(a) Interpretation: The pMg of the solution should be determined. Concept introduction: pX = − log a x = − n ( E c e l l − K ) 0.0592 K = E J − E r e f + L n − number of electrons K − constant L − constant E J − junction potential E ref − reference electrode potential

Question

The following cell was found to have a potential of 0.2897 V:SCEIIMg2+(a = 3.32 * 10^-3M)membrane electrode for Mg^2+(a) When the solution of known magnesium activity was replaced with an unknown solution, the potentialwas found to be 0.2041 V. What was the pMg of this unknown solution?(b) Assuming an uncertainty of 60.002 V in the junction potential, what is the range of Mg21 activitieswithin which the true value might be expected?(c) What is the relative error in [Mg^2+] associated with the uncertainty in Ej?

Answer 1

Question

Chapter 23, Problem 23.25QAP

Interpretation Introduction

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(b)

Interpretation:

The range of Mg²+ activities within which the true value might be expected should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%

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The following cell was found to have a potential of 0.2897 V:SCEIIMg2+(a = 3.32 * 10^-3M)membrane electrode for Mg^2+(a) When the solution of known magnesium activity was replaced with an unknown solution, the potentialwas found to be 0.2041 V. What was the pMg of this unknown solution?(b) Assuming an uncertainty of 60.002 V in the junction potential, what is the range of Mg21 activitieswithin which the true value might be expected?(c) What is the relative error in [Mg^2+] associated with the uncertainty in Ej?

For the cellPt | Fe2+ (a = 2.00), Fe3+ (a = 1.20) || I- (a = 0.100) | I2 (s) | Pt (a) write the cell reaction;(b) calculate the cell potential at 298 K, assuming the net liquid junction potential is negligible.[-0.164 V] The answer for (b) is written in the bracket. Thank you!

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Answer 2

Question

Chapter 23, Problem 23.25QAP

Interpretation Introduction

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(b)

Interpretation:

The range of Mg²+ activities within which the true value might be expected should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%

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Answer 3

Question

Chapter 23, Problem 23.25QAP

Interpretation Introduction

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(b)

Interpretation:

The range of Mg²+ activities within which the true value might be expected should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%

Expert Solution & Answer

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Answer 4

Question

Chapter 23, Problem 23.25QAP

Interpretation Introduction

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(b)

Interpretation:

The range of Mg²+ activities within which the true value might be expected should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%

Expert Solution & Answer

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Answer 5

Chapter 23, Problem 23.25QAP

Interpretation Introduction

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(b)

Interpretation:

The range of Mg²+ activities within which the true value might be expected should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Interpretation Introduction

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%

Answer 6

Chapter 23, Problem 23.25QAP

Interpretation Introduction

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Answer 7

Chapter 23, Problem 23.25QAP

Interpretation Introduction

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Answer 8

Interpretation Introduction

(b)

Interpretation:

The range of Mg²+ activities within which the true value might be expected should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Answer 9

Interpretation Introduction

(b)

Interpretation:

The range of Mg²+ activities within which the true value might be expected should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

Answer 10

Interpretation Introduction

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%

Answer 11

Interpretation Introduction

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%

Answer 12

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Answer 23

Ch. 23 - Prob. 23.1QAP Ch. 23 - Prob. 23.2QAP Ch. 23 - Prob. 23.3QAP Ch. 23 - Prob. 23.4QAP Ch. 23 - Prob. 23.5QAP Ch. 23 - Prob. 23.6QAP Ch. 23 - Prob. 23.7QAP Ch. 23 - Prob. 23.8QAP Ch. 23 - Prob. 23.9QAP Ch. 23 - List the advantages and disadvantages of a...

(a) Interpretation: The pMg of the solution should be determined. Concept introduction: pX = − log a x = − n ( E c e l l − K ) 0.0592 K = E J − E r e f + L n − number of electrons K − constant L − constant E J − junction potential E ref − reference electrode potential

Concept explainers

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%

Chapter 23 Solutions

(a) Interpretation: The pMg of the solution should be determined. Concept introduction: pX = − log a x = − n ( E c e l l − K ) 0.0592 K = E J − E r e f + L n − number of electrons K − constant L − constant E J − junction potential E ref − reference electrode potential

Concept explainers

(a) Interpretation: The pMg of the solution should be determined. Concept introduction: pX = −logax=−n(Ecell−K)0.0592 K=EJ−Eref+L n − number of electrons K − constant L − constant EJ − junction potential Eref − reference electrode potential

(c) Interpretation: The relative error in [Mg2+] associated with the uncertainty in Ej should be determined. Concept introduction: Relative error = (Measured - Actual)Actual×100%

Chapter 23 Solutions

(a)

Interpretation:

The pMg of the solution should be determined.

Concept introduction:

pX = −logax=−n(Ecell−K)0.0592

K=EJ−Eref+L

n − number of electrons

K − constant

L − constant

E_J − junction potential

E_ref − reference electrode potential

(c)

Interpretation:

The relative error in [Mg²⁺] associated with the uncertainty in E_j should be determined.

Concept introduction:

Relative error = (Measured - Actual)Actual×100%