Chapter 2, Problem 103A

Interpretation Introduction

Interpretation:

The volume of a $23\text{g}$ sample of ethanol with the density of $0.7893\text{g/mL}$ needs to be determined.

Concept introduction:

Density of a sample of matter or an object is equal to the mass of the sample divided by the volume of the sample.

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$

Answer to Problem 103A

Volume of the given sample is $29.14\text{mL}$.

Explanation of Solution

Mass of the ethanol sample = $23\text{g}$

Volume of the ethanol sample = $0.7893\text{g/mL}$

Thus,

$\begin{array}{c}\text{Density}=\frac{\text{Mass}}{\text{Volume}}\\ 0.7893\text{g/mL}=\frac{\text{23}\text{g}}{\text{Volume}}\\ \text{Volume}=\frac{\text{23}\text{g}}{0.7893\text{g/mL}}\\ =29.14\text{mL}\end{array}$

Conclusion

Thus, the volume of the given sample is $29.14\text{mL}$.