Explanation Given Information: The provided expression is 1 1 9 × 3 . Formula used: Steps to multiply the mixed numbers and whole numbers. 1. Express the mixed numbers and whole numbers in the form of improper fractions. 2. Reduce the numerators and denominators. 3. Perform the multiplication of the fractions. 4. Reduce the fraction in its lowest terms and write as a whole number or mixed number as required. For any mixed fraction, a b c = ( a × c ) + b c , where c ≠ 0 . Calculation: Consider the expression, 1 1 9 × 3 Express the mixed numbers as improper fractions, 1 1 9 × 3 = (

11th Edition

ISBN: 9780134496436

Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble

Publisher: PEARSON

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Chapter 2.3, Problem 1-4SC

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To calculate: The product 119×3 as a proper fraction or mixed number in lowest terms.

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Chapter 2.3, Problem 1-3SC

Chapter 2.3, Problem 1-5SC

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Chapter 2 Solutions

Business Math (11th Edition)

Ch. 2.1 - Prob. 1-1SC Ch. 2.1 - Prob. 1-2SC Ch. 2.1 - Prob. 1-3SC Ch. 2.1 - Prob. 1-4SC Ch. 2.1 - Prob. 1-5SC Ch. 2.1 - Prob. 1-6SC Ch. 2.1 - Prob. 2-1SC Ch. 2.1 - Prob. 2-2SC Ch. 2.1 - Prob. 2-3SC Ch. 2.1 - Prob. 2-4SC

Ch. 2.1 - Prob. 2-5SC Ch. 2.1 - Prob. 3-1SC Ch. 2.1 - Prob. 3-2SC Ch. 2.1 - Prob. 3-3SC Ch. 2.1 - Prob. 3-4SC Ch. 2.1 - Prob. 3-5SC Ch. 2.1 - Prob. 4-1SC Ch. 2.1 - Prob. 4-2SC Ch. 2.1 - Prob. 4-3SC Ch. 2.1 - Prob. 4-4SC Ch. 2.1 - Prob. 4-5SC Ch. 2.1 - Prob. 4-6SC Ch. 2.1 - Prob. 4-7SC Ch. 2.1 - Prob. 4-8SC Ch. 2.1 - Prob. 5-1SC Ch. 2.1 - Prob. 5-2SC Ch. 2.1 - Prob. 5-3SC Ch. 2.1 - Prob. 5-4SC Ch. 2.1 - Prob. 5-5SC Ch. 2.1 - Prob. 5-6SC Ch. 2.1 - Prob. 1SE Ch. 2.1 - Prob. 2SE Ch. 2.1 - Prob. 3SE Ch. 2.1 - Prob. 4SE Ch. 2.1 - Prob. 5SE Ch. 2.1 - Prob. 6SE Ch. 2.1 - Prob. 7SE Ch. 2.1 - Prob. 8SE Ch. 2.1 - Prob. 9SE Ch. 2.1 - Prob. 10SE Ch. 2.1 - Prob. 11SE Ch. 2.1 - Prob. 12SE Ch. 2.1 - Prob. 13SE Ch. 2.1 - Prob. 14SE Ch. 2.1 - Prob. 15SE Ch. 2.1 - Prob. 16SE Ch. 2.1 - Prob. 17SE Ch. 2.1 - Prob. 18SE Ch. 2.1 - Prob. 19SE Ch. 2.1 - Prob. 20SE Ch. 2.1 - Prob. 21SE Ch. 2.1 - Prob. 22SE Ch. 2.1 - Prob. 23SE Ch. 2.1 - Prob. 24SE Ch. 2.1 - Prob. 25SE Ch. 2.1 - Prob. 26SE Ch. 2.1 - Prob. 27SE Ch. 2.1 - 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Prob. 11SE Ch. 2.2 - Prob. 12SE Ch. 2.2 - Prob. 13SE Ch. 2.2 - Prob. 14SE Ch. 2.2 - Prob. 15SE Ch. 2.2 - Prob. 16SE Ch. 2.2 - Prob. 17SE Ch. 2.2 - Prob. 18SE Ch. 2.2 - Prob. 19SE Ch. 2.2 - Prob. 20SE Ch. 2.2 - Prob. 21SE Ch. 2.2 - Prob. 22SE Ch. 2.2 - Prob. 23SE Ch. 2.2 - Prob. 24SE Ch. 2.2 - Prob. 25SE Ch. 2.2 - Prob. 26SE Ch. 2.2 - Prob. 27SE Ch. 2.2 - Prob. 28SE Ch. 2.2 - Prob. 29SE Ch. 2.2 - Prob. 30SE Ch. 2.3 - Prob. 1-1SC Ch. 2.3 - Prob. 1-2SC Ch. 2.3 - Prob. 1-3SC Ch. 2.3 - Prob. 1-4SC Ch. 2.3 - Prob. 1-5SC Ch. 2.3 - Prob. 1-6SC Ch. 2.3 - Prob. 1-7SC Ch. 2.3 - Prob. 2-1SC Ch. 2.3 - Prob. 2-2SC Ch. 2.3 - Prob. 2-3SC Ch. 2.3 - Prob. 2-4SC Ch. 2.3 - Prob. 2-5SC Ch. 2.3 - Prob. 2-6SC Ch. 2.3 - Prob. 2-7SC Ch. 2.3 - Prob. 1SE Ch. 2.3 - Prob. 2SE Ch. 2.3 - Prob. 3SE Ch. 2.3 - Prob. 4SE Ch. 2.3 - Prob. 5SE Ch. 2.3 - Prob. 6SE Ch. 2.3 - Prob. 7SE Ch. 2.3 - Prob. 8SE Ch. 2.3 - Prob. 9SE Ch. 2.3 - Prob. 10SE Ch. 2.3 - Prob. 11SE Ch. 2.3 - Prob. 12SE Ch. 2.3 - Prob. 13SE Ch. 2.3 - Prob. 14SE Ch. 2.3 - Prob. 15SE Ch. 2.3 - Prob. 16SE Ch. 2.3 - Prob. 17SE Ch. 2.3 - Prob. 18SE Ch. 2.3 - Prob. 19SE Ch. 2.3 - Prob. 20SE Ch. 2.3 - Prob. 21SE Ch. 2.3 - Prob. 22SE Ch. 2.3 - Prob. 23SE Ch. 2.3 - Prob. 24SE Ch. 2 - Prob. 1ES Ch. 2 - Prob. 2ES Ch. 2 - Prob. 3ES Ch. 2 - Prob. 4ES Ch. 2 - Prob. 5ES Ch. 2 - Prob. 6ES Ch. 2 - Prob. 7ES Ch. 2 - Prob. 8ES Ch. 2 - Prob. 9ES Ch. 2 - Prob. 10ES Ch. 2 - Prob. 11ES Ch. 2 - Prob. 12ES Ch. 2 - Prob. 13ES Ch. 2 - Prob. 14ES Ch. 2 - Prob. 15ES Ch. 2 - Prob. 16ES Ch. 2 - Prob. 17ES Ch. 2 - Prob. 18ES Ch. 2 - Prob. 19ES Ch. 2 - Prob. 20ES Ch. 2 - Prob. 21ES Ch. 2 - Prob. 22ES Ch. 2 - Prob. 23ES Ch. 2 - Prob. 24ES Ch. 2 - Prob. 25ES Ch. 2 - Prob. 26ES Ch. 2 - Prob. 27ES Ch. 2 - Prob. 28ES Ch. 2 - Prob. 29ES Ch. 2 - Prob. 30ES Ch. 2 - Prob. 31ES Ch. 2 - Prob. 32ES Ch. 2 - Prob. 33ES Ch. 2 - Prob. 34ES Ch. 2 - Prob. 35ES Ch. 2 - Prob. 36ES Ch. 2 - Prob. 37ES Ch. 2 - Prob. 38ES Ch. 2 - Prob. 39ES Ch. 2 - Prob. 40ES Ch. 2 - Prob. 41ES Ch. 2 - Prob. 42ES Ch. 2 - Prob. 43ES Ch. 2 - 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Prob. 15PT Ch. 2 - Prob. 16PT Ch. 2 - Prob. 17PT Ch. 2 - Prob. 18PT Ch. 2 - Prob. 19PT Ch. 2 - Prob. 20PT Ch. 2 - Prob. 21PT Ch. 2 - Prob. 22PT Ch. 2 - Prob. 23PT Ch. 2 - Prob. 24PT Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 1CP Ch. 2 - Prob. 2CP Ch. 2 - Prob. 1CS1 Ch. 2 - Prob. 2CS1 Ch. 2 - Prob. 3CS1 Ch. 2 - Prob. 1CS2 Ch. 2 - Prob. 2CS2 Ch. 2 - Prob. 3CS2 Ch. 2 - Prob. 4CS2

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The product 1 1 9 × 3 as a proper fraction or mixed number in lowest terms.

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To calculate: The product 119×3 as a proper fraction or mixed number in lowest terms.

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Chapter 2 Solutions