(a)
Interpretation:
The name of an alkali metal in period 6 needs to be determined.
Concept Introduction:
In a Periodic table, there are in total 7 periods and 18 groups. And, in a Periodic table all the elements found in nature are arranged according to increasing
Alkali metals are the metals that belong to group 1 of the Periodic table. General electronic configuration of alkali metals is
Alkali group contains six elements.
These elements are as follows. Lithium, sodium, potassium, Rubidium, Cesium and Francium.
(b)
Interpretation:
The element present in period 5 and group 8 in the periodic table needs to be determined.
Concept Introduction:
In a Periodic table, there are in total 7 periods and 18 groups. And, in a Periodic table all the elements found in nature are arranged according to increasing atomic number.
General electronic configuration of transition metals is
These elements are placed in the middle of Periodic table.
(c)
Interpretation:
The element present in group 7A and period 3 needs to be determined.
Concept Introduction:
In a Periodic table, there are in total 7 periods and 18 groups. And, in a Periodic table all the elements found in nature are arranged according to increasing atomic number.
Group
Elements which belong to this group are Fluorine, Chlorine, Bromine, Iodine, and Astatine.
(d)
Interpretation:
The elementpresent inperiod 2 and group 2A needs to be determined.
Concept Introduction:
In a Periodic table, there are in total 7 rows and 18 columns. And, in a Periodic table all the elements found in nature are arranged according to increasing atomic number.
Elements of group
Elements present in this group are Beryllium, Magnesium, Calcium, Strontium, Barium, and Radium.
(e)
Interpretation:
The halogen present in period 2 needs to be determined.
Concept Introduction:
In a Periodic table, there are in total 7 periods and 18 groups. And, in a Periodic table all the elements found in nature are arranged according to increasing atomic number.
Group
Elements which belong to this group are Fluorine, Chlorine, Bromine, Iodine, and Astatine.
(f)
Interpretation:
An inner transition metalwith one electron in 4f orbital needs to be determined.
Concept Introduction:
In a Periodic table, there are in total 7 rows and 18 columns. And, in a Periodic table all the elements found in nature are arranged according to increasing atomic number.
Elements that belong to lanthanide and actinide series are known as inner transition metals. Elements with atomic number 57 to 71 are all lanthanides whereas elements with atomic number 89 to 103 are all actinides.

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Chapter 2 Solutions
ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
- Use the reaction coordinate diagram to answer the below questions. Type your answers into the answer box for each question. (Watch your spelling) Energy A B C D Reaction coordinate E A) Is the reaction step going from D to F endothermic or exothermic? A F G B) Does point D represent a reactant, product, intermediate or transition state? A/ C) Which step (step 1 or step 2) is the rate determining step? Aarrow_forward1. Using radii from Resource section 1 (p.901) and Born-Lande equation, calculate the lattice energy for PbS, which crystallizes in the NaCl structure. Then, use the Born-Haber cycle to obtain the value of lattice energy for PbS. You will need the following data following data: AH Pb(g) = 196 kJ/mol; AHƒ PbS = −98 kJ/mol; electron affinities for S(g)→S¯(g) is -201 kJ/mol; S¯(g) (g) is 640kJ/mol. Ionization energies for Pb are listed in Resource section 2, p.903. Remember that enthalpies of formation are calculated beginning with the elements in their standard states (S8 for sulfur). The formation of S2, AHF: S2 (g) = 535 kJ/mol. Compare the two values, and explain the difference. (8 points)arrow_forwardIn the answer box, type the number of maximum stereoisomers possible for the following compound. A H H COH OH = H C Br H.C OH CHarrow_forward
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- Draw the product(s) formed when alkene A is reacted with ozone, followed by Zn and H₂O. If no second product is formed, do not draw a structure in the second box. Higher Molecular Weight Product A Lower Molecular Weight Product draw structure ... draw structure ...arrow_forwardRank A - D in order of increasing rate of reaction with H2 and Pd/C. ب ب ب ب A B с Which option correctly ranks the alkenes in order of increasing rate of reaction with H₂ and Pd/C? О Barrow_forwardDraw the product of the following Sharpless epoxidation, including stereochemistry. Click the "draw structure" button to launch the drawing utility. -OH (CH3)3C-OOH Ti[OCH(CH3)2]4 (+)-DET draw structure ... Guidarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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