
(a)
Interpretation: Using a Gabriel synthesis, a give set of primary amine compounds have to be synthesized.
Concept Introduction: The general formula for primary amine is –NH2. There are several methods available to prepare primary
Step-1: Formation of potassium phthalimide (deprotonation)
Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.
Step-2: Formation of R−N bond by SN2 nucleophilic substitution
The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary
Step-3: Formation of primary amine by hydrolysis
The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.
(b)
Interpretation: Using a Gabriel synthesis, a give set of primary amine compounds have to be synthesized.
Concept Introduction: The general formula for primary amine is –NH2. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.
Step-1: Formation of potassium phthalimide (deprotonation)
Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.
Step-2: Formation of R−N bond by SN2 nucleophilic substitution
The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is SN2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.
Step-3: Formation of primary amine by hydrolysis
The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.
(c)
Interpretation: Using a Gabriel synthesis, a give set of primary amine compounds have to be synthesized.
Concept Introduction: The general formula for primary amine is –NH2. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.
Step-1: Formation of potassium phthalimide (deprotonation)
Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.
Step-2: Formation of R−N bond by SN2 nucleophilic substitution
The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is SN2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.
Step-3: Formation of primary amine by hydrolysis
The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.
(d)
Interpretation: Using a Gabriel synthesis, a give set of primary amine compounds have to be synthesized.
Concept Introduction: The general formula for primary amine is –NH2. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.
Step-1: Formation of potassium phthalimide (deprotonation)
Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.
Step-2: Formation of R−N bond by SN2 nucleophilic substitution
The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is SN2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.
Step-3: Formation of primary amine by hydrolysis
The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.

Want to see the full answer?
Check out a sample textbook solution
Chapter 22 Solutions
ORGANIC CHEMISTRY-STD.WILEY PLUS CARD
- For the reaction: CO2(g) + H2(g) --> CO (g) + H2O (g) Kc= 0.64 at 900 degrees celcius. if initially you start with 1.00 atmoshpere of carbon dioxide and 1 atmoshpere of hydrogen gas, what are the equilibrium partial pressuses of all species.arrow_forwardCan I please get this answered? With the correct number of significant digits.arrow_forwardDraw the Hofmann product of the dehydroiodination of this alkyl iodide. ☐ : + Explanation Check esc F1 2 3 I 88 % 5 F5 I. X © tBuOK Click and drag to sta drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Te BI BB F6 W E R Y S H Karrow_forward
- Can I please get help with this graph, if you could show exactly where it needs to pass through please.arrow_forwardDraw the condensed structure of 1,3-dihydroxy-2-pentanone. Explanation Check Click anywhere to draw the first atom of your structure. Х C © 2025 McGraw Hill LLC. All Rights Reserved. Terms of use +arrow_forward0.500 moles of NOCl are placed into a 1.00 L vessesl at 700K and after the system comes to equilibrium, the consentration of NOCl is 0.440 M. Calculate the equilibrium constant Kc for the reaction: 2NOCL (g) --> 2NO (g) + Cl2 (g)arrow_forward
- What is the hydronium ion concentration in a solution of water that has a hydroxide ion concentrationof 1.0 x 10-2 M?arrow_forwardIdentify conjugate acid-base pairs in the following reactions:HBr (aq) + H2O (l) ⇌ H3O+ (aq) + Br- (aq) - OH (aq) + CH3COOH (aq) ⇌ H2O (l) + CH3COO- (aq)arrow_forward4:45 PM Tue Apr 1 K 77% Problem 9 of 10 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting structure, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Then draw any missing organic intermediates or products for this reaction. Include all lone pairs in the structures. Ignore inorganic byproducts, counterions, and solvents. :0: H Select to Add Arrows HI CH3OH H+ ·HO CH3OH, H+ 0:0 H H Select to Add Arrows tion Versirate CH3OH, H* Select to Draw Productarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





