CHEMISTRY 1111 LAB MANUAL >C<
CHEMISTRY 1111 LAB MANUAL >C<
1st Edition
ISBN: 9781307092097
Author: Chang
Publisher: MCG/CREATE
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Chapter 21, Problem 21.19QP
Interpretation Introduction

Interpretation:

The terms conductor, insulator, semiconducting elements, donor impurities, acceptor impurities, n-type semiconductors, and p-type semiconductors has to be defined.

Concept introduction:

Conductor: A conductor is a material which allows the flow of an electrical current.

Insulator: An insulator is a material which does not allows the flow of an electrical current.

Semiconducting elements: Semiconducting elements are partially allows flow of an electrical current.

Donor impurities: Conduction elements producing impurities are said to be donor impurities.

Acceptor impurities: Impurities which are electron deficient are said to be acceptor impurities.

n-type semiconductors: Solid semiconducting material having donor impurities are said to be n-type semiconductors, where “n” indicates negative which means the charge of the extra electron.

p-type semiconductors: Semiconducting material having acceptor impurities are said to be p-type semiconductors, where p indicates positive.

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redraw the flowchart with boxes and molecules written in them
Part I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400
• Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peak

Chapter 21 Solutions

CHEMISTRY 1111 LAB MANUAL >C<

Ch. 21 - In the Mond process for the purification of...Ch. 21 - Copper is purified by electrolysis (see Figure...Ch. 21 - Prob. 21.13QPCh. 21 - Prob. 21.14QPCh. 21 - Prob. 21.15QPCh. 21 - Prob. 21.16QPCh. 21 - Which of the following compounds would require...Ch. 21 - Although iron is only about two-thirds as abundant...Ch. 21 - Prob. 21.19QPCh. 21 - Prob. 21.20QPCh. 21 - Prob. 21.21QPCh. 21 - Prob. 21.22QPCh. 21 - Prob. 21.23QPCh. 21 - Why is potassium usually not prepared...Ch. 21 - Prob. 21.25QPCh. 21 - Prob. 21.26QPCh. 21 - Prob. 21.27QPCh. 21 - Prob. 21.28QPCh. 21 - Prob. 21.29QPCh. 21 - Prob. 21.30QPCh. 21 - Prob. 21.31QPCh. 21 - Prob. 21.32QPCh. 21 - Prob. 21.33QPCh. 21 - Prob. 21.34QPCh. 21 - Prob. 21.35QPCh. 21 - Prob. 21.36QPCh. 21 - Prob. 21.37QPCh. 21 - Prob. 21.38QPCh. 21 - Prob. 21.39QPCh. 21 - Prob. 21.40QPCh. 21 - Prob. 21.41QPCh. 21 - Prob. 21.42QPCh. 21 - Prob. 21.43QPCh. 21 - With the Hall process, how many hours will it take...Ch. 21 - Aluminum forms the complex ions AlCl4 and AlF63....Ch. 21 - The overall reaction for the electrolytic...Ch. 21 - Prob. 21.47QPCh. 21 - Write a balanced equation for the thermal...Ch. 21 - Prob. 21.49QPCh. 21 - The pressure of gaseous Al2Cl6 increases more...Ch. 21 - Starting with aluminum, describe with balanced...Ch. 21 - Prob. 21.52QPCh. 21 - Prob. 21.53QPCh. 21 - Prob. 21.54QPCh. 21 - Prob. 21.55QPCh. 21 - Referring to Figure 21.6, would you expect H2O and...Ch. 21 - A 0.450-g sample of steel contains manganese as an...Ch. 21 - Given that Gf (Fe2O3) = 741.0 kJ/mol and that Gf...Ch. 21 - Prob. 21.59QPCh. 21 - Prob. 21.60QPCh. 21 - Prob. 21.61QPCh. 21 - Explain each of the following statements: (a) An...Ch. 21 - Prob. 21.63QPCh. 21 - Write a balanced equation for the reaction between...Ch. 21 - Prob. 21.65QPCh. 21 - Explain why most metals have a flickering...Ch. 21 - Prob. 21.67QPCh. 21 - Prob. 21.68QPCh. 21 - The following are two reaction schemes involving...Ch. 21 - Prob. 21.70QPCh. 21 - Prob. 21.71QPCh. 21 - Prob. 21.72QPCh. 21 - After heating, a metal surface (such as that of a...Ch. 21 - Prob. 21.74QPCh. 21 - Prob. 21.75QPCh. 21 - As stated in the chapter, potassium superoxide...Ch. 21 - A sample of 10.00 g of sodium reacts with oxygen...
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