For a given set of nitrogen containing compound, general or IUPAC names have to be assigned. Concept Introduction : If , and groups are attached to the parent carbon, they are called primary, secondary and tertiary amines respectively. There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given. The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of alkanes . If one, two, three, four, five, six, etc carbons are activating as the main chain in general name method, then the name of the compound comes as methyl, ethyl, propyl, butyl, pentyl, hexyl, etc. which are the name of alkyl groups. If substituent groups are attached to nitrogen atom as in the case of tertiary or secondary amines, the name is given as N-alkyl name of the substituent. If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets ( Z )-configuration. If they are on the opposite directions, ( E )-configuration results. If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets ( R )-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets ( S )-isomer. To find: Assign the name for a given compound

Question

Want to see the full answer?

Answer 1

Question

Chapter 22.2, Problem 1LTS

Interpretation Introduction

Interpretation: For a given set of nitrogen containing compound, general or IUPAC names have to be assigned.

Concept Introduction:

If , and groups are attached to the parent carbon, they are called primary, secondary and tertiary amines respectively.

There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.

The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of alkanes. If one, two, three, four, five, six, etc carbons are activating as the main chain in general name method, then the name of the compound comes as methyl, ethyl, propyl, butyl, pentyl, hexyl, etc. which are the name of alkyl groups. If substituent groups are attached to nitrogen atom as in the case of tertiary or secondary amines, the name is given as N-alkyl name of the substituent.

If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configuration results.

If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.

To find: Assign the name for a given compound

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

my ccc edu - Search X Quick Access X D2L Homepage - Spring 2025 x N Netflix X Dimensional Analysis - A x+ pp.aktiv.com Q ☆ X Question 59 of 70 The volume of 1 unit of plasma is 200.0 mL If the recommended dosage for adult patients is 10.0 mL per kg of body mass, how many units are needed for a patient with a body mass of 80.0 kg ? 80.0 kg 10.0 DAL 1 units X X 4.00 units 1 1 Jeg 200.0 DAL L 1 units X 200.0 mL = 4.00 units ADD FACTOR *( ) DELETE ANSWER RESET D 200.0 2.00 1.60 × 10³ 80.0 4.00 0.0400 0.250 10.0 8.00 & mL mL/kg kg units/mL L unit Q Search delete prt sc 111 110 19

Identify the starting material in the following reaction. Click the "draw structure" button to launch the drawing utility. draw structure ... [1] 0 3 C10H18 [2] CH3SCH3 H

In an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C. 2 NH3 (g) N2 (g) + 3 H₂ (g) K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104