution

Answer to Problem 86E

f(x)=−7.51190t2+184.65476t−387.94048

Explanation of Solution

Given information:

The numbers of confirmed cases of Lyme disease in Maine from 2003 to 2010 are shown in the table, where t represents the year, with t=3 corresponding to 2003 .

EBK PRECALCULUS W/LIMITS, Chapter 2.3, Problem 86E , additional homework tip 5

Use the regression feature of the graphing utility to find a quadratic model for the data. Graph the model in the same viewing window as the scatter plot.

Calculation:

Use the regression feature of the graphing utility to find a quadratic model for the data

f(x)=−7.51190t2+184.65476t−387.94048

Using a graphing utility to create a scatter plot.

EBK PRECALCULUS W/LIMITS, Chapter 2.3, Problem 86E , additional homework tip 7

Hence, the solution is plot and f(x)=−7.51190t2+184.65476t−387.94048

To determine

Compare the model with the original data.

Expert Solution

Answer to Problem 86E

There is lot of variance between the model and original data.

Explanation of Solution

Given information:

The numbers of confirmed cases of Lyme disease in Maine from 2003 to 2010 are shown in the table, where t represents the year, with t=3 corresponding to 2003 .

EBK PRECALCULUS W/LIMITS, Chapter 2.3, Problem 86E , additional homework tip 8

Use the model to create a table of estimated values of N Compare the model with the original data.

Calculation:

The model to create a table of estimated values of N .

yeart345678910numberN98230348450537609665707

From the table it is clear that there is lot of variance between the model and original data.

Hence, the solution is shown in table.

To determine

Use synthetic division to confirm algebraically your estimated value for the year 2010 .

Expert Solution

Answer to Problem 86E

662

Explanation of Solution

Given information:

The numbers of confirmed cases of Lyme disease in Maine from 2003 to 2010 are shown in the table, where t represents the year, with t=3 corresponding to 2003 .

EBK PRECALCULUS W/LIMITS, Chapter 2.3, Problem 86E , additional homework tip 10

Use synthetic division to confirm algebraically your estimated value for the year 2010 .

Calculation:

Use synthetic division , t=10

10−8185−388−801050−8105662

662 is very close to the estimated value 707 .

Hence, the solution is 662 .

Chapter 2.3, Problem 85E

Chapter 2.3, Problem 87E

Chapter 2 Solutions

EBK PRECALCULUS W/LIMITS

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Prob. 104E Ch. 2.5 - Prob. 105E Ch. 2.5 - Prob. 106E Ch. 2.5 - Prob. 107E Ch. 2.5 - Prob. 108E Ch. 2.5 - Prob. 109E Ch. 2.5 - Prob. 110E Ch. 2.5 - Prob. 111E Ch. 2.5 - Prob. 112E Ch. 2.5 - Prob. 113E Ch. 2.5 - Prob. 114E Ch. 2.5 - Prob. 115E Ch. 2.5 - Prob. 116E Ch. 2.5 - Prob. 117E Ch. 2.5 - Prob. 118E Ch. 2.5 - Prob. 119E Ch. 2.5 - Prob. 120E Ch. 2.5 - Prob. 121E Ch. 2.5 - Prob. 122E Ch. 2.5 - Prob. 123E Ch. 2.5 - Prob. 124E Ch. 2.5 - Prob. 125E Ch. 2.5 - Prob. 126E Ch. 2.5 - Prob. 127E Ch. 2.5 - Prob. 128E Ch. 2.5 - Prob. 129E Ch. 2.5 - Prob. 130E Ch. 2.5 - Prob. 131E Ch. 2.6 - Prob. 1E Ch. 2.6 - Prob. 2E Ch. 2.6 - Prob. 3E Ch. 2.6 - Prob. 4E Ch. 2.6 - Prob. 5E Ch. 2.6 - Prob. 6E Ch. 2.6 - Prob. 7E Ch. 2.6 - Prob. 8E Ch. 2.6 - Prob. 9E Ch. 2.6 - Prob. 10E Ch. 2.6 - Prob. 11E Ch. 2.6 - Prob. 12E Ch. 2.6 - Prob. 13E Ch. 2.6 - Prob. 14E Ch. 2.6 - Prob. 15E Ch. 2.6 - Prob. 16E Ch. 2.6 - Prob. 17E Ch. 2.6 - Prob. 18E Ch. 2.6 - Prob. 19E Ch. 2.6 - Prob. 20E Ch. 2.6 - Prob. 21E Ch. 2.6 - Prob. 22E Ch. 2.6 - Prob. 23E Ch. 2.6 - Prob. 24E Ch. 2.6 - Prob. 25E Ch. 2.6 - Prob. 26E Ch. 2.6 - Prob. 27E Ch. 2.6 - Prob. 28E Ch. 2.6 - Prob. 29E Ch. 2.6 - Prob. 30E Ch. 2.6 - Prob. 31E Ch. 2.6 - Prob. 32E Ch. 2.6 - Prob. 33E Ch. 2.6 - Prob. 34E Ch. 2.6 - Prob. 35E Ch. 2.6 - Prob. 36E Ch. 2.6 - Prob. 37E Ch. 2.6 - Prob. 38E Ch. 2.6 - Prob. 39E Ch. 2.6 - Prob. 40E Ch. 2.6 - Prob. 41E Ch. 2.6 - Prob. 42E Ch. 2.6 - Prob. 43E Ch. 2.6 - Prob. 44E Ch. 2.6 - Prob. 45E Ch. 2.6 - Prob. 46E Ch. 2.6 - Prob. 47E Ch. 2.6 - Prob. 48E Ch. 2.6 - Prob. 49E Ch. 2.6 - Prob. 50E Ch. 2.6 - Prob. 51E Ch. 2.6 - Prob. 52E Ch. 2.6 - Prob. 53E Ch. 2.6 - Prob. 54E Ch. 2.6 - Prob. 55E Ch. 2.6 - Prob. 56E Ch. 2.6 - Prob. 57E Ch. 2.6 - Prob. 58E Ch. 2.6 - Prob. 59E Ch. 2.6 - Prob. 60E Ch. 2.6 - Prob. 61E Ch. 2.6 - Prob. 62E Ch. 2.6 - Prob. 63E Ch. 2.6 - Prob. 64E Ch. 2.6 - Prob. 65E Ch. 2.6 - Prob. 66E Ch. 2.6 - Prob. 67E Ch. 2.6 - Prob. 68E Ch. 2.6 - Prob. 69E Ch. 2.6 - Prob. 70E Ch. 2.6 - Prob. 71E Ch. 2.6 - Prob. 72E Ch. 2.6 - Prob. 73E Ch. 2.6 - Prob. 74E Ch. 2.6 - Prob. 75E Ch. 2.6 - Prob. 76E Ch. 2.6 - Prob. 77E Ch. 2.6 - Prob. 78E Ch. 2.6 - Prob. 79E Ch. 2.6 - Prob. 80E Ch. 2.6 - Prob. 81E Ch. 2.6 - Prob. 82E Ch. 2.7 - Prob. 1E Ch. 2.7 - Prob. 2E Ch. 2.7 - Prob. 3E Ch. 2.7 - Prob. 4E Ch. 2.7 - Prob. 5E Ch. 2.7 - Prob. 6E Ch. 2.7 - Prob. 7E Ch. 2.7 - Prob. 8E Ch. 2.7 - Prob. 9E Ch. 2.7 - Prob. 10E Ch. 2.7 - Prob. 11E Ch. 2.7 - Prob. 12E Ch. 2.7 - Prob. 13E Ch. 2.7 - Prob. 14E Ch. 2.7 - Prob. 15E Ch. 2.7 - Prob. 16E Ch. 2.7 - Prob. 17E Ch. 2.7 - Prob. 18E Ch. 2.7 - Prob. 19E Ch. 2.7 - Prob. 20E Ch. 2.7 - Prob. 21E Ch. 2.7 - Prob. 22E Ch. 2.7 - Prob. 23E Ch. 2.7 - Prob. 24E Ch. 2.7 - Prob. 25E Ch. 2.7 - Prob. 26E Ch. 2.7 - Prob. 27E Ch. 2.7 - Prob. 28E Ch. 2.7 - Prob. 29E Ch. 2.7 - Prob. 30E Ch. 2.7 - Prob. 31E Ch. 2.7 - Prob. 32E Ch. 2.7 - Prob. 33E Ch. 2.7 - Prob. 34E Ch. 2.7 - Prob. 35E Ch. 2.7 - Prob. 36E Ch. 2.7 - Prob. 37E Ch. 2.7 - Prob. 38E Ch. 2.7 - Prob. 39E Ch. 2.7 - Prob. 40E Ch. 2.7 - Prob. 41E Ch. 2.7 - Prob. 42E Ch. 2.7 - Prob. 43E Ch. 2.7 - Prob. 44E Ch. 2.7 - Prob. 45E Ch. 2.7 - Prob. 46E Ch. 2.7 - Prob. 47E Ch. 2.7 - Prob. 48E Ch. 2.7 - Prob. 49E Ch. 2.7 - Prob. 50E Ch. 2.7 - Prob. 51E Ch. 2.7 - Prob. 52E Ch. 2.7 - Prob. 53E Ch. 2.7 - Prob. 54E Ch. 2.7 - Prob. 55E Ch. 2.7 - Prob. 56E Ch. 2.7 - Prob. 57E Ch. 2.7 - Prob. 58E Ch. 2.7 - Prob. 59E Ch. 2.7 - Prob. 60E Ch. 2.7 - Prob. 61E Ch. 2.7 - Prob. 62E Ch. 2.7 - Prob. 63E Ch. 2.7 - Prob. 64E Ch. 2.7 - Prob. 65E Ch. 2.7 - Prob. 66E Ch. 2.7 - Prob. 67E Ch. 2.7 - Prob. 68E Ch. 2.7 - Prob. 69E Ch. 2.7 - Prob. 70E Ch. 2.7 - Prob. 71E Ch. 2.7 - Prob. 72E Ch. 2.7 - Prob. 73E Ch. 2.7 - Prob. 74E Ch. 2.7 - Prob. 75E Ch. 2.7 - Prob. 76E Ch. 2.7 - Prob. 77E Ch. 2.7 - Prob. 78E Ch. 2.7 - Prob. 79E Ch. 2.7 - Prob. 80E Ch. 2.7 - Prob. 81E Ch. 2.7 - Prob. 82E Ch. 2.7 - Prob. 83E Ch. 2.7 - Prob. 84E Ch. 2.7 - Prob. 85E Ch. 2.7 - Prob. 86E Ch. 2.7 - Prob. 87E Ch. 2.7 - Prob. 88E Ch. 2.7 - Prob. 89E Ch. 2.7 - Prob. 90E Ch. 2 - Prob. 1RE Ch. 2 - Prob. 2RE Ch. 2 - Prob. 3RE Ch. 2 - Prob. 4RE Ch. 2 - Prob. 5RE Ch. 2 - Prob. 6RE Ch. 2 - Prob. 7RE Ch. 2 - Prob. 8RE Ch. 2 - Prob. 9RE Ch. 2 - Prob. 10RE Ch. 2 - Prob. 11RE Ch. 2 - Prob. 12RE Ch. 2 - Prob. 13RE Ch. 2 - Prob. 14RE Ch. 2 - Prob. 15RE Ch. 2 - Prob. 16RE Ch. 2 - Prob. 17RE Ch. 2 - Prob. 18RE Ch. 2 - Prob. 19RE Ch. 2 - Prob. 20RE Ch. 2 - Prob. 21RE Ch. 2 - Prob. 22RE Ch. 2 - Prob. 23RE Ch. 2 - Prob. 24RE Ch. 2 - Prob. 25RE Ch. 2 - Prob. 26RE Ch. 2 - Prob. 27RE Ch. 2 - Prob. 28RE Ch. 2 - Prob. 29RE Ch. 2 - Prob. 30RE Ch. 2 - Prob. 31RE Ch. 2 - Prob. 32RE Ch. 2 - Prob. 33RE Ch. 2 - Prob. 34RE Ch. 2 - Prob. 35RE Ch. 2 - Prob. 36RE Ch. 2 - Prob. 37RE Ch. 2 - Prob. 38RE Ch. 2 - Prob. 39RE Ch. 2 - Prob. 40RE Ch. 2 - Prob. 41RE Ch. 2 - Prob. 42RE Ch. 2 - Prob. 43RE Ch. 2 - Prob. 44RE Ch. 2 - Prob. 45RE Ch. 2 - Prob. 46RE Ch. 2 - Prob. 47RE Ch. 2 - Prob. 48RE Ch. 2 - Prob. 49RE Ch. 2 - Prob. 50RE Ch. 2 - Prob. 51RE Ch. 2 - Prob. 52RE Ch. 2 - Prob. 53RE Ch. 2 - Prob. 54RE Ch. 2 - Prob. 55RE Ch. 2 - Prob. 56RE Ch. 2 - Prob. 57RE Ch. 2 - Prob. 58RE Ch. 2 - Prob. 59RE Ch. 2 - Prob. 60RE Ch. 2 - Prob. 61RE Ch. 2 - Prob. 62RE Ch. 2 - Prob. 63RE Ch. 2 - Prob. 64RE Ch. 2 - Prob. 65RE Ch. 2 - Prob. 66RE Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 13CT Ch. 2 - Prob. 14CT Ch. 2 - Prob. 15CT Ch. 2 - Prob. 16CT Ch. 2 - Prob. 17CT Ch. 2 - Prob. 18CT Ch. 2 - Prob. 1PS Ch. 2 - Prob. 2PS Ch. 2 - Prob. 3PS Ch. 2 - Prob. 4PS Ch. 2 - Prob. 5PS Ch. 2 - Prob. 6PS Ch. 2 - Prob. 7PS Ch. 2 - Prob. 8PS Ch. 2 - Prob. 9PS Ch. 2 - Prob. 10PS Ch. 2 - Prob. 11PS Ch. 2 - Prob. 12PS Ch. 2 - Prob. 13PS

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