
Concept explainers
(a)
Interpretation: The compound or ion of a second period element, that has formula and lewis structure analogous to given formula
Concept introduction: The elements belonging to the same group of periodic table have same number of electrons in their valence shell. Thus, their physical and chemical properties are also similar.
These elements can exist in similar oxidation state due to same number of valence electrons in the outermost shell. Hence, the elements of same group form compounds with same formula.
If two elements belongs to
However, the lighter elements of the group do not expand their octet while the heavier elements can expand their octet and form compounds with different oxidation numbers. So if the elements belong to group
So, the same number of valence electrons in outermost shell of the elements in same group is responsible for the similar chemical properties of these elements. Thus they also form compounds with same formula.
(b)
Interpretation: The compound or ion of a second period element, that has formula and lewis structure analogous to given formula
Concept introduction: The elements belonging to the same group of periodic table have same number of electrons in their valence shell. Thus, their physical and chemical properties are also similar.
These elements can exist in similar oxidation state due to same number of valence electrons in the outermost shell. Hence, the elements of same group form compounds with same formula.
If two elements belongs to
However, the lighter elements of the group do not expand their octet while the heavier elements can expand their octet and form compounds with different oxidation numbers. So if the elements belong to group
So, the same number of valence electrons in outermost shell of the elements in same group is responsible for the similar chemical properties of these elements. Thus they also form compounds with same formula.
(c)
Interpretation: The compound or ion of a second period element, that has formula and lewis structure analogous to given formula
Concept introduction: The elements belonging to the same group of periodic table have same number of electrons in their valence shell. Thus, their physical and chemical properties are also similar.
These elements can exist in similar oxidation state due to same number of valence electrons in the outermost shell. Hence, the elements of same group form compounds with same formula.
If two elements belongs to
However, the lighter elements of the group do not expand their octet while the heavier elements can expand their octet and form compounds with different oxidation numbers. So if the elements belong to group
So, the same number of valence electrons in outermost shell of the elements in same group is responsible for the similar chemical properties of these elements. Thus they also form compounds with same formula.
(d)
Interpretation: The compound or ion of a second period element, that has formula and lewis structure analogous to given formula
Concept introduction: The elements belonging to the same group of periodic table have same number of electrons in their valence shell. Thus, their physical and chemical properties are also similar.
These elements can exist in similar oxidation state due to same number of valence electrons in the outermost shell. Hence, the elements of same group form compounds with same formula.
If two elements belongs to
However, the lighter elements of the group do not expand their octet while the heavier elements can expand their octet and form compounds with different oxidation numbers. So if the elements belong to group
So, the same number of valence electrons in outermost shell of the elements in same group is responsible for the similar chemical properties of these elements. Thus they also form compounds with same formula.

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Chapter 21 Solutions
Owlv2 With Ebook, 1 Term (6 Months) Printed Access Card For Kotz/treichel/townsend/treichel's Chemistry & Chemical Reactivity, 10th
- The following reaction is run in which the initial conditions include only methane (CH4) at a concentration of0.115 M. Once equilibrium was established, the concentration of acetylene (C2H2) was measured to be 0.035M. What is the value of the equilibrium constant, K?2 CH4 (g) ⇋ C2H2 (g) + 3 H2 (g)arrow_forwardCalculate the equilibrium concentration of carbon dioxide for the following reaction:2 COF2 (g) ⇋ CF4 (g) + CO2 (g) Kc = 2.00 at 10.00 °C. at equilibrium [COF2] = 0.255M; [CF4] = 0.118Marrow_forwardIn a benzene derivative that has -CH2CH3, indicate how it can be substituted by -COOH.arrow_forward
- In a sulfonated derivative of benzene, indicate how -SO3H can be eliminated.arrow_forwardWhat is the equilibrium expression (law of mass action) for the following reaction:CO2 (g) + H2O (l) ⇋ H+ (aq) + HCO3- (aq)arrow_forwardIndicate the compound resulting from adding NaOH cyclopentane-CH2-CHO.arrow_forward
- Use the provided information to calculate Kc for the following reaction at 550 °C: H2(g) + CO2(g) ⇌ CO(g) + H2O(g) Kc = ?CoO(s) + CO(g) ⇌ Co(s) + CO2(g) Kc1 = 490CoO(s) + H2(g) ⇌ Co(s) + H2O(g) Kc2 = 67arrow_forwardCalculate Kc for the reaction: I2 (g) ⇋ 2 I (g) Kp = 6.26 x 10-22 at 298Karrow_forwardFor each scenario below, select the color of the solution using the indicator thymol blue during the titration. When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] . At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] . When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] . When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color isarrow_forward
- To convert cyclopentane-CH2-CHO to cyclopentane-CH2-CH3, compound A is added, followed by (CH3)3CO-K+, DMS at 100oC. Indicate which compound A is.arrow_forwardIndicate how to obtain the compound 2-Hydroxy-2-phenylacetonitrile from phenylmethanol.arrow_forwardIndicate the reagent needed to go from cyclopentane-CH2-CHO to cyclopentane-CH2-CH=CH-C6H5.arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning

