Concept explainers
(a)
Interpretation:
The element withatomic number
Concept Introduction:
An atom has three sub particles, electrons, protons and neutrons. The electrons carry a negative charge; protons carry a positive charge while neutrons are neutral entities. The number of proton in an atom is assigned as its
(b)
Interpretation:
The element with atomic number
Concept Introduction:
An atom has three sub particles, electrons, protons and neutrons. The electrons carry a negative charge; protons carry a positive charge while neutrons are neutral entities. The number of proton in an atom is assigned as its atomic number.
(c)
Interpretation:
The element with atomic number
Concept Introduction:
An atom has three sub particles, electrons, protons and neutrons. The electrons carry a negative charge; protons carry a positive charge while neutrons are neutral entities. The number of proton in an atom is assigned as its atomic number.
(d)
Interpretation:
The element with atomic number
Concept Introduction:
An atom has three sub particles, electrons, protons and neutrons. The electrons carry a negative charge; protons carry a positive charge while neutrons are neutral entities. The number of proton in an atom is assigned as its atomic number.
(e)
Interpretation:
The element with atomic number
Concept Introduction:
An atom has three sub particles, electrons, protons and neutrons. The electrons carry a negative charge; protons carry a positive charge while neutrons are neutral entities. The number of proton in an atom is assigned as its atomic number.

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Chapter 2 Solutions
ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
- Using a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c. (Please provide a full derivation of the equation for x from the equation for I). d) Calculate x for the 1645 cm-1 bandarrow_forwardI need help with the follloaingarrow_forwardFor a CARS experiment on a Raman band 918 cm-1, if omega1= 1280 nm, calculate the omega2 in wavelength (nm) and the CARS output in wavelength (nm).arrow_forward
- I need help with the following questionarrow_forwardFor CARS, which statement is not true regarding its advantages? a) Contrast signal based on vibrational characteristics, no need for fluorescent tagging. b) Stronger signals than spontaneous Raman. c) Suffers from fluorescence interference, because CARS signal is at high frequency. d) Faster, more efficient imaging for real-time analysis. e) Higher resolution than spontaneous Raman microscopy.arrow_forwardDraw the major product of the Claisen condensation reaction between two molecules of this ester. Ignore inorganic byproducts. Incorrect, 5 attempts remaining 1. NaOCH3/CH3OH 2. Acidic workup Select to Draw O Incorrect, 5 attempts remaining The total number of carbons in the parent chain is incorrect. Review the reaction conditions including starting materials and/or intermediate structures and recount the number of carbon atoms in the parent chain of your structure. OKarrow_forward
- Using a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c d) Calculate x for the 1645 cm-1 bandarrow_forwardConvert 1.38 eV into wavelength (nm) and wavenumber (cm-1) (c = 2.998 x 108 m/s; h = 6.626 x 10-34 J*s).arrow_forwardCan you help me understand the CBC method on metal bridging by looking at this problem?arrow_forward
- A partir de Aluminio y Co(NO3)2ꞏ6H2O, indicar las reacciones a realizar para obtener Azul de Thenard (Al2CoO4).arrow_forwardTo obtain Thenard Blue (Al2CoO4), the following reaction is correct (performed in an oven):Al(OH)3 + Co(OH)2 → Al2CoO4 + 4 H2Oarrow_forwardProblem 38 can u explain and solve thanks april 24arrow_forward
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