Concept explainers
(a)
Interpretation:
Synthesis of benzoic acid has to be shown.
Concept Introduction:
Benzoic acid can be synthesized from ethyl benzene using
(b)
Interpretation:
Synthesis of 1-bromo-1-phenylethane has to be shown.
Concept Introduction:
1-bromo-1-phenylethane can be synthesized using the reagents
(c)
Interpretation:
Synthesis of styrene has to be shown.
Concept Introduction:
The reagent used for the conversion of 1-bromo-1-phenylethane to styrene is
(d)
Interpretation:
Synthesis of 1-phenylethanol has to be shown.
Concept Introduction:
1-phenyl ethanol can be synthesized from styrene by the addition of water in acidic medium.
(e)
Interpretation:
Synthesis of acetophenone has to be shown.
Concept Introduction:
Acetophenone can be synthesized from benzene and benzene can be synthesized from benzoic acid. When
(f)
Interpretation:
Synthesis of 2-phenylethanol has to be shown.
Concept Introduction:
2-phenylethanol can be synthesized from styrene through hydroboration oxidation reaction.
(g)
Interpretation:
Synthesis of phenyl acetaldehyde has to be shown.
Concept Introduction:
phenyl acetaldehyde can be synthesized from styrene.
The reagent titanosilicate and hydrogen peroxide enhance the ethylene epoxidation reaction.
Al-SBA-15 is an aluminosilicate compound having mesoporous structure. It helps in isomerization of
(h)
Interpretation:
Synthesis of 2-phenylacetic acid has to be shown.
Concept Introduction:
The ester formed during this reaction is treated with
(i)
Interpretation:
Synthesis of 1,2-dibromo-1-phenylethane has to be shown.
Concept Introduction:
1,2-dibromo-1-phenylethane can be synthesized from styrene through bromination reaction.
(j)
Interpretation:
Synthesis of phenylethyne has to be shown.
Concept Introduction:
phenylethyne can be synthesized from 1,2-dibromo-1-phenylethane. The reagent used is sodium amide in liquid ammonia cause dehydrohalogenation.
(k)
Interpretation:
Synthesis of 1-phenyl-4-penten-1-yne has to be shown.
Concept Introduction:
1-phenyl-4-penten-1-yne can be prepared from phenylethyne and prop-2-en-1-ol. Carbon-carbon coupling will occur by using these reagents.
(l)
Interpretation:
Synthesis of 1-phenyloctyne has to be shown.
Concept Introduction:
1-phenyloctyne can be synthesized from phenylethyne through two steps. In the first step phenylethyne treated with Grignard reagent to get 1-phenylethyne magnesium bromide which then react with hexyl iodide in second step to give 1-phenyloctyne.
(m)
Interpretation:
Concept Introduction:
(n)
Interpretation:
Concept Introduction:
Trending nowThis is a popular solution!
Chapter 21 Solutions
OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition
- 5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forwardShow work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?arrow_forward13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning