Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 2.3, Problem 38PP

(a)

Interpretation Introduction

Interpretation:

The number 84, 791kg needs to be round off to four significant figures.

Concept introduction:

In order to determine the number of significant figures, the following rules should be applied,

1. The non-zero digits are always significant.

2. In a number, the zeros to the left of the first non-zero digit are not significant.

3. Zeros between non zero digits are significant

4. Zeros to the right of the decimal place are significant

5. If a number ends in zero that are not to the right of a decimal, the zeros may or may not be significant.

To round off a number, look at the digit up to which number needs to be rounded off. If the digit right to it is less than 5 simply add 1 to the previous digit and remove all the digits after it from the number. If the digit right to the digit up to which rounding needs to be done is less than 5, just remove all the digits after it from the number.

Now, if the digit is equal to 5 then 1 is added to the previous digit if it is an odd number. If the previous digit is an even number, simply remove all the digits after it from the number.

(a)

Expert Solution
Check Mark

Answer to Problem 38PP

84, 791kg to four significant figures is 84, 790kg.

Explanation of Solution

In the given number, 84, 791kg the fifth digit is less than 5, remove all the digits to the right and to the right to make the number up to four significant figures. The last zero in the final answer is not significant but if there were a decimal point after the zero than the last zero will be considered a significant figure.

84, 791kg=84, 790kg

(b)

Interpretation Introduction

Interpretation:

The given number 38.5432g needs to be rounded off to four significant figures.

Concept introduction:

In order to determine the number of significant figures, the following rules should be applied,

1. The non-zero digits are always significant.

2. In a number, the zeros to the left of the first non-zero digit are not significant.

3. Zeros between non zero digits are significant

4. Zeros to the right of the decimal place are significant

5. If a number ends in zero that are not to the right of a decimal, the zeros may or may not be significant.

To round off a number, look at the digit up to which number needs to be rounded off. If the digit right to it is less than 5 simply add 1 to the previous digit and remove all the digits after it from the number. If the digit right to the digit up to which rounding needs to be done is less than 5, just remove all the digits after it from the number.

Now, if the digit is equal to 5 then 1 is added to the previous digit if it is an odd number. If the previous digit is an even number, simply remove all the digits after it from the number.

(b)

Expert Solution
Check Mark

Answer to Problem 38PP

38.5432g to four significant figures is 38.54g.

Explanation of Solution

In the given number, 38.5432g the third digit after the decimal point is less than 5, then remove all the digits to the right to make the number up to four significant figures.

38.5432g=38.54g

(c)

Interpretation Introduction

Interpretation:

The given number 256.75cm needs to be rounded off to four significant figures.

Concept introduction:

In order to determine the number of significant figures, the following rules should be applied,

1. The non-zero digits are always significant.

2. In a number, the zeros to the left of the first non-zero digit are not significant.

3. Zeros between non zero digits are significant

4. Zeros to the right of the decimal place are significant

5. If a number ends in zero that are not to the right of a decimal, the zeros may or may not be significant.

To round off a number, look at the digit up to which number needs to be rounded off. If the digit right to it is less than 5 simply add 1 to the previous digit and remove all the digits after it from the number. If the digit right to the digit up to which rounding needs to be done is less than 5, just remove all the digits after it from the number.

Now, if the digit is equal to 5 then 1 is added to the previous digit if it is an odd number. If the previous digit is an even number, simply remove all the digits after it from the number.

(c)

Expert Solution
Check Mark

Answer to Problem 38PP

256.75cm to four significant figures is 256.8cm.

Explanation of Solution

In the given number, 256.75cm the second digit after the decimal point is equal to 5, add 1 to the digit in the previous place and then remove all the digits to the right to make the number up to four significant figures.

256.75cm=256.8cm

(d)

Interpretation Introduction

Interpretation:

The given number 4.9356m needs to be rounded off to four significant figures.

Concept introduction:

In order to determine the number of significant figures, the following rules should be applied,

1. The non-zero digits are always significant.

2. In a number, the zeros to the left of the first non-zero digit are not significant.

3. Zeros between non zero digits are significant

4. Zeros to the right of the decimal place are significant

5. If a number ends in zero that are not to the right of a decimal, the zeros may or may not be significant.

To round off a number, look at the digit up to which number needs to be rounded off. If the digit right to it is less than 5 simply add 1 to the previous digit and remove all the digits after it from the number. If the digit right to the digit up to which rounding needs to be done is less than 5, just remove all the digits after it from the number.

Now, if the digit is equal to 5 then 1 is added to the previous digit if it is an odd number. If the previous digit is an even number, simply remove all the digits after it from the number.

(d)

Expert Solution
Check Mark

Answer to Problem 38PP

4.9356m to four significant figures is 4.936m.

Explanation of Solution

In the given number, 4.9356m the fourth digit after the decimal point is greater than 5, add 1 to the digit in the previous place and then remove all the digits to the right to make the number up to four significant figures.

4.9356m=4.936m

Chapter 2 Solutions

Chemistry: Matter and Change

Ch. 2.2 - Prob. 11PPCh. 2.2 - Prob. 12PPCh. 2.2 - Prob. 13PPCh. 2.2 - Prob. 14PPCh. 2.2 - Prob. 15PPCh. 2.2 - Prob. 16PPCh. 2.2 - Prob. 17PPCh. 2.2 - Prob. 18PPCh. 2.2 - Prob. 19PPCh. 2.2 - Prob. 20PPCh. 2.2 - Prob. 21PPCh. 2.2 - Prob. 22PPCh. 2.2 - Prob. 23PPCh. 2.2 - Prob. 24SSCCh. 2.2 - Prob. 25SSCCh. 2.2 - Prob. 26SSCCh. 2.2 - Prob. 27SSCCh. 2.2 - Prob. 28SSCCh. 2.2 - Prob. 29SSCCh. 2.2 - Prob. 30SSCCh. 2.2 - Prob. 31SSCCh. 2.3 - Prob. 32PPCh. 2.3 - Prob. 33PPCh. 2.3 - Prob. 34PPCh. 2.3 - Prob. 35PPCh. 2.3 - Prob. 36PPCh. 2.3 - Prob. 37PPCh. 2.3 - Prob. 38PPCh. 2.3 - Prob. 39PPCh. 2.3 - Prob. 40PPCh. 2.3 - Prob. 41PPCh. 2.3 - Prob. 42PPCh. 2.3 - Prob. 43PPCh. 2.3 - Prob. 44PPCh. 2.3 - Prob. 45SSCCh. 2.3 - Prob. 46SSCCh. 2.3 - Prob. 47SSCCh. 2.3 - Prob. 48SSCCh. 2.3 - Prob. 49SSCCh. 2.3 - Prob. 50SSCCh. 2.3 - Prob. 51SSCCh. 2.4 - Prob. 52SSCCh. 2.4 - Prob. 53SSCCh. 2.4 - Prob. 54SSCCh. 2.4 - Prob. 55SSCCh. 2.4 - Prob. 56SSCCh. 2.4 - Prob. 57SSCCh. 2.4 - Prob. 58SSCCh. 2 - Prob. 59ACh. 2 - Prob. 60ACh. 2 - Prob. 61ACh. 2 - Prob. 62ACh. 2 - Prob. 63ACh. 2 - Prob. 64ACh. 2 - Prob. 65ACh. 2 - Prob. 66ACh. 2 - Prob. 67ACh. 2 - Prob. 68ACh. 2 - Prob. 69ACh. 2 - Prob. 70ACh. 2 - Prob. 71ACh. 2 - Prob. 72ACh. 2 - Prob. 73ACh. 2 - Prob. 74ACh. 2 - Prob. 75ACh. 2 - Prob. 76ACh. 2 - Prob. 77ACh. 2 - Prob. 78ACh. 2 - Prob. 79ACh. 2 - Prob. 80ACh. 2 - Prob. 81ACh. 2 - Prob. 82ACh. 2 - Prob. 83ACh. 2 - Prob. 84ACh. 2 - Prob. 85ACh. 2 - Prob. 86ACh. 2 - Prob. 87ACh. 2 - Prob. 88ACh. 2 - Prob. 89ACh. 2 - Prob. 90ACh. 2 - Prob. 91ACh. 2 - Prob. 92ACh. 2 - Prob. 93ACh. 2 - Prob. 94ACh. 2 - Prob. 95ACh. 2 - Prob. 96ACh. 2 - Prob. 97ACh. 2 - Prob. 98ACh. 2 - Prob. 99ACh. 2 - Prob. 100ACh. 2 - Prob. 101ACh. 2 - Prob. 102ACh. 2 - Prob. 103ACh. 2 - Prob. 104ACh. 2 - Prob. 105ACh. 2 - Prob. 106ACh. 2 - Prob. 107ACh. 2 - Prob. 108ACh. 2 - Prob. 109ACh. 2 - Prob. 110ACh. 2 - Prob. 111ACh. 2 - Prob. 112ACh. 2 - Prob. 113ACh. 2 - Prob. 114ACh. 2 - Prob. 115ACh. 2 - Prob. 116ACh. 2 - Prob. 117ACh. 2 - Prob. 118ACh. 2 - Prob. 119ACh. 2 - Prob. 120ACh. 2 - Prob. 121ACh. 2 - Prob. 122ACh. 2 - Prob. 123ACh. 2 - Prob. 124ACh. 2 - Prob. 125ACh. 2 - Prob. 126ACh. 2 - Prob. 127ACh. 2 - Prob. 128ACh. 2 - Prob. 129ACh. 2 - Prob. 130ACh. 2 - Prob. 1STPCh. 2 - Which value is NOT equivalent to the others? A....Ch. 2 - Prob. 3STPCh. 2 - Prob. 4STPCh. 2 - Prob. 5STPCh. 2 - Prob. 6STPCh. 2 - Prob. 7STPCh. 2 - Prob. 8STPCh. 2 - Prob. 9STPCh. 2 - Prob. 10STPCh. 2 - Prob. 11STPCh. 2 - Prob. 12STPCh. 2 - Prob. 13STPCh. 2 - Prob. 14STPCh. 2 - Prob. 15STPCh. 2 - Prob. 16STPCh. 2 - Prob. 17STPCh. 2 - Prob. 18STPCh. 2 - Prob. 19STPCh. 2 - Prob. 20STP
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