Chapter 2.2, Problem 19PP

Interpretation Introduction

(a)

Interpretation:

The given time in 360 s needs to be converted to ms.

Concept introduction:

Conversion refers to the change in the forms of measurements, different units but without the change in the size or the amount.

Answer to Problem 19PP

360 s is 360, 000 in meter second (ms).

Explanation of Solution

The conversion of 360 s to ms is given below:

$360s\times \frac{1000ms}{1s}=360,000ms$

(b)

Interpretation Introduction

Interpretation:

The given mass needs to be converted from 4800 g to kg.

Concept introduction:

Conversion refers to the change in the forms of measurements, different units but without the change in the size or the amount.

Answer to Problem 19PP

4800 g is 4.8 in kilogram (kg).

Explanation of Solution

The conversion of 4800 g to kg is given below:

$4800g\times \frac{1kg}{1000g}=4.8kg$

(c)

Interpretation Introduction

Interpretation:

The given length needs to be converted from 5600 dm to m.

Concept introduction:

Conversion refers to the change in the forms of measurements, different units but without the change in the size or the amount.

Answer to Problem 19PP

5600 dm is 560 in meter (m).

Explanation of Solution

The conversion of 5600 dm to m is given below:

$5600dm\times \frac{1m}{10dm}=560m$

(d)

Interpretation Introduction

Interpretation:

The mass 72 g needs to be converted to mg.

Concept introduction:

Conversion refers to the change in the forms of measurements, different units but without the change in the size or the amount.

Answer to Problem 19PP

72 g is 72, 000 in milligram (mg).

Explanation of Solution

The conversion of 72 g to mg is given below:

$72g\times \frac{1000mg}{1g}=72,000mg$

(e)

Interpretation Introduction

Interpretation:

The time $2.45\times {10}^{2}ms$ needs to be converted into s.

Concept introduction:

Conversion refers to the change in the forms of measurements, different units but without the change in the size or the amount.

Answer to Problem 19PP

$2.45\times {10}^{2}ms$ is 0.245 in second (s).

Explanation of Solution

The conversion of $2.45\times {10}^{2}ms$ to s is given below:

$2.45\times {10}^{2}ms\times \frac{1s}{1000ms}=0.245s$

(f)

Interpretation Introduction

Interpretation:

The length or distance $5\mu m$ needs to be converted to km.

Concept introduction:

Conversion refers to the change in the forms of measurements, different units but without the change in the size or the amount.

Answer to Problem 19PP

$5\mu m$ is $5\times {10}^{-9}km$.

Explanation of Solution

The conversion of $5\mu m$ to km is given below:

$5\mu m\times \frac{{10}^{-9}km}{1\mu m}=5\times {10}^{-9}km$

(g)

Interpretation Introduction

Interpretation:

The length or distance $6.800\times {10}^3$ cm needs to be converted to km.

Concept introduction:

Conversion refers to the change in the forms of measurements, different units but without the change in the size or the amount.

Answer to Problem 19PP

$6.800\times {10}^3$ cm is 0.068 in kilometers (km).

Explanation of Solution

The conversion of $6.800\times {10}^3$ cm to km is given below:

$6800cm\times \frac{1m}{100cm}\times \frac{1km}{1000m}=0.068km$

(h)

Interpretation Introduction

Interpretation:

The mass $2.5\times {10}^1$ kg needs to be converted to Mg.

Concept introduction:

Conversion refers to the change in the forms of measurements, different units but without the change in the size or the amount.

Answer to Problem 19PP

$2.5\times {10}^1$ kg is 0.025 in milligram (mg).

Explanation of Solution

The conversion of $2.5\times {10}^1$ kg to Mg is given below:

$2.5\times {10}^{1}kg\times \frac{1Mg}{1000kg}=0.025Mg$