
Concept explainers
(a)
Interpretation:
Whether or not the given sole fact supports the possible identification of the sample as
Concept introduction:
A unit cell of the crystal is the three-dimensional arrangement of the atoms present in the crystal. The unit cell is the smallest and simplest unit of the crystal which on repetition forms an entire crystal. Unit cell can be a cubic unit cell or hexagonal unit cell. The classification of a unit cell depends on the lattice site occupied by the atoms.
(b)
Interpretation:
Whether or not the given sole fact supports the possible identification of the sample as
Concept introduction:
A unit cell of the crystal is the three-dimensional arrangement of the atoms present in the crystal. The unit cell is the smallest and simplest unit of the crystal which on repetition forms an entire crystal. Unit cell can be a cubic unit cell or hexagonal unit cell. The classification of a unit cell depends on the lattice site occupied by the atoms.
(c)
Interpretation:
Whether or not the given sole fact supports the possible identification of the sample as
Concept introduction:
A unit cell of the crystal is the three-dimensional arrangement of the atoms present in the crystal. The unit cell is the smallest and simplest unit of the crystal which on repetition forms an entire crystal. Unit cell can be a cubic unit cell or hexagonal unit cell. The classification of a unit cell depends on the lattice site occupied by the atoms.
(d)
Interpretation:
Whether or not given sole fact supports the possible identification of the sample as
Concept introduction:
A unit cell of the crystal is the three-dimensional arrangement of the atoms present in the crystal. The unit cell is the smallest and simplest unit of the crystal which on repetition forms an entire crystal. Unit cell can be a cubic unit cell or hexagonal unit cell. The classification of a unit cell depends on the lattice site occupied by the atoms.

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Chapter 21 Solutions
Physical Chemistry
- At 300 K, in the decomposition reaction of a reactant R into products, several measurements of the concentration of R over time have been made (see table). Calculate the order of the reaction. t/s [R]/ (mol L-1) 0 0,5 171 0,16 720 0,05 1400 0,027arrow_forwardWrite the correct IUPAC names of the molecules in the picturearrow_forwardHow many grams of solid NaCN have to be added to 1.5L of water to dissolve 0.18 mol of Fe(OH)3 in the form Fe(CN)63 - ? ( For simplicity, ignore the reaction of CN - ion with water) Ksp for Fe(OH)3 is 2.8E -39, and Kform for Fe(CN)63 - is 1.0E31arrow_forward
- Draw the most stable chair conformation of 1-ethyl-1-methylcyclohexane, clearly showing the axial and equatorial substituents. [4] Draw structures corresponding to the following IUPAC name for each of the following compounds; [5] i) 4-Isopropyl-2,4,5-trimethylheptane ii) trans-1-tert-butyl-4-ethylcyclohexane iii) Cyclobutylcycloheptane iv) cis-1,4-di-isopropylcyclohexane (chair conformation) v) 3-Ethyl-5-isobutylnonanearrow_forwardDraw and name molecules that meet the following descriptions; [4] a) An organic molecule containing 2 sp2 hybridised carbon and 1 sp-hybridised carbon atom. b) A cycloalkene, C7H12, with a tetrasubstituted double bond. Also answer question 2 from the imagearrow_forwardH 14. Draw the line angle form of the following molecule make sure you use the proper notation to indicate spatial positioning of atoms. F F H 15. Convert the following condensed form to line angle form: (CH3)3CCH2COCH2CON(CH2CH3)2arrow_forward
- In a reaction between two reactants A and B, the half-life is the same for both only if(A) the stoichiometry A:B is 1:1.(B) the stoichiometry A:B is 1:2 or 2:1.arrow_forwardIn a reaction between two reactants A and B, the half-life is the same for both.(1) Only if the stoichiometry A:B is 1:1.(2) If the initial quantities of A and B are in their stoichiometric ratios.arrow_forwardThere are 48 pairs of students in the following table. Each pair has quantitatively determined the mass of taurine in a 250 mL can of the popular energy drink marketed as “Munster” using High Performance Liquid Chromatography (HPLC). The class results are presented below: QUESTION: Calculate the measurement of uncertainty and provide the data in a spreadsheet table. Mass of Taurine (mg) Mass of Taurine (mg) (Table continued) 152.01 152.23 151.87 151.45 154.11 152.64 152.98 153.24 152.88 151.45 153.49 152.48 150.68 152.33 151.52 153.63 152.48 151.68 153.17 153.40 153.77 153.67 152.34 153.16 152.57 153.02 152.86 151.50 151.23 152.57 152.72 151.54 146.47 152.38 152.44 152.54 152.53 152.54 151.32 152.87 151.24 153.26 152.02 152.90 152.87 151.49 152.46 152.58arrow_forward
- 1. Predict the organic product(s) of the following reactions. Assume excess of reagents unless otherwise noted. a) &l BH3 •THF b) 1) NaOH 2) H3O+ solve d) ala 1) EtMgBr 2) H3O+ e) H2N سكر CuLi NH2 1) SOCI2 2) EtMgBr 3) H3O+ NC H3O+ Δarrow_forwardThere are 48 pairs of students in the following table. Each pair has quantitatively determined the mass of taurine in a 250 mL can of the popular energy drink marketed as “Munster” using High Performance Liquid Chromatography (HPLC). The class results are presented below: QUESTION: Summarise and report these results including an indication of measurement uncertainty. In both calculation samples calculate if an outlier is present, max value, number of samples, mean, standard deviation, g (suspect), g (critical) and t (critical). Mass of Taurine (mg) Mass of Taurine (mg) (Table continued) 152.01 152.23 151.87 151.45 154.11 152.64 152.98 153.24 152.88 151.45 153.49 152.48 150.68 152.33 151.52 153.63 152.48 151.68 153.17 153.40 153.77 153.67 152.34 153.16 152.57 153.02 152.86 151.50 151.23 152.57 152.72 151.54 146.47 152.38 152.44 152.54 152.53 152.54 151.32…arrow_forwardIndicate the rate expressions for reactions that have order 0, 1, and 2.arrow_forward
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