Chapter 21, Problem 64IAE

Interpretation Introduction

(a)

Interpretation:

To calculate $\Delta H^0$ of the reaction.

Concept introduction:

The standard enthalpy change $\left(\Delta H^0\right)$ of a reaction is equal to the sum of standard enthalpies of formation of product minus standard enthalpies of formation of reactant that is

$\Delta H_{\text{reaction}}^0={\displaystyle \sum \Delta H_{\text{f}}^0}\left(\text{Product}\right)-{\displaystyle \sum \Delta H_{\text{f}}^0}\left(\text{Reactant}\right)$ .......(1)

Interpretation Introduction

(b)

Interpretation:

To calculate $\Delta H^0$ of the reaction.

Concept introduction:

The standard enthalpy change $\left(\Delta H^0\right)$ of a reaction is equal to the sum of standard enthalpies of formation of product minus standard enthalpies of formation of reactant that is

$\Delta H_{\text{reaction}}^0={\displaystyle \sum \Delta H_{\text{f}}^0}\left(\text{Product}\right)-{\displaystyle \sum \Delta H_{\text{f}}^0}\left(\text{Reactant}\right)$ .......(1)

Interpretation Introduction

(c)

Interpretation:

To calculate $\Delta H^0$ of the reaction.

Concept introduction:

The standard enthalpy change $\left(\Delta H^0\right)$ of a reaction is equal to the sum of standard enthalpies of formation of product minus standard enthalpies of formation of reactant that is

$\Delta H_{\text{reaction}}^0={\displaystyle \sum \Delta H_{\text{f}}^0}\left(\text{Product}\right)-{\displaystyle \sum \Delta H_{\text{f}}^0}\left(\text{Reactant}\right)$ .......(1)