ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE
10th Edition
ISBN: 9781260008562
Author: Carey
Publisher: MCG
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Question
Chapter 21, Problem 51P
Interpretation Introduction
Interpretation:
The structure of capsaicin with respect to thelaboratory synthesis is to be determined.
Concept Introduction:
>The replacement or substitution of one
The electron rich chemical species that contains negative charge or lone pair of electrons are known as nucleophiles and the species that are electron deficient are known as electrophiles.
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Students have asked these similar questions
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
Chapter 21 Solutions
ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE
Ch. 21.1 - Prob. 1PCh. 21.1 - Prob. 2PCh. 21.1 - Prob. 3PCh. 21.1 - Prob. 4PCh. 21.1 - Prob. 5PCh. 21.2 - Prob. 6PCh. 21.2 - Prob. 7PCh. 21.2 - Prob. 8PCh. 21.3 - Prob. 9PCh. 21.3 - Prob. 10P
Ch. 21.3 - Prob. 11PCh. 21.4 - Prob. 12PCh. 21.4 - Prob. 13PCh. 21.5 - Prob. 14PCh. 21.5 - Problem 21.15 Write the structure of the Dieckmann...Ch. 21.5 - Prob. 16PCh. 21.5 - Prob. 17PCh. 21.6 - Prob. 18PCh. 21.6 - Prob. 19PCh. 21.6 - Prob. 20PCh. 21.6 - Prob. 21PCh. 21.6 - Prob. 22PCh. 21.7 - Prob. 23PCh. 21.8 - Problem 21.24 Mesityl oxide is an industrial...Ch. 21.8 - Prob. 25PCh. 21.8 - Prob. 26PCh. 21.8 - Prob. 27PCh. 21.8 - Prob. 28PCh. 21 - Prob. 29PCh. 21 - Terreic acid, a naturally occurring antibiotic...Ch. 21 - Prob. 31PCh. 21 - Prob. 32PCh. 21 - Prob. 33PCh. 21 - Prob. 34PCh. 21 - Give the structure of the expected organic product...Ch. 21 - Prob. 36PCh. 21 - Prob. 37PCh. 21 - Prob. 38PCh. 21 - Prob. 39PCh. 21 - Give the structure of the principal organic...Ch. 21 - Prob. 41PCh. 21 - Prob. 42PCh. 21 - Prob. 43PCh. 21 - Prob. 44PCh. 21 - Prob. 45PCh. 21 - Prob. 46PCh. 21 - Prob. 47PCh. 21 - The use of epoxides as alkylating agents for...Ch. 21 - Prob. 49PCh. 21 - Show how you could prepare each of the following...Ch. 21 - Prob. 51PCh. 21 - Prob. 52PCh. 21 - Prob. 53PCh. 21 - Prob. 54PCh. 21 - The - methylene ketone sarkomycin has an...Ch. 21 - - Lactone can be prepared in good yield from...Ch. 21 - Prob. 57PCh. 21 - Prob. 58DSPCh. 21 - The Enolate Chemistry of Dianionss The synthetic...Ch. 21 - Prob. 60DSPCh. 21 - Prob. 61DSPCh. 21 - Prob. 62DSPCh. 21 - Prob. 63DSP
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