
Business Math (11th Edition)
11th Edition
ISBN: 9780134496436
Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 2, Problem 46ES
To determine
To calculate: The total length of lumber if the three pieces measures
Expert Solution & Answer

Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Solve the following nonlinear system using Newton's method
1
f1(x1, x2, x3)=3x₁ = cos(x2x3)
-
-
2
f2(x1, x2, x3) = x² - 81(x2 +0.1)² + sin x3 + 1.06
f3(x1, x2, x3) = ex1x2 +20x3 +
Using x (0)
X1 X2 X3
10π-3
3
= 0.1, 0.1, 0.1 as initial conditio
Use the graph of the function y = g(x) below to answer the questions.
y'
-5
-4
4-
3-
27
-2
-3+
-4
x
4
(a) Is g(-2) negative?
Yes
No
(b) For which value(s) of x is g(x) > 0?
Write your answer using interval notation.
☐
(c) For which value(s) of x is g(x) = 0?
If there is more than one value, separate them with commas.
0,0... (0,0) (0,0)
(0,0) (0,0) OVO
0
It is given that E4E3E2E1A=⎡⎣⎢⎢⎢−1002−40488⎤⎦⎥⎥⎥.
Here the matrices E4, E3, E2, and, E1 are:
E1=⎡⎣⎢⎢⎢100010008⎤⎦⎥⎥⎥E2=⎡⎣⎢⎢⎢100010−501⎤⎦⎥⎥⎥E3=⎡⎣⎢⎢⎢1000−10001⎤⎦⎥⎥⎥E4=⎡⎣⎢⎢⎢001010100⎤⎦⎥⎥⎥
Chapter 2 Solutions
Business Math (11th Edition)
Ch. 2.1 - Prob. 1-1SCCh. 2.1 - Prob. 1-2SCCh. 2.1 - Prob. 1-3SCCh. 2.1 - Prob. 1-4SCCh. 2.1 - Prob. 1-5SCCh. 2.1 - Prob. 1-6SCCh. 2.1 - Prob. 2-1SCCh. 2.1 - Prob. 2-2SCCh. 2.1 - Prob. 2-3SCCh. 2.1 - Prob. 2-4SC
Ch. 2.1 - Prob. 2-5SCCh. 2.1 - Prob. 3-1SCCh. 2.1 - Prob. 3-2SCCh. 2.1 - Prob. 3-3SCCh. 2.1 - Prob. 3-4SCCh. 2.1 - Prob. 3-5SCCh. 2.1 - Prob. 4-1SCCh. 2.1 - Prob. 4-2SCCh. 2.1 - Prob. 4-3SCCh. 2.1 - Prob. 4-4SCCh. 2.1 - Prob. 4-5SCCh. 2.1 - Prob. 4-6SCCh. 2.1 - Prob. 4-7SCCh. 2.1 - Prob. 4-8SCCh. 2.1 - Prob. 5-1SCCh. 2.1 - Prob. 5-2SCCh. 2.1 - Prob. 5-3SCCh. 2.1 - Prob. 5-4SCCh. 2.1 - Prob. 5-5SCCh. 2.1 - Prob. 5-6SCCh. 2.1 - Prob. 1SECh. 2.1 - Prob. 2SECh. 2.1 - Prob. 3SECh. 2.1 - Prob. 4SECh. 2.1 - Prob. 5SECh. 2.1 - Prob. 6SECh. 2.1 - Prob. 7SECh. 2.1 - Prob. 8SECh. 2.1 - Prob. 9SECh. 2.1 - Prob. 10SECh. 2.1 - Prob. 11SECh. 2.1 - Prob. 12SECh. 2.1 - Prob. 13SECh. 2.1 - Prob. 14SECh. 2.1 - Prob. 15SECh. 2.1 - Prob. 16SECh. 2.1 - Prob. 17SECh. 2.1 - Prob. 18SECh. 2.1 - Prob. 19SECh. 2.1 - Prob. 20SECh. 2.1 - Prob. 21SECh. 2.1 - Prob. 22SECh. 2.1 - Prob. 23SECh. 2.1 - Prob. 24SECh. 2.1 - Prob. 25SECh. 2.1 - Prob. 26SECh. 2.1 - Prob. 27SECh. 2.1 - Prob. 28SECh. 2.1 - Prob. 29SECh. 2.1 - Prob. 30SECh. 2.1 - Prob. 31SECh. 2.1 - Prob. 32SECh. 2.1 - Prob. 33SECh. 2.1 - Prob. 34SECh. 2.1 - Prob. 35SECh. 2.1 - Prob. 36SECh. 2.1 - Prob. 37SECh. 2.1 - Prob. 38SECh. 2.2 - Prob. 1-1SCCh. 2.2 - Prob. 1-2SCCh. 2.2 - Prob. 1-3SCCh. 2.2 - Prob. 1-4SCCh. 2.2 - Prob. 1-5SCCh. 2.2 - Prob. 2-1SCCh. 2.2 - Prob. 2-2SCCh. 2.2 - Prob. 2-3SCCh. 2.2 - Prob. 2-4SCCh. 2.2 - Prob. 2-5SCCh. 2.2 - Prob. 3-1SCCh. 2.2 - Prob. 3-2SCCh. 2.2 - Prob. 3-3SCCh. 2.2 - Prob. 3-4SCCh. 2.2 - Prob. 3-5SCCh. 2.2 - Prob. 3-6SCCh. 2.2 - Prob. 4-1SCCh. 2.2 - Prob. 4-2SCCh. 2.2 - Prob. 4-3SCCh. 2.2 - Prob. 4-4SCCh. 2.2 - Prob. 4-5SCCh. 2.2 - Prob. 4-6SCCh. 2.2 - Prob. 4-7SCCh. 2.2 - Prob. 4-8SCCh. 2.2 - Prob. 4-9SCCh. 2.2 - Prob. 4-10SCCh. 2.2 - Prob. 1SECh. 2.2 - Prob. 2SECh. 2.2 - Prob. 3SECh. 2.2 - Prob. 4SECh. 2.2 - Prob. 5SECh. 2.2 - Prob. 6SECh. 2.2 - Prob. 7SECh. 2.2 - Prob. 8SECh. 2.2 - Prob. 9SECh. 2.2 - Prob. 10SECh. 2.2 - Prob. 11SECh. 2.2 - Prob. 12SECh. 2.2 - Prob. 13SECh. 2.2 - Prob. 14SECh. 2.2 - Prob. 15SECh. 2.2 - Prob. 16SECh. 2.2 - Prob. 17SECh. 2.2 - Prob. 18SECh. 2.2 - Prob. 19SECh. 2.2 - Prob. 20SECh. 2.2 - Prob. 21SECh. 2.2 - Prob. 22SECh. 2.2 - Prob. 23SECh. 2.2 - Prob. 24SECh. 2.2 - Prob. 25SECh. 2.2 - Prob. 26SECh. 2.2 - Prob. 27SECh. 2.2 - Prob. 28SECh. 2.2 - Prob. 29SECh. 2.2 - Prob. 30SECh. 2.3 - Prob. 1-1SCCh. 2.3 - Prob. 1-2SCCh. 2.3 - Prob. 1-3SCCh. 2.3 - Prob. 1-4SCCh. 2.3 - Prob. 1-5SCCh. 2.3 - Prob. 1-6SCCh. 2.3 - Prob. 1-7SCCh. 2.3 - Prob. 2-1SCCh. 2.3 - Prob. 2-2SCCh. 2.3 - Prob. 2-3SCCh. 2.3 - Prob. 2-4SCCh. 2.3 - Prob. 2-5SCCh. 2.3 - Prob. 2-6SCCh. 2.3 - Prob. 2-7SCCh. 2.3 - Prob. 1SECh. 2.3 - Prob. 2SECh. 2.3 - Prob. 3SECh. 2.3 - Prob. 4SECh. 2.3 - Prob. 5SECh. 2.3 - Prob. 6SECh. 2.3 - Prob. 7SECh. 2.3 - Prob. 8SECh. 2.3 - Prob. 9SECh. 2.3 - Prob. 10SECh. 2.3 - Prob. 11SECh. 2.3 - Prob. 12SECh. 2.3 - Prob. 13SECh. 2.3 - Prob. 14SECh. 2.3 - Prob. 15SECh. 2.3 - Prob. 16SECh. 2.3 - Prob. 17SECh. 2.3 - Prob. 18SECh. 2.3 - Prob. 19SECh. 2.3 - Prob. 20SECh. 2.3 - Prob. 21SECh. 2.3 - Prob. 22SECh. 2.3 - Prob. 23SECh. 2.3 - Prob. 24SECh. 2 - Prob. 1ESCh. 2 - Prob. 2ESCh. 2 - Prob. 3ESCh. 2 - Prob. 4ESCh. 2 - Prob. 5ESCh. 2 - Prob. 6ESCh. 2 - Prob. 7ESCh. 2 - Prob. 8ESCh. 2 - Prob. 9ESCh. 2 - Prob. 10ESCh. 2 - Prob. 11ESCh. 2 - Prob. 12ESCh. 2 - Prob. 13ESCh. 2 - Prob. 14ESCh. 2 - Prob. 15ESCh. 2 - Prob. 16ESCh. 2 - Prob. 17ESCh. 2 - Prob. 18ESCh. 2 - Prob. 19ESCh. 2 - Prob. 20ESCh. 2 - Prob. 21ESCh. 2 - Prob. 22ESCh. 2 - Prob. 23ESCh. 2 - Prob. 24ESCh. 2 - Prob. 25ESCh. 2 - Prob. 26ESCh. 2 - Prob. 27ESCh. 2 - Prob. 28ESCh. 2 - Prob. 29ESCh. 2 - Prob. 30ESCh. 2 - Prob. 31ESCh. 2 - Prob. 32ESCh. 2 - Prob. 33ESCh. 2 - Prob. 34ESCh. 2 - Prob. 35ESCh. 2 - Prob. 36ESCh. 2 - Prob. 37ESCh. 2 - Prob. 38ESCh. 2 - Prob. 39ESCh. 2 - Prob. 40ESCh. 2 - Prob. 41ESCh. 2 - Prob. 42ESCh. 2 - Prob. 43ESCh. 2 - Prob. 44ESCh. 2 - Prob. 45ESCh. 2 - Prob. 46ESCh. 2 - Prob. 47ESCh. 2 - Prob. 48ESCh. 2 - Prob. 49ESCh. 2 - Prob. 50ESCh. 2 - Prob. 51ESCh. 2 - Prob. 52ESCh. 2 - Prob. 53ESCh. 2 - Prob. 54ESCh. 2 - Prob. 55ESCh. 2 - Prob. 56ESCh. 2 - Prob. 57ESCh. 2 - Prob. 58ESCh. 2 - Prob. 59ESCh. 2 - Prob. 60ESCh. 2 - Prob. 61ESCh. 2 - Prob. 62ESCh. 2 - Prob. 63ESCh. 2 - Prob. 64ESCh. 2 - Prob. 65ESCh. 2 - Prob. 66ESCh. 2 - Prob. 67ESCh. 2 - Prob. 68ESCh. 2 - Prob. 69ESCh. 2 - Prob. 70ESCh. 2 - Prob. 71ESCh. 2 - Prob. 72ESCh. 2 - Prob. 73ESCh. 2 - Prob. 74ESCh. 2 - Prob. 75ESCh. 2 - Prob. 76ESCh. 2 - Prob. 78ESCh. 2 - Prob. 79ESCh. 2 - Prob. 80ESCh. 2 - Prob. 81ESCh. 2 - Prob. 82ESCh. 2 - Prob. 83ESCh. 2 - Prob. 84ESCh. 2 - Prob. 1PTCh. 2 - Prob. 2PTCh. 2 - Prob. 3PTCh. 2 - Prob. 4PTCh. 2 - Prob. 5PTCh. 2 - Prob. 6PTCh. 2 - Prob. 7PTCh. 2 - Prob. 8PTCh. 2 - Prob. 9PTCh. 2 - Prob. 10PTCh. 2 - Prob. 11PTCh. 2 - Prob. 12PTCh. 2 - Prob. 13PTCh. 2 - Prob. 14PTCh. 2 - Prob. 15PTCh. 2 - Prob. 16PTCh. 2 - Prob. 17PTCh. 2 - Prob. 18PTCh. 2 - Prob. 19PTCh. 2 - Prob. 20PTCh. 2 - Prob. 21PTCh. 2 - Prob. 22PTCh. 2 - Prob. 23PTCh. 2 - Prob. 24PTCh. 2 - Prob. 1CTCh. 2 - Prob. 2CTCh. 2 - Prob. 3CTCh. 2 - Prob. 4CTCh. 2 - Prob. 5CTCh. 2 - Prob. 6CTCh. 2 - Prob. 7CTCh. 2 - Prob. 8CTCh. 2 - Prob. 9CTCh. 2 - Prob. 10CTCh. 2 - Prob. 11CTCh. 2 - Prob. 12CTCh. 2 - Prob. 1CPCh. 2 - Prob. 2CPCh. 2 - Prob. 1CS1Ch. 2 - Prob. 2CS1Ch. 2 - Prob. 3CS1Ch. 2 - Prob. 1CS2Ch. 2 - Prob. 2CS2Ch. 2 - Prob. 3CS2Ch. 2 - Prob. 4CS2
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.Similar questions
- It is given that E4E3E2E1A=⎡⎣⎢⎢⎢−1002−40488⎤⎦⎥⎥⎥. Here the matrices E4, E3, E2, and, E1 are: E1=⎡⎣⎢⎢⎢100010008⎤⎦⎥⎥⎥E2=⎡⎣⎢⎢⎢100010−501⎤⎦⎥⎥⎥E3=⎡⎣⎢⎢⎢1000−10001⎤⎦⎥⎥⎥E4=⎡⎣⎢⎢⎢001010100⎤⎦⎥⎥⎥ What is the determinant of A?arrow_forwardUse the graph of the function y = f(x) below to answer the questions. 4 3- 2+ 1 -5 -4 -3 -2 -1 3 -1+ -2+ -3+ -4- -5+ (a) Isf (3) negative? Yes No (b) For which value(s) of x is f(x) = 0? If there is more than one value, separate them with commas. (c) For which value(s) of x is f(x) ≤0? Write your answer using interval notation.arrow_forwardSolve the differential equation. 37 6 dy = 2x³y7 - 4x³ dxarrow_forward
- Name: Date: Transformations of Quadratic Functions y=a(x-h)²+k Describe all transformations for each quadratic function. 1. 2. -2 2 -4 2 2arrow_forward5:45 Done ⚫ myopenmath.com Oli Score on last try: 0 of 12 pts. See Details for more. > Next question You can retry this question. below 384 Draw a graph that models the connecting relationships in the floorplan below. The vertices represent the rooms and the edges represent doorways connecting the rooms. Vertex D represents the outdoors. D A B C Is it possible to find a path through the house that uses each doorway once? If so, enter the sequence of rooms(vertices) visited, for example ABCDA. If it is not possible, enter DNE. DCBACD Question Help: ☑Video 1 > Video 2 Submit Questionarrow_forwardUse the graph of the function y = f(x) below to answer the questions. У 5- 4- 3- 2+ 1- 4 -3 -2 -1 3 4 -N -2 -3- -4 -5- (a) Isf(1) positive? Yes No (b) For which value(s) of x is f(x) > 0? Write your answer using interval notation. (c) For which value(s) of x is f(x) = 0? If there is more than one value, separate them with commas. 0,0,... (0,0) (0,0) (0,0) (0,0) QUO 0arrow_forward
- Consider the following Gauss elimination: What is the determinant of A ?arrow_forward2. (a) State Fermat's principle for the propagation of a light ray from point P at (x1,y1) to Q at (x2, y2), expressing the principle as a problem in Calculus of Variations. (b) Suppose c(y) is the speed of light in a medium, given by c(y) Y where a is a constant. Find the path of a light ray between the points P: (−1,3) and Q (1, 3). Is there more than one possible path? (c) Sketch the path of the light ray, and interpret what an observer at Q would see if there were a light source at P.arrow_forwardA. 90.6 square meters B. 91.4 square meters C. 92.5 square meters D. 93.7 square metersarrow_forward
- An ice cream cone is 10cm deep and 4cm across the opening of the cone. Two sphere-shaped scoops of ice cream, which also have diameters of 4cm, are placed on top of the cone. Use π≈3.14 and round your answers to the nearest hundredth.a) What is the volume of the cone? cubic centimetersb) What is the total volume of the two sphere-shaped scoops of ice cream? cubic centimetersarrow_forwardSolve for xx. Round to the nearest tenth, if necessary. DEF61°x11 Answer Attempt 1 out of 2arrow_forwardOn a given day, the sea level pressure is 1013.2 hPA. The temperature at 3,000 ft AMSL is given as minus 4°C. The temperature difference compared with the ISA is: Can you give me a step by step explanation ISA - 13°C ISA - 4°C (c)ISA - 10°C (d) ISA +10°C ISA is +15 Celsius Answer is -13Celsiusarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Discrete Mathematics and Its Applications ( 8th I...MathISBN:9781259676512Author:Kenneth H RosenPublisher:McGraw-Hill EducationMathematics for Elementary Teachers with Activiti...MathISBN:9780134392790Author:Beckmann, SybillaPublisher:PEARSON
- Thinking Mathematically (7th Edition)MathISBN:9780134683713Author:Robert F. BlitzerPublisher:PEARSONDiscrete Mathematics With ApplicationsMathISBN:9781337694193Author:EPP, Susanna S.Publisher:Cengage Learning,Pathways To Math Literacy (looseleaf)MathISBN:9781259985607Author:David Sobecki Professor, Brian A. MercerPublisher:McGraw-Hill Education

Discrete Mathematics and Its Applications ( 8th I...
Math
ISBN:9781259676512
Author:Kenneth H Rosen
Publisher:McGraw-Hill Education

Mathematics for Elementary Teachers with Activiti...
Math
ISBN:9780134392790
Author:Beckmann, Sybilla
Publisher:PEARSON


Thinking Mathematically (7th Edition)
Math
ISBN:9780134683713
Author:Robert F. Blitzer
Publisher:PEARSON

Discrete Mathematics With Applications
Math
ISBN:9781337694193
Author:EPP, Susanna S.
Publisher:Cengage Learning,

Pathways To Math Literacy (looseleaf)
Math
ISBN:9781259985607
Author:David Sobecki Professor, Brian A. Mercer
Publisher:McGraw-Hill Education
Use of ALGEBRA in REAL LIFE; Author: Fast and Easy Maths !;https://www.youtube.com/watch?v=9_PbWFpvkDc;License: Standard YouTube License, CC-BY
Compound Interest Formula Explained, Investment, Monthly & Continuously, Word Problems, Algebra; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=P182Abv3fOk;License: Standard YouTube License, CC-BY
Applications of Algebra (Digit, Age, Work, Clock, Mixture and Rate Problems); Author: EngineerProf PH;https://www.youtube.com/watch?v=Y8aJ_wYCS2g;License: Standard YouTube License, CC-BY