COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
2nd Edition
ISBN: 9781319414597
Author: Freedman
Publisher: MAC HIGHER
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Chapter 21, Problem 38QAP
To determine

(a)

The rms current passing through the resistor.

Expert Solution
Check Mark

Answer to Problem 38QAP

The rms current is 0.353A.

Explanation of Solution

Given info:

The Vmax voltage is 50.0 V.

The resistance of the resistor is 100.0Ω.

Formula used:

The relation between rms current and r.m.s. voltage is,

  Irms=VrmsR  Equation-1

Here, Vrms is the V r.m.s. voltage, Irms is the rms current and R is the resistor.

The relation between V r.m.s. voltage and peak voltage is,

  Vrms=Vmax2  Equation-2

Here, Vrms is the V r.m.s. voltage and Vmax is the maximum voltage drop is,

Using equation-1 the expression for peak voltage is

  Irms=Vmax2R   Equation-3

Calculation:

Finding rms current:

Substitute the all given value in equation-3 to find Vmax,

  Irms=50.0V2×100 =0.353A(rms) Equation-4

Conclusion:

From equation-4 the rms current is 0.353A.

To determine

(b)

The maximum voltage across the resistor.

Expert Solution
Check Mark

Answer to Problem 38QAP

The maximum voltage is 707V.

Explanation of Solution

Given info:

The rms current is 2.50A.

The resistance of the resistor is 200.0Ω.

Formula used:

The relation between rms current and maximum voltage is,

  Irms=Vmax2R

Here, Vmax is the maximum voltage, Irms is the rms current and R is the resistor.

Rearrange the equation to find the Vmax

  Vmax=2IrmsR   Equation-4

Calculation:

Finding maximum voltage:

Substitute the all given value in equation-4 to find Vmax,

  Vmax=2×2.5A×200Ω=707V Equation-5

Conclusion:

From equation-5 the maximum voltage is 707V.

To determine

(c)

The resistance of the resistor.

Expert Solution
Check Mark

Answer to Problem 38QAP

The resistance of the resistor is 156Ω.

Explanation of Solution

Given info:

  • The rms current is 127mA.
  • Converting milli-Ampere to ampere.

      127mA=127mA×1A1000mA=127×103A

  • The maximum voltage is 28.0V.

Formula used:

The relation between rms current and maximum voltage is,

  Irms=Vmax2R

Here, Vmax is the maximum voltage, Irms is the rms current and R is the resistor.

Rearrange the equation to find the R.

  R=Vmax2Irms   Equation-6

Calculation:

Finding maximum voltage:

Substitute the all given value in equation-6 to find R,

  R=28.0V2×1127×103A=156Ω Equation-7

Conclusion:

From equation-7 the resistance of the resistor is 156Ω.

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Chapter 21 Solutions

COLLEGE PHYSICS LL W/ 6 MONTH ACCESS

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