Interpretation:
All carbon atoms, hydrogen atoms and lone pairs can be drawn for the given bond-line structured compounds.
Concept introduction:
The representation of each atom with their symbol in a bond-line structure of a compound is called as the structural formula of that compound. In bond-line structure each corner represent the carbon atom which in bonded with hydrogen atoms. The number of hydrogen depends upon the number of atoms attached to that particular carbon, because the covalence of carbon should be four. The lone-pairs of the compound are the non-bonding valence electrons of hetero atoms occupied in the compound. It can be calculated by the formula,
Then the lone pairs are represented as dots on its heteroatoms in structural formula.
To draw: the all carbon atoms, hydrogen atoms and lone pairs for given compounds can be do with looking upon the corners of bond-line structure and attached heteroatoms.
Answer to Problem 34PP
The structural formula of the following given compounds are
Explanation of Solution
To draw all carbon atoms for given bond-line structures of compounds.
Put a carbon atom ‘C’ to each corner in bond-line structure.
In bond-line structure, every corner represents the carbon atoms. Hence, all corners are replaced with the carbon symbol ‘C’.
To draw hydrogen atoms for given bond-line structure of compounds.
Count the adjacent atoms of carbon whether it is carbon or heteroatoms and if it is less than four we have to add hydrogen atoms in that carbon to make four as covalence.
To draw lone pairs for compound structures.
In all given compounds the lone pairs of electron are carried by heteroatoms attached to the carbon. Hence, identify the heteroatoms presented in the compound and count its bond pairs of electrons. Because Lone pairs of electron are the non-bonding pairs of electrons. The numbers of lone pairs of electron are calculated by the formula,
These lone pairs are represented by dots on the atoms in structural formula.
The structural formula of given bond-line structured compounds are drawn by representing the all atoms presented in that compound and the number of lone pairs of electron are calculated by above equation.
Want to see more full solutions like this?
Chapter 2 Solutions
Organic Chemistry Third Edition + Electronic Solutions Manual And Study Guide
- 5. a. Data were collected for Trial 1 to determine the molar mass of a nonvolatile solid solute when dissolved in cyclo- hexane. Complete the table for the analysis (See Report Sheet). Record calculated values with the correct number of significant figures. B. Freezing Point of Cyclohexane plus Calculation Zone Unknown Solute 2. Mass of cyclohexane (g) 10.14 Part C.4 3. Mass of added solute (g) 0.255 C. Calculations 1. k; for cyclohexane (°C⚫ kg/mol) 20.0 2. Freezing point change, AT, (°C) 3.04 Part C.6 3. Mass of cyclohexane in solution (kg) 4. Moles of solute, total (mol) Show calculation. 5. Mass of solute in solution, total (g) 6. Molar mass of solute (g/mol) Show calculation.arrow_forwardDraw and name the R groups of all 20 amino acids.arrow_forward3. Two solutions are prepared using the same solute: Solution A: 0.14 g of the solute dissolves in 15.4 g of t-butanol Solution B: 0.17 g of the solute dissolves in 12.7 g of cyclohexane Which solution has the greatest freezing point change? Show calculations and explain.arrow_forward
- 2. Give the ground state electron configuration (e.g., 02s² σ*2s² П 2p²) for these molecules and deduce its bond order. Ground State Configuration Bond Order H2+ 02- N2arrow_forward1. This experiment is more about understanding the colligative properties of a solution rather than the determination of the molar mass of a solid. a. Define colligative properties. b. Which of the following solutes has the greatest effect on the colligative properties for a given mass of pure water? Explain. (i) 0.01 mol of CaCl2 (ii) 0.01 mol of KNO3 (iii) 0.01 mol of CO(NH2)2 (an electrolyte) (an electrolyte) (a nonelectrolyte)arrow_forward5. b. For Trials 2 and 3, the molar mass of the solute was 151 g/mol and 143 g/mol respectively. a. What is the average molar mass of the solute ? b. What are the standard deviation and the relative standard deviation (%RSD) for the molar mass of the solute ?arrow_forward
- Show work. Don't give Ai generated solutionarrow_forward2. Explain why ice cubes formed from water of a glacier freeze at a higher temperature than ice cubes formed from water of an under- ground aquifer. Photodynamic/iStockphotoarrow_forwardShow reaction mechanism. don't give Ai generated solutionarrow_forward
- 7. Draw the Lewis structures and molecular orbital diagrams for CO and NO. What are their bond orders? Are the molecular orbital diagrams similar to their Lewis structures? Explain. CO Lewis Structure NO Lewis Structure CO Bond Order NO Bond Order NO Molecular Orbital Diagram CO Molecular Orbital Diagramarrow_forward5. The existence of compounds of the noble gases was once a great surprise and stimulated a great deal of theoretical work. Label the molecular orbital diagram for XeF (include atom chemical symbol, atomic orbitals, and molecular orbitals) and deduce its ground state electron configuration. Is XeF likely to have a shorter bond length than XeF+? Bond Order XeF XeF+arrow_forward6. Draw the molecular orbital diagram shown to determine which of the following is paramagnetic. B22+ B22+, B2, C22, B22 and N22+ Molecular Orbital Diagram B2 C22- B22- N22+ Which molecule is paramagnetic?arrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY