
Interpretation:
The resonance structure of the compound has to be given.
Concept Introduction:
Resonance is a method to relating to describe about delocalized electrons inside certain molecules or polyatomic ions where the Lewis structure can’t be expressed. A molecule or ion containing delocalized electrons can be represented by using several similar structures such structures are called as resonance structures or canonical structures.
The delocalization of electron lowers the potential energy of the substance and making it more stable than any of the contributing structures. The variation in the potential energy of the actual structure and that of resemblance structure with lowest potential energy is known as resonance energy or delocalization energy.
Curved arrows:
The necessary tools to draw perfect resonance structure are curved arrows. Curved arrows don’t represent the flow of electrons. A tail and a head can be seen in curved arrow.
A head and tail of every arrow are to be drawn in the exact location. The tail represents where the electrons are originated, and the head represents the place where the electrons are going.
Lone pair:
A lone pair is given by a pair of outer most electrons that are not shared with another atom, otherwise called as non bonding pair. These are generally found in the valence shell of atom and are identified by Lewis structure. Pairs of electrons are considered as lone pairs when two electrons are paired and are not participated in

Want to see the full answer?
Check out a sample textbook solution
Chapter 2 Solutions
Organic Chemistry Third Edition + Electronic Solutions Manual And Study Guide
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





