Chapter 23, Problem 23.71AP

Interpretation Introduction

(a)

Interpretation:

The compound $A\left({\text{C}}_{\text{9}}{\text{H}}_{\text{13}}\text{NO}\right)$ is to be identified by the use of given spectroscopy data.

Concept introduction:

NMR spectroscopy is a technique used to determine the unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy. The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region.

Interpretation Introduction

(b)

Interpretation:

The compound $B\left({\text{C}}_{\text{6}}{\text{H}}_{\text{16}}{\text{N}}_{\text{2}}\right)$ is to be identified by the use of given spectroscopy data.

Concept introduction:

NMR spectroscopy is a technique used to determine the unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as as a proton in the NMR spectroscopy. The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region.

Interpretation Introduction

(c)

Interpretation:

The compound $C\left({\text{C}}_{\text{6}}{\text{H}}_{\text{13}}\text{N}\right)$ is to be identified by the use of given spectroscopy data.

Concept introduction:

NMR spectroscopy is a technique used to determine the unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy. The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region.