Chapter 21, Problem 73IAE

Interpretation Introduction

(a)

Interpretation:

To calculate the molar solubility of ${\text{MgCO}}_{\text{3}}$ in $1.00\text{M}$

${\text{NH}}_{\text{4}}\text{Cl}\left(\text{aq}\right)$.

Concept introduction:

Molar solubility is the moles number of substances which is dissolved in 1L of solution before the solution becomes saturated. Molar solubility is calculated from solubility product constant and stoichiometry.

Interpretation Introduction

(b)

Interpretation:

To calculate the molar solubility of ${\text{MgCO}}_{\text{3}}$ in $1.00\text{M}{\text{NH}}_3$ and $1.00\text{M}{\text{NH}}_4\text{Cl}$.

Concept introduction:

Molar solubility is the moles number of substances which is dissolved in 1L of solution before the solution becomes saturated. Molar solubility is calculated from solubility product constant and stoichiometry.

Interpretation Introduction

(c)

Interpretation:

To calculate the molar solubility of ${\text{MgCO}}_{\text{3}}$ in $0.100\text{M}{\text{NH}}_3$ and $1.00\text{M}{\text{NH}}_4\text{Cl}$.

Concept introduction:

Molar solubility is the moles number of substances which is dissolved in 1L of solution before the solution becomes saturated. Molar solubility is calculated from solubility product constant and stoichiometry.