The balanced chemical equation for the reaction of barium oxide with dioxygen should be given. Concept introduction: A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction. A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.

Question

A solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell: calomel electrode (saturated)//titration solution/Hg(l) Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E. Hg2+(aq) + 2e- = Hg(l) E0= 0.852 V E' (calomel electrode, saturated KCl) = 0.241 V

Answer 1

Question

Chapter 21, Problem 72GQ

(a)

Interpretation Introduction

Interpretation: The balanced chemical equation for the reaction of barium oxide with dioxygen should be given.

Concept introduction:

A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.

A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the reaction of iron with barium peroxide should be given.

Concept introduction:

A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.

A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.

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A solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell: calomel electrode (saturated)//titration solution/Hg(l) Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E. Hg2+(aq) + 2e- = Hg(l) E0= 0.852 V E' (calomel electrode, saturated KCl) = 0.241 V

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