Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
bartleby

Concept explainers

Question
Book Icon
Chapter 21, Problem 21.59QE

(a)

Interpretation Introduction

Interpretation:

Amount of coal that is required to produce the energy as same as fission of 1kg uranium has to be calculated in metric tons.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given information:

Amount of energy produced from one kilogram of coal is 2.8×104kJ.  Amount of energy produced by fission of 1mol of 235U is 1.9×1010kJ.

Molar mass of 235U is 235.05g/mol.  Therefore, mass of one mole of 235U is 235.05g.

Energy released by one mole of 235U is 1.9×1010kJ.  This is equal to energy released by 0.23505kg of 235U.

Amount of energy released by one kilogram of uranium-235 is calculated as shown below.

    Energyreleased=1.9×1010kJ0.23505kg×1kg=8.083×1010kJ=8.1×1010kJ

Therefore, one kilogram of uranium-235 releases 8.1×1010kJ of energy.

One kilogram of high-grade coal produces 2.8×104kJ of energy.  Mass of coal required to produce 8.1×1010kJ of energy can be calculated as shown below.

    Massofcoal=8.1×1010kJ×1kg2.8×104kJ=2.892×106kg=2.9×106kg

Conversion of kilogram into metric ton can be done using the conversion factor as shown below.

    2.9×106kg=2.9×106kg×1metricton1000kg=2.9×103metricton

Therefore, the amount of coal required to produce the same amount of energy as of one kilogram of uranium-235 is 2.9×103metricton.

(b)

Interpretation Introduction

Interpretation:

Metric tons of sulfur dioxide that is produced by burning 2.9×103metricton of coal has to be calculed.

(b)

Expert Solution
Check Mark

Explanation of Solution

In the problem statement it is given that coal contains 0.90% mass sulfur.  This means 0.9g of sulfur is present in 100g of coal.  Total grams of sulfur present in 2.9×103metricton of coal is calculated as shown below.

    MassofSulfur=2.9×103metricton coal×0.9gS100gcoal=2.9×109g coal×0.9gS100gcoal=2.61×107gS

Reaction between sulfur and oxygen to produce sulfur dioxide can be given as shown.

    S+O2SO2

From the equation, it is found that one mole of sulfur reacts with one mole of oxygen to form one mole of sulfur dioxide.  Molar mass of sulfur is 32.1g and that of SO2 is 64.1g.  This means 32.1g of sulfur burns in oxygen to produce 64.1g of sulfur dioxide.  Therefore, the amount of sulfur dioxide produced by burning 2.61×107g of sulfur can be calculated as shown below.

    2.61×107g1molS32.1gS×1molSO21molS×64.1gSO21molSO2=167.301×10732.1gSO2=5.2×107gSO2

Conversion of gram into metric ton can be done using the conversion factor as shown below.

    5.2×107gSO2=5.2×107g×1metricton1000000g=5.2×101metricton=52 metricton

Therefore, the amount of sulfur dioxide produced is 52 metrictons.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Protecting Groups and Carbonyls 6) The synthesis generates allethrolone that exhibits high insect toxicity but low mammalian toxicity. They are used in pet shampoo, human lice shampoo, and industrial sprays for insects and mosquitos. Propose detailed mechanistic steps to generate the allethrolone label the different types of reagents (Grignard, acid/base protonation, acid/base deprotonation, reduction, oxidation, witting, aldol condensation, Robinson annulation, etc.) III + VI HS HS H+ CH,CH,Li III I II IV CI + P(Ph)3 V ༼ Hint: no strong base added VI S VII IX HO VIII -MgBr HgCl2,HgO HO. isomerization aqeuous solution H,SO, ༽༽༤༽༽ X MeOH Hint: enhances selectivity for reaction at the S X ☑
Draw the complete mechanism for the acid-catalyzed hydration of this alkene. esc 田 Explanation Check 1 888 Q A slock Add/Remove step Q F4 F5 F6 A བྲA F7 $ % 5 @ 4 2 3 & 6 87 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce W E R T Y U S D LL G H IK DD 요 F8 F9 F10 F1 * ( 8 9 0 O P J K L Z X C V B N M H He command
Explanation Check F1 H₂O H₂ Pd 1) MCPBA 2) H3O+ 1) Hg(OAc)2, H₂O 2) NaBH4 OH CI OH OH OH hydration halohydrin formation addition halogenation hydrogenation inhalation hydrogenation hydration ☐ halohydrin formation addition halogenation formation chelation hydrogenation halohydrin formation substitution hydration halogenation addition Ohalohydrin formation subtraction halogenation addition hydrogenation hydration F2 80 F3 σ F4 F5 F6 1 ! 2 # 3 $ 4 % 05 Q W & Å © 2025 McGraw Hill LLC. All Rights Reserved. F7 F8 ( 6 7 8 9 LU E R T Y U A F9

Chapter 21 Solutions

Chemistry: Principles and Practice

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Text book image
Introductory Chemistry For Today
Chemistry
ISBN:9781285644561
Author:Seager
Publisher:Cengage