Chapter 2, Problem 82A

Interpretation Introduction

Interpretation:

The number of kernels of the popcorns in $\text{0}\text{.500}\text{pounds}$ of popcorn needs to be determined.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits. Conversion is factor is the ratio of equivalent value with different units.

Answer to Problem 82A

There are $\text{1810}$ kernels of popcorn in $\text{0}\text{.500}\text{pounds}$.

Explanation of Solution

Given Information:

For 1 kernel popcorn, the average mass is $\text{0}\text{.125}\text{g}$. Also, $\text{1}\text{pound}$ is equal to $\text{16}\text{ounces}$ and $\text{1}\text{ounce}$ is of $\text{28}\text{.3}\text{g}$.

Calculation:

Conversion factor is needed for the calculation of number of kernels of popcorns in $\text{0}\text{.500}\text{pounds}$. The conversion factor is as:

$\begin{array}{c}\text{Number of kernels}\text{=0}\text{.500}\text{pounds}\text{.popcorn×}\frac{\text{16 ounces}}{\text{1 pound}}\text{×}\frac{\text{28}\text{.3}\text{g}}{\text{1 ounce}}\text{×}\frac{\text{1kernel}}{0.125\text{g}}\\ =\text{1810}\text{kernels}\text{popcorn}\end{array}$

Hence, the there are $\text{1810}$ kernels of popcorn in $\text{0}\text{.500}\text{pounds}$.

Conclusion

There are $\text{1810}$ kernels of popcorn in $\text{0}\text{.500}\text{pounds}$.