CHEMISTRY 1111 LAB MANUAL >C<
CHEMISTRY 1111 LAB MANUAL >C<
1st Edition
ISBN: 9781307092097
Author: Chang
Publisher: MCG/CREATE
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Chapter 21, Problem 21.51QP

Starting with aluminum, describe with balanced equations how you would prepare (a) Al2Cl6, (b) Al2O3, (c) Al2(SO4)3, (d) NH4Al(SO4)2 · 12H2O.

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The balanced equations for the given aluminum compounds has to be described.

Concept introduction:

  • There is a law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical equation is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.

Answer to Problem 21.51QP

The balanced equation for preparation of Al2Cl6 is,

2Al(s) + 3Cl2(g) Al2Cl6(s)

Explanation of Solution

To write the balanced equation for preparation of Al2Cl6

We can produce Al2Cl6 by reaction of aluminum with chlorine gas.

Al(s) + Cl2(g) Al2Cl6(s)

Here, the reaction is unbalanced. So we need to balance it.  To balance the reaction, calculate the number of atoms present in left side and right side.  Finally, obtained values could place it as coefficients of reactants as well as products.  The balanced equation is

2Al(s) + 3Cl2(g) Al2Cl6(s)

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The balanced equations for the given aluminum compounds has to be described.

Concept introduction:

  • There is a law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical equation is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.

Answer to Problem 21.51QP

The balanced equation for preparation of Al2O3 is,

4Al(s) + 3O2(g) 2Al2O3(s)

Explanation of Solution

To write the balanced equation for preparation of Al2O3

We can produce Al2O3 by reaction of aluminum with oxygen gas.

Al(s) + O2(g) Al2O3(s)

Here, the reaction is unbalanced. So we need to balance it.  To balance the reaction, calculate the number of atoms present in left side and right side.  Finally, obtained values could place it as coefficients of reactants as well as products.  The balanced equation is

4Al(s) + 3O2(g) 2Al2O3(s)

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The balanced equations for the given aluminum compounds has to be described.

Concept introduction:

  • There is a law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical equation is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.

Answer to Problem 21.51QP

The balanced equation for Al2(SO4)3 is,

2Al(s) + 3H2SO4(aq)Al2(SO4)3(aq) + 3H2(g)

Explanation of Solution

To write the balanced equation for Al2(SO4)3

We can produce Al2(SO4)3 by reaction of aluminum with sulfuric acid.

Al(s) + H2SO4(aq)Al2(SO4)3(aq) + H2(g)

Here, the reaction is unbalanced. So we need to balance it.  To balance the reaction, calculate the number of atoms present in left side and right side.  Finally, obtained values could place it as coefficients of reactants as well as products.  The balanced equation is

2Al(s) + 3H2SO4(aq)Al2(SO4)3(aq) + 3H2(g)

(d)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The balanced equations for the given aluminum compounds has to be described.

Concept introduction:

  • There is a law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
  • The concept of writing a balanced chemical equation is depends on conversion of reactants into products.
  • First write the reaction from the given information.
  • Then count the number of atoms of each element in reactants as well as products.
  • Finally obtained values could place it as coefficients of reactants as well as products.

Answer to Problem 21.51QP

The balanced equation for NH4Al(SO4)2 is ,

Al2(SO4)3(aq) + (NH4)2SO4(aq)2NH4Al(SO4)2

Explanation of Solution

To write the balanced equation for NH4Al(SO4)2

We can produce NH4Al(SO4)2 by reaction of Al2(SO4)3(aq) with ammonium sulfate and after the evaporation process.

Al2(SO4)3(aq) + (NH4)2SO4(aq)NH4Al(SO4)2(s)

Here, the reaction is unbalanced. So we need to balance it.  To balance the reaction, calculate the number of atoms present in left side and right side.  Finally, obtained values could place it as coefficients of reactants as well as products.  The balanced equation is

Al2(SO4)3(aq) + (NH4)2SO4(aq)2NH4Al(SO4)2

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Chapter 21 Solutions

CHEMISTRY 1111 LAB MANUAL >C<

Ch. 21 - In the Mond process for the purification of...Ch. 21 - Copper is purified by electrolysis (see Figure...Ch. 21 - Prob. 21.13QPCh. 21 - Prob. 21.14QPCh. 21 - Prob. 21.15QPCh. 21 - Prob. 21.16QPCh. 21 - Which of the following compounds would require...Ch. 21 - Although iron is only about two-thirds as abundant...Ch. 21 - Prob. 21.19QPCh. 21 - Prob. 21.20QPCh. 21 - Prob. 21.21QPCh. 21 - Prob. 21.22QPCh. 21 - Prob. 21.23QPCh. 21 - Why is potassium usually not prepared...Ch. 21 - Prob. 21.25QPCh. 21 - Prob. 21.26QPCh. 21 - Prob. 21.27QPCh. 21 - Prob. 21.28QPCh. 21 - Prob. 21.29QPCh. 21 - Prob. 21.30QPCh. 21 - Prob. 21.31QPCh. 21 - Prob. 21.32QPCh. 21 - Prob. 21.33QPCh. 21 - Prob. 21.34QPCh. 21 - Prob. 21.35QPCh. 21 - Prob. 21.36QPCh. 21 - Prob. 21.37QPCh. 21 - Prob. 21.38QPCh. 21 - Prob. 21.39QPCh. 21 - Prob. 21.40QPCh. 21 - Prob. 21.41QPCh. 21 - Prob. 21.42QPCh. 21 - Prob. 21.43QPCh. 21 - With the Hall process, how many hours will it take...Ch. 21 - Aluminum forms the complex ions AlCl4 and AlF63....Ch. 21 - The overall reaction for the electrolytic...Ch. 21 - Prob. 21.47QPCh. 21 - Write a balanced equation for the thermal...Ch. 21 - Prob. 21.49QPCh. 21 - The pressure of gaseous Al2Cl6 increases more...Ch. 21 - Starting with aluminum, describe with balanced...Ch. 21 - Prob. 21.52QPCh. 21 - Prob. 21.53QPCh. 21 - Prob. 21.54QPCh. 21 - Prob. 21.55QPCh. 21 - Referring to Figure 21.6, would you expect H2O and...Ch. 21 - A 0.450-g sample of steel contains manganese as an...Ch. 21 - Given that Gf (Fe2O3) = 741.0 kJ/mol and that Gf...Ch. 21 - Prob. 21.59QPCh. 21 - Prob. 21.60QPCh. 21 - Prob. 21.61QPCh. 21 - Explain each of the following statements: (a) An...Ch. 21 - Prob. 21.63QPCh. 21 - Write a balanced equation for the reaction between...Ch. 21 - Prob. 21.65QPCh. 21 - Explain why most metals have a flickering...Ch. 21 - Prob. 21.67QPCh. 21 - Prob. 21.68QPCh. 21 - The following are two reaction schemes involving...Ch. 21 - Prob. 21.70QPCh. 21 - Prob. 21.71QPCh. 21 - Prob. 21.72QPCh. 21 - After heating, a metal surface (such as that of a...Ch. 21 - Prob. 21.74QPCh. 21 - Prob. 21.75QPCh. 21 - As stated in the chapter, potassium superoxide...Ch. 21 - A sample of 10.00 g of sodium reacts with oxygen...
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