(III) A flat slab of nonconducting material has thickness 2 d , which is small compared to its height and breadth. Define the x axis to be along the direction of the slab’s thickness with the origin at the center of the slab (Fig. 22–41). If the slab carries a volume charge density ρ E ( x ) = − ρ 0 in the region − d ≤ x < 0 and ρ E ( x ) = + ρ 0 in the region 0 < x ≤ + d , determine the electric field E → as a function of x in the regions ( a ) outside the slab, ( b ) 0 < x ≤ + d , and ( c ) − d ≤ x < 0. Let ρ 0 be a positive constant.
(III) A flat slab of nonconducting material has thickness 2 d , which is small compared to its height and breadth. Define the x axis to be along the direction of the slab’s thickness with the origin at the center of the slab (Fig. 22–41). If the slab carries a volume charge density ρ E ( x ) = − ρ 0 in the region − d ≤ x < 0 and ρ E ( x ) = + ρ 0 in the region 0 < x ≤ + d , determine the electric field E → as a function of x in the regions ( a ) outside the slab, ( b ) 0 < x ≤ + d , and ( c ) − d ≤ x < 0. Let ρ 0 be a positive constant.
(III) A flat slab of nonconducting material has thickness 2d, which is small compared to its height and breadth. Define the x axis to be along the direction of the slab’s thickness with the origin at the center of the slab (Fig. 22–41). If the slab carries a volume charge density ρE (x) = −ρ0 in the region −d ≤ x < 0 and ρE(x) = +ρ0 in the region 0 < x ≤ +d, determine the electric field
E
→
as a function of x in the regions (a) outside the slab, (b) 0 < x ≤ + d, and (c) −d ≤ x < 0. Let ρ0 be a positive constant.
I did my homework related to radiation damage in materials wrong. Please correct my answers and justify them so I can learn from my miskates.
No Chatgpt please will upvote
The electric force of repulsion between two electrons is similar to the gravitational force:
where k is called Planck's constant, q is the charge on a particle, and r is the distance separating the charges.
Find the new force of repulsion between them, in terms of R:
a. when the distance between the electrons is doubled.
b, when the distance between the electrons is multiplied by 1.2.
C. when the distance between the electrons is multiplied by 1/3.
D. when the distance between the electrons is divided by 6.
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