Explanation Given Information: The mixed fraction as: 15 ÷ 3 4 Formula used: The fraction is defined as: Numerator Denominator Steps to determine the reciprocal of a number. 1. Write the number as a fraction, in case the number is in mixed fraction. 2. Interchange the numerator and denominator of the fraction. The reciprocal of any fraction a b is b a . For any mixed fraction, a b c = ( a × c ) + b c , where c ≠ 0 . Steps to determine the division of two fractions 1: Write the reciprocal of the divisor. 2: Multiply the reciprocal of the divisor with the dividend.in which multiply numerator with numerator and denominator with denominator. Calculation: Consider the mixed fraction as: 15 ÷ 3 4 First find the reciprocal of the divisor 3 4 Now in reciprocal fraction the numerator will become the denominator and vice versa

11th Edition

ISBN: 9780134496436

Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble

Publisher: PEARSON

See similar textbooks

Concept explainers

Unitary Method

The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.

Speed, Time, and Distance

Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …

Profit and Loss

The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.

Units and Measurements

Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…

Videos

Question

Chapter 2, Problem 76ES

To determine

To calculate: The division of the fraction 15÷34 reduce the quotient into lowest terms and if appropriate write it as whole or mixed numbers.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 2, Problem 75ES

Chapter 2, Problem 77ES

Students have asked these similar questions

Use a graph of f to estimate lim f(x) or to show that the limit does not exist. Evaluate f(x) near x = a to support your conjecture. Complete parts (a) and (b). x-a f(x)= 1 - cos (4x-4) 3(x-1)² ; a = 1 a. Use a graphing utility to graph f. Select the correct graph below.. A. W → ✓ Each graph is displayed in a [- 1,3] by [0,5] window. B. in ✓ ○ C. und ☑ Use the graphing utility to estimate lim f(x). Select the correct choice below and, if necessary, fill in the answer box to complete your choice. x-1 ○ A. The limit appears to be approximately ☐ . (Round to the nearest tenth as needed.) B. The limit does not exist. b. Evaluate f(x) for values of x near 1 to support your conjecture. X 0.9 0.99 0.999 1.001 1.01 1.1 f(x) ○ D. + ☑ (Round to six decimal places as needed.) Does the table from the previous step support your conjecture? A. No, it does not. The function f(x) approaches a different value in the table of values than in the graph, after the approached values are rounded to the…

x²-19x+90 Let f(x) = . Complete parts (a) through (c) below. x-a a. For what values of a, if any, does lim f(x) equal a finite number? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. x→a+ ○ A. a= (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. There are no values of a for which the limit equals a finite number. b. For what values of a, if any, does lim f(x) = ∞o? Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. x→a+ A. (Type integers or simplified fractions) C. There are no values of a that satisfy lim f(x) = ∞. + x-a c. For what values of a, if any, does lim f(x) = -∞0? Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. x→a+ A. Either a (Type integers or simplified fractions) B.

Sketch a possible graph of a function f, together with vertical asymptotes, that satisfies all of the following conditions. f(2)=0 f(4) is undefined lim f(x)=1 X-6 lim f(x) = -∞ x-0+ lim f(x) = ∞ lim f(x) = ∞ x-4 _8

Chapter 2 Solutions

Business Math (11th Edition)

Ch. 2.1 - Prob. 1-1SC Ch. 2.1 - Prob. 1-2SC Ch. 2.1 - Prob. 1-3SC Ch. 2.1 - Prob. 1-4SC Ch. 2.1 - Prob. 1-5SC Ch. 2.1 - Prob. 1-6SC Ch. 2.1 - Prob. 2-1SC Ch. 2.1 - Prob. 2-2SC Ch. 2.1 - Prob. 2-3SC Ch. 2.1 - Prob. 2-4SC

Ch. 2.1 - Prob. 2-5SC Ch. 2.1 - Prob. 3-1SC Ch. 2.1 - Prob. 3-2SC Ch. 2.1 - Prob. 3-3SC Ch. 2.1 - Prob. 3-4SC Ch. 2.1 - Prob. 3-5SC Ch. 2.1 - Prob. 4-1SC Ch. 2.1 - Prob. 4-2SC Ch. 2.1 - Prob. 4-3SC Ch. 2.1 - Prob. 4-4SC Ch. 2.1 - Prob. 4-5SC Ch. 2.1 - Prob. 4-6SC Ch. 2.1 - Prob. 4-7SC Ch. 2.1 - Prob. 4-8SC Ch. 2.1 - Prob. 5-1SC Ch. 2.1 - Prob. 5-2SC Ch. 2.1 - Prob. 5-3SC Ch. 2.1 - Prob. 5-4SC Ch. 2.1 - Prob. 5-5SC Ch. 2.1 - Prob. 5-6SC Ch. 2.1 - Prob. 1SE Ch. 2.1 - Prob. 2SE Ch. 2.1 - Prob. 3SE Ch. 2.1 - Prob. 4SE Ch. 2.1 - Prob. 5SE Ch. 2.1 - Prob. 6SE Ch. 2.1 - Prob. 7SE Ch. 2.1 - Prob. 8SE Ch. 2.1 - Prob. 9SE Ch. 2.1 - Prob. 10SE Ch. 2.1 - Prob. 11SE Ch. 2.1 - Prob. 12SE Ch. 2.1 - Prob. 13SE Ch. 2.1 - Prob. 14SE Ch. 2.1 - Prob. 15SE Ch. 2.1 - Prob. 16SE Ch. 2.1 - Prob. 17SE Ch. 2.1 - Prob. 18SE Ch. 2.1 - Prob. 19SE Ch. 2.1 - Prob. 20SE Ch. 2.1 - Prob. 21SE Ch. 2.1 - Prob. 22SE Ch. 2.1 - Prob. 23SE Ch. 2.1 - Prob. 24SE Ch. 2.1 - Prob. 25SE Ch. 2.1 - Prob. 26SE Ch. 2.1 - Prob. 27SE Ch. 2.1 - Prob. 28SE Ch. 2.1 - Prob. 29SE Ch. 2.1 - Prob. 30SE Ch. 2.1 - Prob. 31SE Ch. 2.1 - Prob. 32SE Ch. 2.1 - Prob. 33SE Ch. 2.1 - Prob. 34SE Ch. 2.1 - Prob. 35SE Ch. 2.1 - Prob. 36SE Ch. 2.1 - Prob. 37SE Ch. 2.1 - Prob. 38SE Ch. 2.2 - Prob. 1-1SC Ch. 2.2 - Prob. 1-2SC Ch. 2.2 - Prob. 1-3SC Ch. 2.2 - Prob. 1-4SC Ch. 2.2 - Prob. 1-5SC Ch. 2.2 - Prob. 2-1SC Ch. 2.2 - Prob. 2-2SC Ch. 2.2 - Prob. 2-3SC Ch. 2.2 - Prob. 2-4SC Ch. 2.2 - Prob. 2-5SC Ch. 2.2 - Prob. 3-1SC Ch. 2.2 - Prob. 3-2SC Ch. 2.2 - Prob. 3-3SC Ch. 2.2 - Prob. 3-4SC Ch. 2.2 - Prob. 3-5SC Ch. 2.2 - Prob. 3-6SC Ch. 2.2 - Prob. 4-1SC Ch. 2.2 - Prob. 4-2SC Ch. 2.2 - Prob. 4-3SC Ch. 2.2 - Prob. 4-4SC Ch. 2.2 - Prob. 4-5SC Ch. 2.2 - Prob. 4-6SC Ch. 2.2 - Prob. 4-7SC Ch. 2.2 - Prob. 4-8SC Ch. 2.2 - Prob. 4-9SC Ch. 2.2 - Prob. 4-10SC Ch. 2.2 - Prob. 1SE Ch. 2.2 - Prob. 2SE Ch. 2.2 - Prob. 3SE Ch. 2.2 - Prob. 4SE Ch. 2.2 - Prob. 5SE Ch. 2.2 - Prob. 6SE Ch. 2.2 - Prob. 7SE Ch. 2.2 - Prob. 8SE Ch. 2.2 - Prob. 9SE Ch. 2.2 - Prob. 10SE Ch. 2.2 - Prob. 11SE Ch. 2.2 - Prob. 12SE Ch. 2.2 - Prob. 13SE Ch. 2.2 - Prob. 14SE Ch. 2.2 - Prob. 15SE Ch. 2.2 - Prob. 16SE Ch. 2.2 - Prob. 17SE Ch. 2.2 - Prob. 18SE Ch. 2.2 - Prob. 19SE Ch. 2.2 - Prob. 20SE Ch. 2.2 - Prob. 21SE Ch. 2.2 - Prob. 22SE Ch. 2.2 - Prob. 23SE Ch. 2.2 - Prob. 24SE Ch. 2.2 - Prob. 25SE Ch. 2.2 - Prob. 26SE Ch. 2.2 - Prob. 27SE Ch. 2.2 - Prob. 28SE Ch. 2.2 - Prob. 29SE Ch. 2.2 - Prob. 30SE Ch. 2.3 - Prob. 1-1SC Ch. 2.3 - Prob. 1-2SC Ch. 2.3 - Prob. 1-3SC Ch. 2.3 - Prob. 1-4SC Ch. 2.3 - Prob. 1-5SC Ch. 2.3 - Prob. 1-6SC Ch. 2.3 - Prob. 1-7SC Ch. 2.3 - Prob. 2-1SC Ch. 2.3 - Prob. 2-2SC Ch. 2.3 - Prob. 2-3SC Ch. 2.3 - Prob. 2-4SC Ch. 2.3 - Prob. 2-5SC Ch. 2.3 - Prob. 2-6SC Ch. 2.3 - Prob. 2-7SC Ch. 2.3 - Prob. 1SE Ch. 2.3 - Prob. 2SE Ch. 2.3 - Prob. 3SE Ch. 2.3 - Prob. 4SE Ch. 2.3 - Prob. 5SE Ch. 2.3 - Prob. 6SE Ch. 2.3 - Prob. 7SE Ch. 2.3 - Prob. 8SE Ch. 2.3 - Prob. 9SE Ch. 2.3 - Prob. 10SE Ch. 2.3 - Prob. 11SE Ch. 2.3 - Prob. 12SE Ch. 2.3 - Prob. 13SE Ch. 2.3 - Prob. 14SE Ch. 2.3 - Prob. 15SE Ch. 2.3 - Prob. 16SE Ch. 2.3 - Prob. 17SE Ch. 2.3 - Prob. 18SE Ch. 2.3 - Prob. 19SE Ch. 2.3 - Prob. 20SE Ch. 2.3 - Prob. 21SE Ch. 2.3 - Prob. 22SE Ch. 2.3 - Prob. 23SE Ch. 2.3 - Prob. 24SE Ch. 2 - Prob. 1ES Ch. 2 - Prob. 2ES Ch. 2 - Prob. 3ES Ch. 2 - Prob. 4ES Ch. 2 - Prob. 5ES Ch. 2 - Prob. 6ES Ch. 2 - Prob. 7ES Ch. 2 - Prob. 8ES Ch. 2 - Prob. 9ES Ch. 2 - Prob. 10ES Ch. 2 - Prob. 11ES Ch. 2 - Prob. 12ES Ch. 2 - Prob. 13ES Ch. 2 - Prob. 14ES Ch. 2 - Prob. 15ES Ch. 2 - Prob. 16ES Ch. 2 - Prob. 17ES Ch. 2 - Prob. 18ES Ch. 2 - Prob. 19ES Ch. 2 - Prob. 20ES Ch. 2 - Prob. 21ES Ch. 2 - Prob. 22ES Ch. 2 - Prob. 23ES Ch. 2 - Prob. 24ES Ch. 2 - Prob. 25ES Ch. 2 - Prob. 26ES Ch. 2 - Prob. 27ES Ch. 2 - Prob. 28ES Ch. 2 - Prob. 29ES Ch. 2 - Prob. 30ES Ch. 2 - Prob. 31ES Ch. 2 - Prob. 32ES Ch. 2 - Prob. 33ES Ch. 2 - Prob. 34ES Ch. 2 - Prob. 35ES Ch. 2 - Prob. 36ES Ch. 2 - Prob. 37ES Ch. 2 - Prob. 38ES Ch. 2 - Prob. 39ES Ch. 2 - Prob. 40ES Ch. 2 - Prob. 41ES Ch. 2 - Prob. 42ES Ch. 2 - Prob. 43ES Ch. 2 - Prob. 44ES Ch. 2 - Prob. 45ES Ch. 2 - Prob. 46ES Ch. 2 - Prob. 47ES Ch. 2 - Prob. 48ES Ch. 2 - Prob. 49ES Ch. 2 - Prob. 50ES Ch. 2 - Prob. 51ES Ch. 2 - Prob. 52ES Ch. 2 - Prob. 53ES Ch. 2 - Prob. 54ES Ch. 2 - Prob. 55ES Ch. 2 - Prob. 56ES Ch. 2 - Prob. 57ES Ch. 2 - Prob. 58ES Ch. 2 - Prob. 59ES Ch. 2 - Prob. 60ES Ch. 2 - Prob. 61ES Ch. 2 - Prob. 62ES Ch. 2 - Prob. 63ES Ch. 2 - Prob. 64ES Ch. 2 - Prob. 65ES Ch. 2 - Prob. 66ES Ch. 2 - Prob. 67ES Ch. 2 - Prob. 68ES Ch. 2 - Prob. 69ES Ch. 2 - Prob. 70ES Ch. 2 - Prob. 71ES Ch. 2 - Prob. 72ES Ch. 2 - Prob. 73ES Ch. 2 - Prob. 74ES Ch. 2 - Prob. 75ES Ch. 2 - Prob. 76ES Ch. 2 - Prob. 78ES Ch. 2 - Prob. 79ES Ch. 2 - Prob. 80ES Ch. 2 - Prob. 81ES Ch. 2 - Prob. 82ES Ch. 2 - Prob. 83ES Ch. 2 - Prob. 84ES Ch. 2 - Prob. 1PT Ch. 2 - Prob. 2PT Ch. 2 - Prob. 3PT Ch. 2 - Prob. 4PT Ch. 2 - Prob. 5PT Ch. 2 - Prob. 6PT Ch. 2 - Prob. 7PT Ch. 2 - Prob. 8PT Ch. 2 - Prob. 9PT Ch. 2 - Prob. 10PT Ch. 2 - Prob. 11PT Ch. 2 - Prob. 12PT Ch. 2 - Prob. 13PT Ch. 2 - Prob. 14PT Ch. 2 - Prob. 15PT Ch. 2 - Prob. 16PT Ch. 2 - Prob. 17PT Ch. 2 - Prob. 18PT Ch. 2 - Prob. 19PT Ch. 2 - Prob. 20PT Ch. 2 - Prob. 21PT Ch. 2 - Prob. 22PT Ch. 2 - Prob. 23PT Ch. 2 - Prob. 24PT Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 1CP Ch. 2 - Prob. 2CP Ch. 2 - Prob. 1CS1 Ch. 2 - Prob. 2CS1 Ch. 2 - Prob. 3CS1 Ch. 2 - Prob. 1CS2 Ch. 2 - Prob. 2CS2 Ch. 2 - Prob. 3CS2 Ch. 2 - Prob. 4CS2

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

The division of the fraction 15 ÷ 3 4 reduce the quotient into lowest terms and if appropriate write it as whole or mixed numbers.

Concept explainers

Videos

To calculate: The division of the fraction 15÷34 reduce the quotient into lowest terms and if appropriate write it as whole or mixed numbers.

Want to see the full answer?

Chapter 2 Solutions