Electric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (a) What magnitude and sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field? (b) What would be the force of repulsion between two people each with the charge calculated| in part (a) and separated by a distance of 100 m? Is use of Ihe earth s electric field a feasible means of flight? Why or why not?
Electric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (a) What magnitude and sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field? (b) What would be the force of repulsion between two people each with the charge calculated| in part (a) and separated by a distance of 100 m? Is use of Ihe earth s electric field a feasible means of flight? Why or why not?
Electric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (a) What magnitude and sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field? (b) What would be the force of repulsion between two people each with the charge calculated| in part (a) and separated by a distance of 100 m? Is use of Ihe earth s electric field a feasible means of flight? Why or why not?
The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed toward the center of the earth.
(a) What magnitude and a sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field?
(b) What would be the force of repulsion between two people each with the charge calculated in part and separated by a distance of 100 m?
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the
skipped part.
Tutorial Exercise
A proton accelerates from rest in a uniform electric field of 663 N/C. At some later time, its speed is 1.29 x 106 m/s.
(a) Find the magnitude of the acceleration of the proton.
(b) How long does it take the proton to reach this speed?
(c) How far has it moved in that interval?
(d) What is its kinetic energy at the later time?
Step 1
eE
(a) The force exerted on the proton of charge qp = +e by the electric field has magnitude F = q E = EE where E is the magnitude of the electric field and F is the magnitude of the force.
ap
Newton's second law gives the acceleration a of the proton in terms of its charge and mass m, as
a =
F eE
Mp Mp
(1.60 x 10-19,
=
= 6.35
663✔
9c)(663
1.673 x 10-27 kg)
6.34 x 1010 m/s².
663 N/C)
1 kg. m/s²
1 N
The Earth has a net electric charge that causes a field at points near its surface equal to
150 N/C and directed in toward the center of the Earth.
a) What magnitude and sign of charge would a human with mass 60 kg have to
acquire to overcome his or her weight by the force exerted by the Earth's electric
field?
b) What would be the force of repulsion between two people each with the charge
calculated in part (a) and separated by a distance of 100 m?
c)
Is use of the Earth's electric field a feasible means of flight? Why or why not?
Chapter 21 Solutions
University Physics with Modern Physics (14th Edition)
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