Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine Concept Introduction : A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows: a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide b) Alkyl bromide in azide synthesis produces primary amine c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton e) Alkene on ozonolysis produces carbonyl compounds f) Alkyl halides with strong base gives alkene g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines . Using these concepts, we can transfer 1-hexanol into the given compounds.

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Answer 1

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

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#1. Retro-Electrochemical Reaction: A ring has been made, but the light is causing the molecule to un- cyclize. Undo the ring into all possible molecules. (2pts, no partial credit) hv

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I have a question about this problem involving mechanisms and drawing curved arrows for acids and bases. I know we need to identify the nucleophile and electrophile, but are there different types of reactions? For instance, what about Grignard reagents and other types that I might not be familiar with? Can you help me with this? I want to identify the names of the mechanisms for problems 1-14, such as Gilman reagents and others. Are they all the same? Also, could you rewrite it so I can better understand? The handwriting is pretty cluttered. Additionally, I need to label the nucleophile and electrophile, but my main concern is whether those reactions differ, like the "Brønsted-Lowry acid-base mechanism, Lewis acid-base mechanism, acid-catalyzed mechanisms, acid-catalyzed reactions, base-catalyzed reactions, nucleophilic substitution mechanisms (SN1 and SN2), elimination reactions (E1 and E2), organometallic mechanisms, and so forth."

Answer 2

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

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Answer 3

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 6

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 7

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 8

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 9

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 10

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 11

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 22.2 - Prob. 1LTS Ch. 22.2 - Prob. 1PTS Ch. 22.2 - Prob. 2PTS Ch. 22.2 - Prob. 3ATS Ch. 22.3 - Prob. 4CC Ch. 22.3 - Prob. 5CC Ch. 22.3 - Prob. 6CC Ch. 22.3 - Prob. 7CC Ch. 22.3 - Prob. 8CC Ch. 22.3 - Prob. 9CC

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Chapter 22 Solutions