(III) An electric field is given by E = E x 0 e − ( x + y a ) 2 i ^ + E y 0 e − ( x + y a ) 2 j ^ , where E x 0 = 50 N/C, E y 0 = 25 N/C, and a = 1.0 m. Given a cube with sides parallel to the coordinate axes, with one corner at the origin (as in Fig. 22–48), and with sides of length 1.0 m, estimate the flux out of the cube using a spreadsheet or other numerical method. How much total charge is enclosed by the cube?
(III) An electric field is given by E = E x 0 e − ( x + y a ) 2 i ^ + E y 0 e − ( x + y a ) 2 j ^ , where E x 0 = 50 N/C, E y 0 = 25 N/C, and a = 1.0 m. Given a cube with sides parallel to the coordinate axes, with one corner at the origin (as in Fig. 22–48), and with sides of length 1.0 m, estimate the flux out of the cube using a spreadsheet or other numerical method. How much total charge is enclosed by the cube?
E
=
E
x
0
e
−
(
x
+
y
a
)
2
i
^
+
E
y
0
e
−
(
x
+
y
a
)
2
j
^
,
where Ex0 = 50 N/C, Ey0 = 25 N/C, and a = 1.0 m. Given a cube with sides parallel to the coordinate axes, with one corner at the origin (as in Fig. 22–48), and with sides of length 1.0 m, estimate the flux out of the cube using a spreadsheet or other numerical method. How much total charge is enclosed by the cube?
Consider the following figure. (If you need to use ∞ or -∞, enter INFINITY or -INFINITY, respectively.)
(a)
(b)
0
-2q
+9
5
5
+9
-29
+3q
10
10
+q
x (cm)
x (cm)
-9
(a) Find the total electric field in N/C at x = 1.00 cm in part (b) of the figure above given that q = 5.00 nC.
N/C
(b) Find the total electric field in N/C at x = 10.70 cm in part (b) of the figure above. (Include the sign of the value in your answer.)
N/C
(c) If the charges are allowed to move and eventually be brought to rest by friction, what will the final charge configuration be? (That is, will there be a single charge, double charge, etc., and what
will its value(s) be? Use the following as necessary: q.)
Consider the following figure. (If you need to use so or-, enter INFINITY or -INFINITY, respectively.)
(a)
(6)
0
0
-20
+9
5
5
-q
-29
+3q
10
10
+9
x (cm)
x (cm)
-9
(a) Find the total electric field in N/C at x 1.00 cm in part (b) of the figure above given that q=1.00 p
N/C
(b) Find the total electric field in N/C at x 12.70 cm in part (b) of the figure above. (Include the sign of the value in your answer.)
N/C
(c) If the charges are allowed to move and eventually be brought to rest by friction, what will the final charge configuration be? (That is, will there be a single charge, de
value(s) be? Use the following as necessary: q.)
An electric dipole with dipole moment p = 6 x 10¬³ C · m sets up an electric field (in newtons per coulomb)
F(x, у, z) %3D
p5
KP (3xz, 3yz, 2z? – x -
y² )
1/2
where r =
(x² + y?
+ z?)"2 with distance in meters and k = 8.99 × 10° N-m² . Calculate the work against F required to
C2
move a particle of charge q = 0.03 C from (1, –5, 0) to (2,3, 4).
Note: The force on q is qF newtons.
(Use decimal notation. Give your answer to one decimal place.)
J
Chapter 22 Solutions
Physics for Science and Engineering With Modern Physics, VI - Student Study Guide
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.