Explanation Given Information: The provided numbers are 39 , 51 and the fraction is, 39 51 . A fraction in lowest term has a numerator and denominator that both can’t be evenly divided by the same whole number other than 1 . To determine the GCD use the numerator 39 as the first divisor and the denominator 51 as dividend. Now divide the terms as, 1 R12 39 51 39 _ 12 Now divide the first divisor 39 by the first remainder 12 as, 3 R3 12 39 36 _ 03

11th Edition

ISBN: 9780134496436

Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble

Publisher: PEARSON

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Chapter 2.1, Problem 4-6SC

To determine

The greatest common division (GCD) of 39 and 51 then to find the lowest term fraction using the method of GCD for the fraction 3951.

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Chapter 2.1, Problem 4-5SC

Chapter 2.1, Problem 4-7SC

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Chapter 2 Solutions

Business Math (11th Edition)

Ch. 2.1 - Prob. 1-1SC Ch. 2.1 - Prob. 1-2SC Ch. 2.1 - Prob. 1-3SC Ch. 2.1 - Prob. 1-4SC Ch. 2.1 - Prob. 1-5SC Ch. 2.1 - Prob. 1-6SC Ch. 2.1 - Prob. 2-1SC Ch. 2.1 - Prob. 2-2SC Ch. 2.1 - Prob. 2-3SC Ch. 2.1 - Prob. 2-4SC

Ch. 2.1 - Prob. 2-5SC Ch. 2.1 - Prob. 3-1SC Ch. 2.1 - Prob. 3-2SC Ch. 2.1 - Prob. 3-3SC Ch. 2.1 - Prob. 3-4SC Ch. 2.1 - Prob. 3-5SC Ch. 2.1 - Prob. 4-1SC Ch. 2.1 - Prob. 4-2SC Ch. 2.1 - Prob. 4-3SC Ch. 2.1 - Prob. 4-4SC Ch. 2.1 - Prob. 4-5SC Ch. 2.1 - Prob. 4-6SC Ch. 2.1 - Prob. 4-7SC Ch. 2.1 - Prob. 4-8SC Ch. 2.1 - Prob. 5-1SC Ch. 2.1 - Prob. 5-2SC Ch. 2.1 - Prob. 5-3SC Ch. 2.1 - Prob. 5-4SC Ch. 2.1 - Prob. 5-5SC Ch. 2.1 - Prob. 5-6SC Ch. 2.1 - Prob. 1SE Ch. 2.1 - Prob. 2SE Ch. 2.1 - Prob. 3SE Ch. 2.1 - Prob. 4SE Ch. 2.1 - Prob. 5SE Ch. 2.1 - Prob. 6SE Ch. 2.1 - Prob. 7SE Ch. 2.1 - Prob. 8SE Ch. 2.1 - Prob. 9SE Ch. 2.1 - Prob. 10SE Ch. 2.1 - Prob. 11SE Ch. 2.1 - Prob. 12SE Ch. 2.1 - Prob. 13SE Ch. 2.1 - Prob. 14SE Ch. 2.1 - Prob. 15SE Ch. 2.1 - Prob. 16SE Ch. 2.1 - Prob. 17SE Ch. 2.1 - Prob. 18SE Ch. 2.1 - Prob. 19SE Ch. 2.1 - Prob. 20SE Ch. 2.1 - Prob. 21SE Ch. 2.1 - Prob. 22SE Ch. 2.1 - Prob. 23SE Ch. 2.1 - Prob. 24SE Ch. 2.1 - Prob. 25SE Ch. 2.1 - Prob. 26SE Ch. 2.1 - Prob. 27SE Ch. 2.1 - 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Prob. 11SE Ch. 2.2 - Prob. 12SE Ch. 2.2 - Prob. 13SE Ch. 2.2 - Prob. 14SE Ch. 2.2 - Prob. 15SE Ch. 2.2 - Prob. 16SE Ch. 2.2 - Prob. 17SE Ch. 2.2 - Prob. 18SE Ch. 2.2 - Prob. 19SE Ch. 2.2 - Prob. 20SE Ch. 2.2 - Prob. 21SE Ch. 2.2 - Prob. 22SE Ch. 2.2 - Prob. 23SE Ch. 2.2 - Prob. 24SE Ch. 2.2 - Prob. 25SE Ch. 2.2 - Prob. 26SE Ch. 2.2 - Prob. 27SE Ch. 2.2 - Prob. 28SE Ch. 2.2 - Prob. 29SE Ch. 2.2 - Prob. 30SE Ch. 2.3 - Prob. 1-1SC Ch. 2.3 - Prob. 1-2SC Ch. 2.3 - Prob. 1-3SC Ch. 2.3 - Prob. 1-4SC Ch. 2.3 - Prob. 1-5SC Ch. 2.3 - Prob. 1-6SC Ch. 2.3 - Prob. 1-7SC Ch. 2.3 - Prob. 2-1SC Ch. 2.3 - Prob. 2-2SC Ch. 2.3 - Prob. 2-3SC Ch. 2.3 - Prob. 2-4SC Ch. 2.3 - Prob. 2-5SC Ch. 2.3 - Prob. 2-6SC Ch. 2.3 - Prob. 2-7SC Ch. 2.3 - Prob. 1SE Ch. 2.3 - Prob. 2SE Ch. 2.3 - Prob. 3SE Ch. 2.3 - Prob. 4SE Ch. 2.3 - Prob. 5SE Ch. 2.3 - Prob. 6SE Ch. 2.3 - Prob. 7SE Ch. 2.3 - Prob. 8SE Ch. 2.3 - Prob. 9SE Ch. 2.3 - Prob. 10SE Ch. 2.3 - Prob. 11SE Ch. 2.3 - Prob. 12SE Ch. 2.3 - Prob. 13SE Ch. 2.3 - Prob. 14SE Ch. 2.3 - Prob. 15SE Ch. 2.3 - Prob. 16SE Ch. 2.3 - Prob. 17SE Ch. 2.3 - Prob. 18SE Ch. 2.3 - Prob. 19SE Ch. 2.3 - Prob. 20SE Ch. 2.3 - Prob. 21SE Ch. 2.3 - Prob. 22SE Ch. 2.3 - Prob. 23SE Ch. 2.3 - Prob. 24SE Ch. 2 - Prob. 1ES Ch. 2 - Prob. 2ES Ch. 2 - Prob. 3ES Ch. 2 - Prob. 4ES Ch. 2 - Prob. 5ES Ch. 2 - Prob. 6ES Ch. 2 - Prob. 7ES Ch. 2 - Prob. 8ES Ch. 2 - Prob. 9ES Ch. 2 - Prob. 10ES Ch. 2 - Prob. 11ES Ch. 2 - Prob. 12ES Ch. 2 - Prob. 13ES Ch. 2 - Prob. 14ES Ch. 2 - Prob. 15ES Ch. 2 - Prob. 16ES Ch. 2 - Prob. 17ES Ch. 2 - Prob. 18ES Ch. 2 - Prob. 19ES Ch. 2 - Prob. 20ES Ch. 2 - Prob. 21ES Ch. 2 - Prob. 22ES Ch. 2 - Prob. 23ES Ch. 2 - Prob. 24ES Ch. 2 - Prob. 25ES Ch. 2 - Prob. 26ES Ch. 2 - Prob. 27ES Ch. 2 - Prob. 28ES Ch. 2 - Prob. 29ES Ch. 2 - Prob. 30ES Ch. 2 - Prob. 31ES Ch. 2 - Prob. 32ES Ch. 2 - Prob. 33ES Ch. 2 - Prob. 34ES Ch. 2 - Prob. 35ES Ch. 2 - Prob. 36ES Ch. 2 - Prob. 37ES Ch. 2 - Prob. 38ES Ch. 2 - Prob. 39ES Ch. 2 - Prob. 40ES Ch. 2 - Prob. 41ES Ch. 2 - Prob. 42ES Ch. 2 - Prob. 43ES Ch. 2 - 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The greatest common division (GCD) of 39 and 51 then to find the lowest term fraction using the method of GCD for the fraction 39 51 .

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The greatest common division (GCD) of 39 and 51 then to find the lowest term fraction using the method of GCD for the fraction 3951.

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Chapter 2 Solutions