The Fisher projection of the open chain of glucose is to be drawn. Concept introduction: The most abundant monsaccharide is glucose. Six carbon atoms are present in the Fisher projection of the open chain of glucose. Fisher projections are used to represent the open chain form of sugars.

Question

Want to see more full solutions like this?

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 23, Problem 23.46SP

(a)

Interpretation Introduction

Interpretation:

The Fisher projection of the open chain of glucose is to be drawn.

Concept introduction:

The most abundant monsaccharide is glucose. Six carbon atoms are present in the Fisher projection of the open chain of glucose. Fisher projections are used to represent the open chain form of sugars.

(a)

Expert Solution

Answer to Problem 23.46SP

The Fisher projection of the open chain of glucose is shown in Figure 1.

Explanation of Solution

The Fisher projection of the open chain of glucose is shown below. Glucose is an aldose because it a sugar with an aldehyde group. Fisher projections are used to draw the structure of carbohydrates.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 1

Figure 1

(b)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(b)

Expert Solution

Answer to Problem 23.46SP

The most stable conformation of the most stable pyranose anomer is shown in Figure 2.

Explanation of Solution

The most stable conformation of the most stable pyranose anomer is shown in Figure 2. In β−D(+) glucopyranose, all the −OH groups are present on equatorial position.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 2

Figure 2

(c)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(c)

Expert Solution

Answer to Problem 23.46SP

The Haworth projection of the most stable pyranose anomer is shown in Figure 3.

Explanation of Solution

The Haworth projection of the most stable pyranose anomer is shown below.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 3

Figure 3

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Consider the reaction of a propanoate ester with hydroxide ion shown below. A series of four alcohol leaving groups were tested to determine which would be the best leaving group. Based on the pKa values of the alcohols, predict which alcohol would produce the fastest hydrolysis reaction. HO FOR A Alcohol I, pKa =16.0 B Alcohol II, pKa =10.0 C Alcohol III, pKa = 7.2 + ROH D Alcohol IV, pKa = 6.6

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :0: NaOH, H₂O 00:4 Na O heat NaO Select to Add Arrows Select to Add Arrows :0: Na a NaOH, H2O :0: NaOH, H2O heat heat Na ONH Select to Add Arrows

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. H CH3NH3+ :0: :0: HO CH3NH2 HH iSelect to Add Arrows i Select to Add Arrows i HH CH3NH3+ CH3NH2 Select to Add Arrows i CH3NH3 CH3NH2 ايكدا HH Select to Add Arrows

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 23, Problem 23.46SP

(a)

Interpretation Introduction

Interpretation:

The Fisher projection of the open chain of glucose is to be drawn.

Concept introduction:

The most abundant monsaccharide is glucose. Six carbon atoms are present in the Fisher projection of the open chain of glucose. Fisher projections are used to represent the open chain form of sugars.

(a)

Expert Solution

Answer to Problem 23.46SP

The Fisher projection of the open chain of glucose is shown in Figure 1.

Explanation of Solution

The Fisher projection of the open chain of glucose is shown below. Glucose is an aldose because it a sugar with an aldehyde group. Fisher projections are used to draw the structure of carbohydrates.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 1

Figure 1

(b)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(b)

Expert Solution

Answer to Problem 23.46SP

The most stable conformation of the most stable pyranose anomer is shown in Figure 2.

Explanation of Solution

The most stable conformation of the most stable pyranose anomer is shown in Figure 2. In β−D(+) glucopyranose, all the −OH groups are present on equatorial position.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 2

Figure 2

(c)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(c)

Expert Solution

Answer to Problem 23.46SP

The Haworth projection of the most stable pyranose anomer is shown in Figure 3.

Explanation of Solution

The Haworth projection of the most stable pyranose anomer is shown below.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 3

Figure 3

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 23, Problem 23.46SP

(a)

Interpretation Introduction

Interpretation:

The Fisher projection of the open chain of glucose is to be drawn.

Concept introduction:

The most abundant monsaccharide is glucose. Six carbon atoms are present in the Fisher projection of the open chain of glucose. Fisher projections are used to represent the open chain form of sugars.

(a)

Expert Solution

Answer to Problem 23.46SP

The Fisher projection of the open chain of glucose is shown in Figure 1.

Explanation of Solution

The Fisher projection of the open chain of glucose is shown below. Glucose is an aldose because it a sugar with an aldehyde group. Fisher projections are used to draw the structure of carbohydrates.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 1

Figure 1

(b)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(b)

Expert Solution

Answer to Problem 23.46SP

The most stable conformation of the most stable pyranose anomer is shown in Figure 2.

Explanation of Solution

The most stable conformation of the most stable pyranose anomer is shown in Figure 2. In β−D(+) glucopyranose, all the −OH groups are present on equatorial position.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 2

Figure 2

(c)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(c)

Expert Solution

Answer to Problem 23.46SP

The Haworth projection of the most stable pyranose anomer is shown in Figure 3.

Explanation of Solution

The Haworth projection of the most stable pyranose anomer is shown below.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 3

Figure 3

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 23, Problem 23.46SP

(a)

Interpretation Introduction

Interpretation:

The Fisher projection of the open chain of glucose is to be drawn.

Concept introduction:

The most abundant monsaccharide is glucose. Six carbon atoms are present in the Fisher projection of the open chain of glucose. Fisher projections are used to represent the open chain form of sugars.

(a)

Expert Solution

Answer to Problem 23.46SP

The Fisher projection of the open chain of glucose is shown in Figure 1.

Explanation of Solution

The Fisher projection of the open chain of glucose is shown below. Glucose is an aldose because it a sugar with an aldehyde group. Fisher projections are used to draw the structure of carbohydrates.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 1

Figure 1

(b)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(b)

Expert Solution

Answer to Problem 23.46SP

The most stable conformation of the most stable pyranose anomer is shown in Figure 2.

Explanation of Solution

The most stable conformation of the most stable pyranose anomer is shown in Figure 2. In β−D(+) glucopyranose, all the −OH groups are present on equatorial position.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 2

Figure 2

(c)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(c)

Expert Solution

Answer to Problem 23.46SP

The Haworth projection of the most stable pyranose anomer is shown in Figure 3.

Explanation of Solution

The Haworth projection of the most stable pyranose anomer is shown below.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 3

Figure 3

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 23, Problem 23.46SP

(a)

Interpretation Introduction

Interpretation:

The Fisher projection of the open chain of glucose is to be drawn.

Concept introduction:

The most abundant monsaccharide is glucose. Six carbon atoms are present in the Fisher projection of the open chain of glucose. Fisher projections are used to represent the open chain form of sugars.

(a)

Expert Solution

Answer to Problem 23.46SP

The Fisher projection of the open chain of glucose is shown in Figure 1.

Explanation of Solution

The Fisher projection of the open chain of glucose is shown below. Glucose is an aldose because it a sugar with an aldehyde group. Fisher projections are used to draw the structure of carbohydrates.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 1

Figure 1

(b)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(b)

Expert Solution

Answer to Problem 23.46SP

The most stable conformation of the most stable pyranose anomer is shown in Figure 2.

Explanation of Solution

The most stable conformation of the most stable pyranose anomer is shown in Figure 2. In β−D(+) glucopyranose, all the −OH groups are present on equatorial position.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 2

Figure 2

(c)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(c)

Expert Solution

Answer to Problem 23.46SP

The Haworth projection of the most stable pyranose anomer is shown in Figure 3.

Explanation of Solution

The Haworth projection of the most stable pyranose anomer is shown below.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 3

Figure 3

Answer 6

Chapter 23, Problem 23.46SP

(a)

Interpretation Introduction

Interpretation:

The Fisher projection of the open chain of glucose is to be drawn.

Concept introduction:

The most abundant monsaccharide is glucose. Six carbon atoms are present in the Fisher projection of the open chain of glucose. Fisher projections are used to represent the open chain form of sugars.

(a)

Expert Solution

Answer to Problem 23.46SP

The Fisher projection of the open chain of glucose is shown in Figure 1.

Explanation of Solution

The Fisher projection of the open chain of glucose is shown below. Glucose is an aldose because it a sugar with an aldehyde group. Fisher projections are used to draw the structure of carbohydrates.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 1

Figure 1

Answer 7

Chapter 23, Problem 23.46SP

(a)

Interpretation Introduction

Interpretation:

The Fisher projection of the open chain of glucose is to be drawn.

Concept introduction:

The most abundant monsaccharide is glucose. Six carbon atoms are present in the Fisher projection of the open chain of glucose. Fisher projections are used to represent the open chain form of sugars.

Answer 8

(a)

Expert Solution

Answer to Problem 23.46SP

The Fisher projection of the open chain of glucose is shown in Figure 1.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The Fisher projection of the open chain of glucose is shown below. Glucose is an aldose because it a sugar with an aldehyde group. Fisher projections are used to draw the structure of carbohydrates.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 1

Figure 1

Answer 13

(b)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

(b)

Expert Solution

Answer to Problem 23.46SP

The most stable conformation of the most stable pyranose anomer is shown in Figure 2.

Explanation of Solution

The most stable conformation of the most stable pyranose anomer is shown in Figure 2. In β−D(+) glucopyranose, all the −OH groups are present on equatorial position.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 2

Figure 2

Answer 14

(b)

Interpretation Introduction

Interpretation:

The most stable conformation of the most stable pyranose anomer is to be drawn.

Concept introduction:

Cyclic monosaccharides are drawn with the help of Fisher projection. The groups on the right side of fisher projection are down in the cyclic structure while groups on the left side are up.

Answer 15

(b)

Expert Solution

Answer to Problem 23.46SP

The most stable conformation of the most stable pyranose anomer is shown in Figure 2.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The most stable conformation of the most stable pyranose anomer is shown in Figure 2. In β−D(+) glucopyranose, all the −OH groups are present on equatorial position.

ORGANIC CHEMISTRY MASTERINGCHEM ACCESS, Chapter 23, Problem 23.46SP , additional homework tip 2

Figure 2