Concept explainers
(a)
Interpretation:
The expected bond angle of
Concept introduction:
The angle formed between two bonds originating from the same atom in a covalent compound is said to be the bond angle.
(b)
Interpretation:
The expected bond angle of
Concept introduction:
The angle formed between two bonds originating from the same atom in a covalent compound is said to be the bond angle.
(c)
Interpretation:
The expected bond angle of
Concept introduction:
The angle formed between two bonds originating from the same atom in a covalent compound is said to be the bond angle.
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Chapter 22 Solutions
Chemistry: Principles and Reactions
- 2. Account for the bond angle differences between (i) H-C-H (109.5°) in methane and H-S-H (90°); H-C-H (109.5°) and H-O-H (107.5°) in water The H-S-H has two lone pairs; The H-O-H has two lone pairs The H-S-H has no hybridization at p-orbitals; The H-O-H has two lone pairs The H-S-H has two lone pairs; The H-O-H has no hybridization at p-orbitals The H-S-H has no hybridization at p-orbitals; The H-O-H has no hybridization at p- orbitalsarrow_forwardIdentify the hybridization state, molecular geometry and approximate bond angle at the indicatednitrogen atom in the following compound. O sp²,bent, 109° O sp²,bent, 120° O sp3, tetrahedral, 109.5° O sp3, trigonal pyramidal, ~109.5° O sp2, trigonal pyramidal, 120° CH3 HH CH₂. H₂=C₂C=C₂C₂O₂H N OU! H³N¬C-C¬-H H HH .0.arrow_forwarda Use the VSEPR model to predict the bond angles and geometry about each highlighted atom: HH H-C-C-O-H II HH b C about C 109.5°, tetrahedral; about O 109.5°, bent about C 109.5°, tetrahedral; about O 180°, linear about C 120°, planar; about O 109.5°, tetrahedral about C 109.5°, bent; about O 180°, linear HH H-C-C-H I HH 109.5°, tetrahedral 120°, planar 180°, linear 109.5°, bent HO H-C-C-C-H H 120°, planar 109.5°, tetrahedral 109.5°, bentarrow_forward
- Please send me the question in 20 minutes it's very urgent plzarrow_forwardIf the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the structure Y-X-Y could be abbreviated as XY,Z,. Classify each molecule according to its shape. Linear Bent (x 120°) Bent (x 109°) Trigonal T-shaped See-saw Square planar Square pyramidal pyramidal Answer Bank XY;Z2 XY,Z XY,Z XY,Z3 XY;Z XY,Z, XY,Z XY,Z2arrow_forwardPredict what the bond angles would be in NBr. Around 120⁰° Less than 90° Around 109.5° Around 90°.arrow_forward
- Identify the hybridization state, molecular geometry and approximate bond angle around the carbon atomfor the molecule shown in box below. sp², tetrahedral, 109° sp², trigonal planar, 120° sp³, tetrahedral, 109.5° sp³, trigonal pyramidal, <109.5° O sp², trigonal pyramidal, 180° HCOOHarrow_forwardWhat is the orbital hybridization of each carbon in the following: O ║ CH3–C≡C-CH2–C–CHBr-CH3arrow_forwardDescribe the bonding between C1 and C2; C2 and H; C2 and C3; C3 and H; C3 and C4. You should be telling me about 6 bonds. Be specific as to type of bond and orbitals involved. H 7 H 3 Harrow_forward
- QUESTION 5 (ii) Show the direction of the dipole moment on the following compounds:a) CO2b) BF3c) H2Od) CH3Cl.arrow_forwardWhat is the hybridization of the sigma bonding orbitals of the carbon atom?arrow_forwardPredict the hybridization and the bond angles around the indicated atoms. a b Ö -N=C=S phenylisothiocyanate Atom a Atom b Atom c Hybridization sp² sp³ ✓ sp Bond angle 120⁰ 109.5°✓ 180°arrow_forward
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