Concept explainers
(a)
Apply the coefficient test on function
(a)
Answer to Problem 20RE
The coefficient of highest power is positive graph will rise at LHS and also rise at RHS, the graph will rise at RHS and also rise at RHS.
Explanation of Solution
Given:
To apply the leading coefficient test on the
equation
The highest power is even and the coefficient of highest power is positive. So by leading coefficient test that when the highest power is even and the coefficient of highest power is positive graph will rise at LHS and also rise at RHS, the graph will rise at RHS and also rise at RHS.
(b)
Find the real zeros of the polynomial.
(b)
Answer to Problem 20RE
The zeros are 1,−3,0
Explanation of Solution
Given:
Find the zeros of this equation by equation it with 0, One of the zeros of this equation can be directly seen. It is x=0. For the other part of the equation
First equate it to zero and then find its roots.
So,
Zeros of such equations are found by first finding some of the roots by hit and trial and solving the rest. So,
Now, take out this factor from the equation and the rest of the equations will be Quadratic equation.
So the zeros are 1,−3,0
(c)
Plotting sufficient points.
(c)
Answer to Problem 20RE
Points are plotted below.
Explanation of Solution
Given:
Plot points for graph. For the points the graph will be like this,
(d)
Sketch
the continuous graph.
(d)
Answer to Problem 20RE
9532815067
Explanation of Solution
Given:
So the continuos graph is as follows,
Chapter 2 Solutions
EBK PRECALCULUS W/LIMITS
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