Free-Falling Object In Exercises 107 and 108, use the position function s ( t ) = − 4.9 t 2 + 200 , which gives the height (in meters) of an object that has fallen for t seconds from a height of 200 meters. The velocity at time t = a seconds is given by lim t → a s ( a ) − s ( t ) a − t ⋅ Find the velocity of the object when t = 3 .
Free-Falling Object In Exercises 107 and 108, use the position function s ( t ) = − 4.9 t 2 + 200 , which gives the height (in meters) of an object that has fallen for t seconds from a height of 200 meters. The velocity at time t = a seconds is given by lim t → a s ( a ) − s ( t ) a − t ⋅ Find the velocity of the object when t = 3 .
Solution Summary: The author calculates the velocity of an object at t=3 seconds. The position function gives the height (in feet) of the object.
Free-Falling Object In Exercises 107 and 108, use the position function
s
(
t
)
=
−
4.9
t
2
+
200
, which gives the height (in meters) of an object that has fallen for t seconds from a height of 200 meters. The velocity at time
t
=
a
seconds is given by
The ordered pairs below give the intensities y in microwatts per square centimeter of the light measured by a light probe located x centimeters from a light source.A model that approximates the data is y = 171.33/x2. (a) Use a graphing utility to plot the data points and the model in the same viewing window. (b) Use the model to approximate the light intensity 25 centimeters from the light source.
gn) / Final Exam Sem2, 2020-2021 Part 2
a) Find the points at which the tangent line to the graph of
function f(x)=2x-24x+6 has slope equal to 0
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