
Concept explainers
Interpretation:
The three ways in which the structure of chlorophyll differs from the structure of heme are to be determined.
Concept introduction:
The basic molecular structure of chlorophyll contains a chlorine ring, which contains four nitrogen atoms surrounding the central magnesium atom. In addition to that, it contains several other side chains and a hydrocarbon tail.
The molecular structure of hemoglobin contains four heme groups surrounding a globin group in the tetrahedral fashion. The four iron atoms bind to the oxygen atom forming an oxyhemobglobin molecule.
The major difference between the structures of chlorophyll and heme group is the presence of a cyclopentanone ring fused to the tetrapyrrole ring.

Trending nowThis is a popular solution!

Chapter 22 Solutions
BIOCHEMISTRY (LOOSELEAF) >CUSTOM PKG<
- Imagine that aldolase can react with the seven carbon molecule Sedoheptulose-1,7-bisphosphate (below). Use the mechanism to predict the two products generated.arrow_forwardShow the mechanisms of PGK and PFK-1. How are they different?arrow_forwardShow the fate of the proton on the 4-Oxygen molecule of F-1,6-BP.arrow_forward
- Sodium borohydride (NaBH4) is a potent inhibitor of aldolase. It is known to ONLY inhibit theenzyme when it is complexed with substrate. Treatment of the enzyme alone has no effect.What is the mechanism for this inhibition?arrow_forwardA non-hydrolysable ATP (AMPPNP - below) is ingested by a graduate student on a dare. Whateffects would you anticipate on his metabolism?arrow_forwardShow the mechanism for the acid-catalyzed formation of an [α-1,6] glycosidic linkagebetween two molecules of α-D-glucopyranose. Please sketch the structure and use arrows showing electron flow!arrow_forward
- I am a Biochemistry student and I am confused on how to analyze FRAP Analysis using Excel Spread Sheets. The following spread sheet has my 0 minute data listed at top and the 4 minute data listed on the bottom. Sheet: https://mnscu-my.sharepoint.com/:x:/g/personal/vi2163ss_go_minnstate_edu/EXjrCizWiXRPmpittqZA12IB8EkB5eE8iaRqj_iun-IAtg?rtime=Wo9zPHFY3Ug The formula for FRAP Analysis is: FRAP value = A (4 min sample) - A (0 min sample) over A (4 min 30 uM ascorbic acid) - A (0 min 30 uM ascorbic acid) multiplied by 30 uM and the dilution factor of 1/10arrow_forwardHO Fill in the missing boxes. ON 800 NO NO Glucose ATP NADH Hexokinase 1,3-Bisphosphoglycerate Mg2+ ADP NAD+, Pi Phosphoglucose Isomerase Glucose-6-Phosphate ON 沁 Glyceraldehyde-3-Phosphate HO حلمة ADP ADP Phospho Mg2+ glycerate Dihydroxyacetone Phosphate ATP kinase ATP Phosphoglycerate 3-phosphoglycerate Mutase H₁₂O Fructose-6-Phosphate ATP Mg2+ ADP Fructose-1,6-Bisphosphate 2-phosphoglycerate H₂O Phosphoenolpyruvate ADP Mg2+ ATP Pyruvatearrow_forwardIn a diffraction experiment of a native crystal, intensity of reflection (-1 0 6) is equivalent to the intensity of reflection (1 0 -6). true or false?arrow_forward
- in an x-ray diffraction experiment, moving the detector farther away from the crystal will allow collection of reflection of reflections with high Miller indices. true or false?arrow_forwardShow the mechanism for the acid-catalyzed formation of an [α-1,6] glycosidic linkagebetween two molecules of α-D-glucopyranose.arrow_forwardLabel the following polysaccharide derivatives as reducing or nonreducing. a. C. b. HO CH₂OH CH2OH OH OH OH OH OH HOCH₂ OH OH OH HOCH₂ HO HO HO OH OH ΙΟ CH₂OH OH OH "OH OHarrow_forward
- BiochemistryBiochemistryISBN:9781305961135Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougalPublisher:Cengage Learning
