Chemical and physical properties of chlorine (Cl 2 ) and magnesium (Mg) have to be explained. Concept introduction: Metals: It is an element which has the following properties: solids at room temperature except mercury, hard in the solid state, good conductors of both heat and electricity, ductility, high density, malleability, high melting and boiling point, tendency to form basic oxides by reacting with oxygen, tendency to form positive ion when they looses the electron and get shiny by polishing. Nonmetals: It is an element or substance but not metal, they have the following properties: they may exist as solid, liquid or gas at room temperature, easily breakable, bad conductors of both heat and electricity, melting and boiling points are low, when they react with oxygen they will form acidic oxides, tendency to form negative ions when they looses electron except hydrogen, which forms positive ion, compare to metals, nonmetals will look dull in nature.

Question

Want to see the full answer?

Answer 1

Question

Chapter 22, Problem 22.3QP

Interpretation Introduction

Interpretation:

Chemical and physical properties of chlorine (Cl2) and magnesium (Mg) have to be explained.

Concept introduction:

Metals: It is an element which has the following properties: solids at room temperature except mercury, hard in the solid state, good conductors of both heat and electricity, ductility, high density, malleability, high melting and boiling point, tendency to form basic oxides by reacting with oxygen, tendency to form positive ion when they looses the electron and get shiny by polishing.

Nonmetals: It is an element or substance but not metal, they have the following properties: they may exist as solid, liquid or gas at room temperature, easily breakable, bad conductors of both heat and electricity, melting and boiling points are low, when they react with oxygen they will form acidic oxides, tendency to form negative ions when they looses electron except hydrogen, which forms positive ion, compare to metals, nonmetals will look dull in nature.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

You have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you manipulated and exploited the acid-base chemistry of one or more of the compounds in your mixture to facilitate their separation into different phases. The key to understanding how liquid- liquid extractions work is by knowing which layer a compound is in, and in what protonation state. The following liquid-liquid extraction is different from the one you performed in Experiment 4, but it uses the same type of logic. Your task is to show how to separate apart Compound A and Compound B. . Complete the following flowchart of a liquid-liquid extraction. Handwritten work is encouraged. • Draw by hand (neatly) only the appropriate organic compound(s) in the boxes. . Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4 and 5. • Box 7a requires the solvent (name is fine). • Box 7b requires one inorganic compound. • You can neatly complete this assignment by hand and…

b) Elucidate compound D w) mt at 170 nd shows c-1 stretch at 550cm;' The compound has the ff electronic transitions: 0%o* and no a* 1H NMR Spectrum (CDCl3, 400 MHz) 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppm 13C{H} NMR Spectrum (CDCl3, 100 MHz) Solvent 80 70 60 50 40 30 20 10 0 ppm ppm ¹H-13C me-HSQC Spectrum ppm (CDCl3, 400 MHz) 5 ¹H-¹H COSY Spectrum (CDCl3, 400 MHz) 0.5 10 3.5 3.0 2.5 2.0 1.5 1.0 10 15 20 20 25 30 30 -35 -1.0 1.5 -2.0 -2.5 3.0 -3.5 0.5 ppm 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppm

Show work with explanation. don't give Ai generated solution