Electric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (a) What magnitude and sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field? (b) What would be the force of repulsion between two people each with the charge calculated| in part (a) and separated by a distance of 100 m? Is use of Ihe earth s electric field a feasible means of flight? Why or why not?
Electric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (a) What magnitude and sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field? (b) What would be the force of repulsion between two people each with the charge calculated| in part (a) and separated by a distance of 100 m? Is use of Ihe earth s electric field a feasible means of flight? Why or why not?
Electric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (a) What magnitude and sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field? (b) What would be the force of repulsion between two people each with the charge calculated| in part (a) and separated by a distance of 100 m? Is use of Ihe earth s electric field a feasible means of flight? Why or why not?
The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed toward the center of the earth.
(a) What magnitude and a sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field?
(b) What would be the force of repulsion between two people each with the charge calculated in part and separated by a distance of 100 m?
(a) Two protons in a molecule are 4.40 × 10
-10
m apart. Find the electric force exerted by one proton on the other.
magnitude
What is the equation for the electrical force acting between two charged objects? N
direction
repulsive
(b) State how the magnitude of this force compares with the magnitude of the gravitational force exerted by one proton on the other.
Fe
%D
F.
What is the mass of a proton?
(c) What must be a particle's charge-to-mass ratio if the magnitude of the gravitational force between two of these particles is equal to the magnitude of electric force between them?
С/kg
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the
skipped part.
Tutorial Exercise
A proton accelerates from rest in a uniform electric field of 663 N/C. At some later time, its speed is 1.29 x 106 m/s.
(a) Find the magnitude of the acceleration of the proton.
(b) How long does it take the proton to reach this speed?
(c) How far has it moved in that interval?
(d) What is its kinetic energy at the later time?
Step 1
eE
(a) The force exerted on the proton of charge qp = +e by the electric field has magnitude F = q E = EE where E is the magnitude of the electric field and F is the magnitude of the force.
ap
Newton's second law gives the acceleration a of the proton in terms of its charge and mass m, as
a =
F eE
Mp Mp
(1.60 x 10-19,
=
= 6.35
663✔
9c)(663
1.673 x 10-27 kg)
6.34 x 1010 m/s².
663 N/C)
1 kg. m/s²
1 N
Chapter 21 Solutions
University Physics with Modern Physics (14th Edition)
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