For the following exercises, consider points P ( − 1 , 3 ) , Q ( 1 , 5 ) , and R ( − 3 , 7 ) . Determine the requested vectors and express each of them a. in component form and b. by using the standard unit vectors. 13. The vector v has initial point P ( 1 , 0 ) and terminal point Q that is on the y -axis and above the initial point. Find the coordinates of terminal point Q such that the magnitude 0f the vector v is 5 .
For the following exercises, consider points P ( − 1 , 3 ) , Q ( 1 , 5 ) , and R ( − 3 , 7 ) . Determine the requested vectors and express each of them a. in component form and b. by using the standard unit vectors. 13. The vector v has initial point P ( 1 , 0 ) and terminal point Q that is on the y -axis and above the initial point. Find the coordinates of terminal point Q such that the magnitude 0f the vector v is 5 .
For the following exercises, consider points
P
(
−
1
,
3
)
,
Q
(
1
,
5
)
, and
R
(
−
3
,
7
)
. Determine the requested vectors and express each of them a. in component form and b. by using the standard unit vectors.
13. The vector v has initial point
P
(
1
,
0
)
and terminal point Q that is on the y-axis and above the initial point. Find the coordinates of terminal point Q such that the magnitude 0f the vector v is
5
.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
Explain the key points and reasons for 12.8.2 (1) and 12.8.2 (2)
Q1:
A slider in a machine moves along a fixed straight rod. Its
distance x cm along the rod is given below for various values of the time. Find the
velocity and acceleration of the slider when t = 0.3 seconds.
t(seconds)
x(cm)
0 0.1 0.2 0.3 0.4 0.5 0.6
30.13 31.62 32.87 33.64 33.95 33.81 33.24
Q2:
Using the Runge-Kutta method of fourth order, solve for y atr = 1.2,
From
dy_2xy +et
=
dx x²+xc*
Take h=0.2.
given x = 1, y = 0
Q3:Approximate the solution of the following equation
using finite difference method.
ly -(1-y=
y = x), y(1) = 2 and y(3) = −1
On the interval (1≤x≤3).(taking h=0.5).