Bundle: Chemistry for Today: General, Organic, and Biochemistry, Loose-Leaf Version, 9th + LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card
9th Edition
ISBN: 9781337598255
Author: Spencer L. Seager
Publisher: Cengage Learning
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Chapter 23, Problem 23.47E
Interpretation Introduction
Interpretation:
The reason as to why
Concept introduction:
Glycolysis is the process in which the glucose molecules convert into pyruvate. The energy released in this process is used for the formation of
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The average adult consumes approximately 11,700 kJ per day. Assuming that the metabolic pathways leading to ATP synthesis operate at 50% thermodynamic efficiency, about 5850 kJ ends up in the form of synthesized ATP.
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Chapter 23 Solutions
Bundle: Chemistry for Today: General, Organic, and Biochemistry, Loose-Leaf Version, 9th + LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card
Ch. 23 - Why is glucose considered the pivotal compound in...Ch. 23 - Prob. 23.2ECh. 23 - Prob. 23.3ECh. 23 - Describe what is meant by the terms blood sugar...Ch. 23 - What range of concentrations for glucose in blood...Ch. 23 - Prob. 23.6ECh. 23 - Prob. 23.7ECh. 23 - Prob. 23.8ECh. 23 - Prob. 23.9ECh. 23 - Prob. 23.10E
Ch. 23 - Prob. 23.11ECh. 23 - Prob. 23.12ECh. 23 - Prob. 23.13ECh. 23 - Prob. 23.14ECh. 23 - Prob. 23.15ECh. 23 - Prob. 23.16ECh. 23 - Prob. 23.17ECh. 23 - Prob. 23.18ECh. 23 - Prob. 23.19ECh. 23 - Prob. 23.20ECh. 23 - Prob. 23.21ECh. 23 - Prob. 23.22ECh. 23 - Prob. 23.23ECh. 23 - Prob. 23.24ECh. 23 - Prob. 23.25ECh. 23 - Prob. 23.26ECh. 23 - Prob. 23.27ECh. 23 - Prob. 23.28ECh. 23 - Prob. 23.29ECh. 23 - Prob. 23.30ECh. 23 - Prob. 23.31ECh. 23 - Prob. 23.32ECh. 23 - Prob. 23.33ECh. 23 - Prob. 23.34ECh. 23 - Prob. 23.35ECh. 23 - Prob. 23.36ECh. 23 - Prob. 23.37ECh. 23 - Prob. 23.38ECh. 23 - Prob. 23.39ECh. 23 - Prob. 23.40ECh. 23 - Prob. 23.41ECh. 23 - Prob. 23.42ECh. 23 - Prob. 23.43ECh. 23 - Prob. 23.44ECh. 23 - Prob. 23.45ECh. 23 - Prob. 23.46ECh. 23 - Prob. 23.47ECh. 23 - Prob. 23.48ECh. 23 - Prob. 23.49ECh. 23 - Prob. 23.50ECh. 23 - Prob. 23.51ECh. 23 - Prob. 23.52ECh. 23 - Prob. 23.53ECh. 23 - Prob. 23.54ECh. 23 - Prob. 23.55ECh. 23 - Prob. 23.56ECh. 23 - Prob. 23.57ECh. 23 - Prob. 23.58ECh. 23 - Prob. 23.59ECh. 23 - Prob. 23.60ECh. 23 - Prob. 23.61ECh. 23 - Prob. 23.62ECh. 23 - Prob. 23.63ECh. 23 - Prob. 23.64ECh. 23 - Prob. 23.65ECh. 23 - Lactate dehydrogenase catalyzes the following...Ch. 23 - Prob. 23.67ECh. 23 - Prob. 23.68ECh. 23 - Prob. 23.69ECh. 23 - Prob. 23.70ECh. 23 - A friend started to make wine by adding yeast to...Ch. 23 - Prob. 23.72ECh. 23 - Explain why monitoring blood lactate levels might...Ch. 23 - Prob. 23.74ECh. 23 - Prob. 23.75ECh. 23 - Prob. 23.76ECh. 23 - Prob. 23.77ECh. 23 - Prob. 23.78ECh. 23 - Prob. 23.79ECh. 23 - Prob. 23.80ECh. 23 - Prob. 23.81ECh. 23 - Prob. 23.82ECh. 23 - Prob. 23.83ECh. 23 - Prob. 23.84ECh. 23 - Prob. 23.85ECh. 23 - Prob. 23.86ECh. 23 - Prob. 23.87ECh. 23 - Prob. 23.88ECh. 23 - Prob. 23.89ECh. 23 - Prob. 23.90E
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- Rigor mortis, the stiffening of muscles. after death is due to the depletion of intracellular ATP. Provide the biochemical basis of rigor mortisarrow_forwardIf sugar must be broken down to release energy through cellular respiration, why is ATP needed in the process? Explain.arrow_forwardKinases are enzymes that catalyze the addition (or removal) of a phosphate group to ( or from) a substance. ATP is also involved. How many kinases are in glycolysis? Name them.arrow_forward
- Below is the overall net equation for the complete oxidation of pyruvate. Calculate the number of ATP molecules that can be produced from the complete oxidation of 6 molecules of pyruvate. Pyruvate + 4NAD+ + FAD + GDP + Pi + 2H₂O → 3CO2 + 4NADH + 4H+ + FADH2 + GTP (Given: The oxidation of one NADH yields 2.5 ATP; the oxidation of one FADH2 yields 1.5 ATP; and one GDP yields 1 ATP.) O 75 ATP O 60 ATP O 12.5 ATP O 32 ATParrow_forwardAnaerobic glycolysis (i.e., lactic acid fermentation) produces pyruvate that is then converted to lactate through the activity of lactate dehydrogenase. The conversion of pyruvate to lactate would seem to be an unnecessary step, since this process does not result in any further release of energy. Explain the necessity for the production of lactate as the endpoint for anaerobic glycolysis.arrow_forwardTrypanosomes living in the bloodstream obtain all their free energy from glycolysis. They take up glucose from the host’s blood and excrete pyruvate as a waste product. In this part of their life cycle, trypanosomes do not carry out any oxidative phosphorylation, but they do use another oxygen-dependent pathway, which is absent in mammals, to oxidize NADH. Would this pathway be necessary if the trypanosome excreted lactate rather than pyruvate? Explain.arrow_forward
- ATP is produced during synthesis of compounds. O True O Falsearrow_forwardDetermine the number of ATP molecules that can be formed from the complete oxidation of 10 molecules of acetyl CoA. The overall net equation for the complete oxidation of acetyl CoA is provided below. Acetyl CoA + 3NAD+ + FAD + GDP + Pi + 2H₂O → 2CO2 + HS-CoA + 3NADH + 3H+ + FADH2 + GTP (Given: The oxidation of one NADH yields 2.5 ATP; the oxidation of one FADH2 yields 1.5 ATP; and one GDP yields 1 ATP.) O 10 ATP O 7,5 ATP O 100 ATP O 75 ATParrow_forwardShort answer questions. You must show work indicating production or consumption of molecules such as ATP or NADH in the various pathways involved in these questions. Consider that a molecule of alanine can be converted to pyruvate by an oxidation reaction that produces one NADH. If the liver is to make a molecule of glucose from alanine, how many molecules of alanine are required? How many ATP equivalents are required?arrow_forward
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