Chapter 23, Problem 23.60P

(a)

Interpretation Introduction

Interpretation:

The coordination number of the metal ion and the number of individual ions per formula unit have has to be given.

Concept introduction:

Coordination number:

The coordination number is the number of ligand atoms bonded directly to the central metal ion in a complex ion.

Oxidation number: (Oxidation state) A number equal to the magnitude of the charge an atom would have if its shared electrons were transferred to the atom that attracts them more strongly.

1. 1. The cation is named before the anion.
2. 2. Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).
3. 3. When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.
4. 4. The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.
5. 5. If the complex ion is an anion, the metal name should end with –ate.

Explanation of Solution

Given,

$K_3\left[Cr{\left(C_2{O}_4\right)}_3\right]$

The counter ion is $K^{+}$ so the complex ion is ${\left[Cr{\left(C_2{O}_4\right)}_3\right]}^{3-}$

Each aqua ligand is bidentate, so the coordination number is 6.

Each molecule dissolves in water to form three $K^{+}$ ion and one ${\left[Cr{\left(H_{2}O\right)}_6\right]}^{3+}$ ion, Hence, Four ions form per formula unit.

(b)

Interpretation Introduction

Interpretation:

The coordination number of the metal ion and the number of individual ions per formula unit have has to be given.

Concept introduction:

Coordination number:

The coordination number is the number of ligand atoms bonded directly to the central metal ion in a complex ion.

Oxidation number: (Oxidation state) A number equal to the magnitude of the charge an atom would have if its shared electrons were transferred to the atom that attracts them more strongly.

1. 1. The cation is named before the anion.
2. 2. Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).
3. 3. When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.
4. 4. The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.
5. 5. If the complex ion is an anion, the metal name should end with –ate.

Explanation of Solution

Given,

${\left[Co{(en)}_3\right]}_4{\left[Mn{(CN)}_{5}I\right]}_3$

There are two complex is present one is ${\left[Co{(en)}_3\right]}_4^{12-}$ and another one is ${\left[Mn{(CN)}_{5}I\right]}_3^{12+}$

The ethylenediamine ligand is bidentate, so the coordination number cobalt is 6.

The cyanide and chloride ligand are unidentate, so the coordination number Manganese is 6.

Each molecule dissolves in water to form four ${\left[Co{(en)}_3\right]}_4^{12-}$ ions and three

${\left[Mn{(CN)}_{5}I\right]}_3^{12+}$ ion, hence, seven ions form per formula unit.

(c)

Interpretation Introduction

Interpretation:

The coordination number of the metal ion and the number of individual ions per formula unit have has to be given.

Concept introduction:

Coordination number:

The coordination number is the number of ligand atoms bonded directly to the central metal ion in a complex ion.

Oxidation number: (Oxidation state) A number equal to the magnitude of the charge an atom would have if its shared electrons were transferred to the atom that attracts them more strongly.

1. 1. The cation is named before the anion.
2. 2. Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).
3. 3. When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.
4. 4. The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.
5. 5. If the complex ion is an anion, the metal name should end with –ate.

Explanation of Solution

Given,

  $\left[Al{\left(H_{2}O\right)}_2{(N{H}_3)}_{2}BrCl\right]N{O}_3$

The counter ion is $N{O}_3^{-}$ so the complex ion is ${\left[Al{\left(H_{2}O\right)}_2{(N{H}_3)}_{2}BrCl\right]}^{+}$

Each of the aquo, ammonia and halogen ligands are unidentate, the coordination number is 6.

Each molecule dissolves in water to form one $N{O}_3^{-}$ ions and one

${\left[Al{\left(H_{2}O\right)}_2{(N{H}_3)}_{2}BrCl\right]}^{+}$ ion,

Hence, two ions form per formula unit.